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how can i check whether my IIS up and running or not.
My VS 2005 application work fine
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Take browser and type http://localhost and it should open the default website or IIS welcome page. If it appears, your IIS is running. BTW, why are you creating project on IIS other than using the inbuilt ASP.NET development server? For using it, choose the file system type project.
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Whn i open http://localhost im getting the error Page can not be dispalyed.What will be exactly happening
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your IIS is not running.... if you are still on developing phase, try to run ur web project in Visual Studio IDE, i'm sure it will create a virtual IIS.... somthing like "http://localhost:1234/default.aspx"....
xxx
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In my aspx form, I have an HTML table which contains rows and columns (tr and td). In one of the row, I have one label control and one text box and in another row I have another label control and a drop-downlist containing data.
My requirement is, on runtime, I need to make these rows visible and hidden based upon some conditons. I know that by giving an id to the row it can be achieved. But how it should be coded in codebehind? Any idea on this? Or is there any other better way of doing this? Can anybody please provide any help on this?
Success is the good fortune that comes from aspiration, desperation, perspiration and inspiration.
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1 - Make that table asp:table. So you can access it from code behind. Or setting runat=server will also allow you to access it from code behind.
2 - Or, put the items that needs to be hidden/visible in a panel and use the panel from code behind.
Does that help?
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Yeah. Thank you very much.
Success is the good fortune that comes from aspiration, desperation, perspiration and inspiration.
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The easiest way to make things hidden or visible is Javascript and CSS. This takes the load off compiling anything on the server and lets the users' browser take care of it. Take look at this page and see if it is something you'd like to try-
http://w3schools.com/htmldom/prop_style_visibility.asp[^]
Ranjit Viswakumar
Professional Services Specialist
HostMySite.com[^]
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Hi all,
i want to disable caching of my web page on the client side.
For this, i am adding a cache-control:no-store header to the out going response in my asp.net page.
It is working fine in IE but with a limitation in Firefox.
what i learnt is Firefox is maintaining 3 caches.
i.Memory cache
ii.disk cache.
iii.offline cache
when i sent no-store value in cache control header,i observed following things when i open the page.
1.i typed about:cache command in a new tab to see all the caches.
2.page is not added to disk cache and offline cache
3.page is added to memory cache
4.when i close the browser window,memory cache entry is now removed.
*what i need is..is there any workaround so that my page is not added to all 3 caches of firefox.
actually we can do it manually by configuring the browser but i think we cannot do this ourselves on all the client browsers who are accessing our page. and also we cannot instruct the user to close the window after he finished browsing our page.
Thanks in advance.
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Since this is browser controlled, I don't think that you can prevent it from adding to memory cache.
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Hi all,
I am using a dropdownlist in that i want to add the current year and when the new year comes i want to add the new year keeping the previous year in the dropdownlist.
How can i do it???
Thanks in advance.....
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You post a constant stream of questions that leave me feeling you are totally untrained and have absolutely no idea what you're doing. I also get the feeling you've never invested in a book, a class or even bothered to try to use google. Why are you persisting with this if you're not willing to apply yourself ?
This is so trivial. DateTime.Now tells you the year today. So, add years to your drop down from today back to what ever hard coded starting year you like, or a specific number of years if you prefer.
Christian Graus
Driven to the arms of OSX by Vista.
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Hello Everybody
I have more than 20 pages on my application
Example: default.aspx, product.aspx, order.aspx, login.aspx, resister.aspx, offer.aspx etc.
Just think, A new customer visiting my website and likes some product from my website. He added some product on ShoppingBox. After that he clicked ORDER button.
You know without logged in no one can place any order but that customer is totally new. So Customer need to resister first to logged in. Also he added some product on shopping chart.
My question is:
1. After resister and logged in how can I send back that customer to order page
2. How can I show that shopping chart which customer is added
Any solution !!
Thanks
Sarfaraj
Sarfarj Ahmed
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typically, a login page takes the redirect page on the URL. And you'd store the cart contents in a cookie or the session, if they are logged in, or not.
Christian Graus
Driven to the arms of OSX by Vista.
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Thanks for your quick reply.
It does make sense.
Sarfarj Ahmed
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But
Just think abuot CodeProject.com
I can logged in from anywhere on this site.
Is their anything I can do:
After Logged In page will be redirect to previous page
Example:
If i click login btn from product.aspx then login.aspx will come. After logged in page will be redirect to product.aspx
waiting for your reply
Thanks
Sarfaraj
Sarfarj Ahmed
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Do it now. You'll see that CP does exactly what I was talking about. It redirects to the login page and passes to the login page, the page to go back to, on the URL. So, once you login, it reads that value and navigates back to that page.
Christian Graus
Driven to the arms of OSX by Vista.
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thanks a lot
i will let you know my result
Sarfarj Ahmed
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Hi mates,
Need help again. About adding textbox value in gridview footer template, would it be possible? How will i do that? Note: The textbox value is come from the maxid of sql query. When the gridview page will load, it should have initial value one of the textbox.
<ItemTemplate>
<asp:Label ID="lblUserId" Text='<%# Eval("UserID") %>' runat="server"></asp:Label>
</ItemTemplate>
<EditItemTemplate>
<asp:Label ID="lblUserId" Text='<%# Eval("UserID") %>' runat="server"></asp:Label>
</EditItemTemplate>
<FooterTemplate>
<asp:TextBox ID="txtUserId" Text='' runat="server"></asp:TextBox>
</FooterTemplate>
C# コードMicrosoft End User
2000-2008
「「「「「「「「「「「「「「「「「「「「「「「「「「「「
The best things in life are free
」」」」」」」」」」」」」」」」」」」」」」」」」」」」
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Hi....I have two drop-down List boxes.How to update one drop-down list box based on values of other drop-down list..
E.g: Drop-down list 1 contains cars like Toyota,Hyundai etc...
If Toyota is Selected
(drop-down list 2 it must be updated with models of Toyota)
else Hyundai is selected
(drop-down list 2 must be updated with models of Hyundai)
All these data must be taken from SQL server
I am able to display the drop-down list 1 but i am not sure how to display only corresponding models of the selected Make(drop-down list1)
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Why is this asked so often when it's so trivial ?
1 - handle the changed event of the first list
2 - in the event, read the value, and use it to populate the second list
Christian Graus
Driven to the arms of OSX by Vista.
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I asked this because i am unable to pass the values.....can u provide me with an example....
I am not sure of how to pass the Make value to database inorder to get the Model.....
Give me one example
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Well, typically, there is an id stored as a value for the first list, so you end up with something like
select * from model where makeID = @makeId
as a stored proc which you call using the id from the selected column.
Christian Graus
Driven to the arms of OSX by Vista.
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This can also be done with AJAX. You have the user-facing page, an AJAX script, and a dynamic page. The user's selection passes a value over an XmlHttp request to a dynamic page, the output is returned via XmlHttp, and the contents of the user-facing page are changed via Javascript. Check out this example which has samples of all three parts-
http://w3schools.com/ajax/ajax_database.asp[^]
Good luck!
Ranjit Viswakumar
Professional Services Specialist
HostMySite.com[^]
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Sure - it's almost the canonical AJAX example. I was just trying not to confuse the guy tho.
Christian Graus
Driven to the arms of OSX by Vista.
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