Re: How to get the cut point of the line and the rect - C / C++ / MFC Discussion Boards

sultan_of_6string31-Mar-02 8:08

31-Mar-02 8:08

This is pissing me off big time. I have an edit box in a dialog and want to show a balloon tip as soon as the dialog is open:

BOOL Welcome_OnInitDialog(HWND hDlg, HWND hWndFocus, LPARAM lParam)
{
	// Display the music folder (as saved in the registry)
	SetDlgItemText(hDlg, IDC_MUSIC_FOLDER, g_musicFolder);
	
	WCHAR szTitle[] = L"Music Folder";
	WCHAR szText[] = L"Enter the path to your music folder here, or click browse..";
	EDITBALLOONTIP ebt;
	ebt.cbStruct = sizeof(ebt);
	ebt.pszTitle = szTitle;
	ebt.pszText = szText;
	ebt.ttiIcon = TTI_INFO;
	Edit_ShowBalloonTip(GetDlgItem(hDlg, IDC_MUSIC_FOLDER), &ebt);

	return TRUE;
}

It is not working. Yet, when the user clicks the OK button. My WM_COMMAND hander has no problem displaying balloon tip:

void Welcome_OnCommand(HWND hDlg, int nId, HWND hWndCtrl, UINT uCodeNotify)
{
	HWND hMusicFolder = GetDlgItem(hDlg, IDC_MUSIC_FOLDER);

	if (nId == IDOK)
	{
		g_musicFolder.GetFromHWnd(hMusicFolder);
		DWORD dwFileAttributes = GetFileAttributes(g_musicFolder);
		if (dwFileAttributes == 0xffffffff || dwFileAttributes &
			FILE_ATTRIBUTE_DIRECTORY != FILE_ATTRIBUTE_DIRECTORY)
		{
			// Select the text in the text box.
			SendMessage(hMusicFolder, EM_SETSEL, 0, -1);
			// Display a balloon tip.
			WCHAR szTitle[] = L"Invalid folder name";
			WCHAR szText[] = L"Please confirm that this is the path to your music folder.";
			EDITBALLOONTIP ebt;
			ebt.cbStruct = sizeof(ebt);
			ebt.pszTitle = szTitle;
			ebt.pszText = szText;
			ebt.ttiIcon = TTI_WARNING;
			Edit_ShowBalloonTip(hMusicFolder, &ebt);
			
			return;
		}
.
.
.
}

What's going on? Any fixes?

Thanks

Re: Edit box balloon tips in WinXP

Ravi Bhavnani31-Mar-02 9:11

Ravi Bhavnani

31-Mar-02 9:11

The dialog may not have finished initializing until OnInitDialog(). Try setting up the balloon tip within a handler for a fake command (I use IDC_INIT_GUI). Post the command (using PostMessage (WM_COMMAND, IDC_INIT_GUI)) from within OnInitDialog() to ensure that the handler will be executed after the dialog has initialized itself.

/ravi

"There is always one more bug..."
http://www.ravib.com
ravib@ravib.com

Test

31-Mar-02 3:18

Re: Test

Jon Newman31-Mar-02 3:52

Jon Newman

31-Mar-02 3:52

Mood swing problems?

I'm not late, I'm just not as early as I could have been.

Re: Test

Nish Nishant31-Mar-02 5:13

Nish Nishant

31-Mar-02 5:13

Jonny Newman wrote:
Mood swing problems?

Nope, I think he's easter-drunk!

Nish

Has anyone seen my sig?

Re: Test

Michael P Butler31-Mar-02 23:12

Michael P Butler

31-Mar-02 23:12

Nish [BusterBoy] wrote:
Nope, I think he's easter-drunk!

Yep, too many chocolate eggs have the same effect on me Big Grin | :-D

Michael

How to get the cut point of the line and the rect

Feng Qin31-Mar-02 3:03

Feng Qin

31-Mar-02 3:03

CRect rect( 10, 10, 100, 100 );
CPoint ptBegin(20,50), ptEnd(200,200);

How to get the cut point of the rect and the line???

I'm amumu, and you?

Re: How to get the cut point of the line and the rect

Nish Nishant31-Mar-02 5:11

Nish Nishant

31-Mar-02 5:11

You'll have to manually figure out the various points and use CRect::PtInRect on each of them

Nish

Has anyone seen my sig?

Re: How to get the cut point of the line and the rect

Feng Qin31-Mar-02 14:50

Feng Qin

31-Mar-02 14:50

I don't think it is a good solution Smile | :)

I'm amumu, and you?

Re: How to get the cut point of the line and the rect

Nish Nishant31-Mar-02 16:10

Nish Nishant

31-Mar-02 16:10

qf0421 wrote:
don't think it is a good solution

Well, seems to me, that, that's the only solution, unless someone has wrapped it into a class or function

Nish

Make MSDN universal, FREE!

Re: How to get the cut point of the line and the rect

PJ Arends31-Mar-02 15:08

PJ Arends

31-Mar-02 15:08

Take a look at the LineDDA() function.

---
CPUA 0x5041

Sonork 100.11743 Chicken Little

It may be that your sole purpose in life is simply to serve as a warning to others.

Re: How to get the cut point of the line and the rect

Feng Qin31-Mar-02 16:02

Feng Qin

31-Mar-02 16:02

Where can get it?

I'm amumu, and you?

Re: How to get the cut point of the line and the rect

Christian Graus31-Mar-02 16:17

Christian Graus

31-Mar-02 16:17

qf0421 wrote:
Where can get it?

I've got one lying around here somewhere.....

It's part of GDI and has been since Windows 3.1. Don't you have MSDN ? Or the Internet ? msdn.microsoft.com is your friend.

Christian

The tragedy of cyberspace - that so much can travel so far, and yet mean so little.

"I'm somewhat suspicious of STL though. My (test,experimental) program worked first time. Whats that all about??!?!
- Jon Hulatt, 22/3/2002

Re: How to get the cut point of the line and the rect

Feng Qin31-Mar-02 17:13

Feng Qin

31-Mar-02 17:13

I can't find it in MSDN 2002.

I'm amumu, and you?

Re: How to get the cut point of the line and the rect

Christian Graus31-Mar-02 18:48

Christian Graus

31-Mar-02 18:48

I see I need to start from the beginning. When the text is a different colour, chances are it's a hyperlink. To tell for sure, move your mouse over it and look in your status bar for a URL. Then click on the URL I provided for you in my last post, and you'll see the appropriate article online. It is most certainly also in the latest MSDN, and every MSDN since 1995, assuming they had them back then.

Christian

The tragedy of cyberspace - that so much can travel so far, and yet mean so little.

"I'm somewhat suspicious of STL though. My (test,experimental) program worked first time. Whats that all about??!?!
- Jon Hulatt, 22/3/2002

Re: How to get the cut point of the line and the rect

Feng Qin31-Mar-02 20:33

Feng Qin

31-Mar-02 20:33

Thank you, I got it Smile | :)

I'm amumu, and you?

Re: How to get the cut point of the line and the rect

Michael A. Barnhart31-Mar-02 15:42

Michael A. Barnhart

31-Mar-02 15:42

The General Equation is:
// line one
A = pt2.y - pt1.y;
B = pt1.x - pt2.x;
C = pt1.x*A + B*pt1.y;
// line two
D = pt4.y - pt3.y;
E = pt3.x - pt4.x;
F = pt3.x*D + E*pt3.y;
DET = A*E - B*D;

if(fabs(DET) < DTSQ) // Paralell lines skip
{
// Paralell
}
else
{
// intersecting point
x = (E*C-B*F)/DET;
y = (A*F-D*C)/DET;
}

// DTSQ is deterimined by the accuracy you have (i.e. what is considered to be zero.)
example DTSQ=0.00001f

//Now is this point on the segement or not for each side of the rect you have. It may miss be on two sides or a corner.

Good ideas are not adopted automatically.
They must be driven into practice with courageous patients. -Admiral Rickover. ...

Re: How to get the cut point of the line and the rect

PJ Arends1-Apr-02 5:37

PJ Arends

1-Apr-02 5:37

Thanks Michael, this is an excellent little piece of code. I knew there had to be an easy way of doing this and you nailed it Big Grin | :-D

I am going to add this code to my file of assorted functions.

Someone, with more knowledge in this area than me, should write an article containing a bunch of geometric functions like this one (or does one already exist somewhere?)

---
CPUA 0x5041

Sonork 100.11743 Chicken Little

It may be that your sole purpose in life is simply to serve as a warning to others.

Re: How to get the cut point of the line and the rect

Michael A. Barnhart1-Apr-02 12:04

Michael A. Barnhart

1-Apr-02 12:04

First you are welcome Smile | :)

I thought Chris was going to write something, but I am not sure where it would be. I have a number of functions coded through the years. Mostly to support Finite Element Editors. That is part of the issue on what area to write for. I am sure if you did a search on google for the right set of terms you will find sources.

Good ideas are not adopted automatically.
They must be driven into practice with courageous patients. -Admiral Rickover. ...

LoadBitmap from resource using VS.NET?

31-Mar-02 1:14

I recently installed Visual Studio .NET and at times I feel a bit lost in the new development enviroment. For some reason I can't figure out I can't load a bitmap from a resource file. Obviously I'm not doing everything that I should. I'm doing a Win32 application, and not using MFC.

HBITMAP hBitmap; // global

// inside the message pump (WM_CREATE)
hBitmap = LoadBitmap(hThisInstance, "MyBitmap");

When I run the app I get the error code saying ERROR_RESOURCE_NAME_NOT_FOUND (the specified resource name cannot be found in the image file).

In the project I add a new bitmap resource, change the filename resulting in that Visual Studio load the bitmap into the Bitmap Editor. Visual Studio also gives the bitmap resource an ID, and I change this ID into a string called "MyBitmap". Using the Visual Studio resource identifier, after converting the ID using MAKEINTRESOURCE, results in the same error. Everything worked fine when using VC++ 6, so I'm getting a bit frustrated here. Help me please! Thanks a million!

ListBox on CEditView

31-Mar-02 1:15

can anyone tell me plz how to make a listbox appear on a CEditView plz. It's very important to me to make a ListBox appear at runtime.

Thanks in advance
Bernard Racoute
Mail @ bracoute@hotmail.com & Bracoute@hotpop.com

Bracoute

heh ... progress but...

l a u r e n31-Mar-02 1:05

l a u r e n

31-Mar-02 1:05

i got the wabapi.h thing sorted out (i think) but now am hitting other problems

what i'm trying to do is use the windows address book in my app and apparently i have to jump thru several hoops wearing a pink tutu to do it (sheesh cant they make this stuff easier!) ... anyways i got this code compiling and working up to the indicated line ... at which point i get an access violation ... *sigh*

any clues would help a lot Smile | :)

---------------------------------------

HRESULT CL4m3Dlg::InitWAB (LPWABOBJECT *lppWABObject,LPADRBOOK *lppAdrBook)
{
HRESULT hr = E_FAIL;
CString csKey;
CString csDllPath;
CString csDefault;
WAB_PARAM wbp;

wbp.cbSize = sizeof(WAB_PARAM);
wbp.hwnd = NULL;
wbp.szFileName = NULL;
wbp.ulFlags = 0;

CRegistry cr;
cr.SetRootKey(HKEY_LOCAL_MACHINE);
cr.SetKey(WAB_DLL_PATH_KEY,false);
csDllPath = cr.ReadString(csDllPath,csDefault);

// hinstWAB = LoadLibrary_WABDll(); <--- dunno what this is
hinstWAB = LoadLibrary(csDllPath);

if (hinstWAB){
lpfnWABOpen = (LPWABOPEN) GetProcAddress(hinstWAB, "WABOpen");
if (lpfnWABOpen)

----------> access violation happens on this line
hr = lpfnWABOpen (lppAdrBook,lppWABObject,&wbp, 0);
}

return hr;
}

-------------------------------------------------

---
"all's fair in love and war but in love there is no geneva convention"

Re: heh ... progress but...

SeNs31-Mar-02 7:28

SeNs

31-Mar-02 7:28

Hmm... have you got your program incrementing the reference
count for the WAB dll in the registry ok?

Assuming you have, I think it is something to do with
the Loadlibrary statement... I know the usual syntax is:

LoadLibrary(file name string);

Have you checked that csDllPath is being loaded with the
correct path to the dll before calling LoadLibrary?

If that's ok then....

What happens when you use:

hinstWAB = LoadLibrary_WABDll();

Or:

hinstWAB = LoadLibrary_WABDll(csDllPath);

Instead of:

hinstWAB = LoadLibrary(csDllPath);

Re: heh ... progress but...

l a u r e n31-Mar-02 9:35

l a u r e n

31-Mar-02 9:35

loadlibrary_wabdll() isnt recognized by the compiler thats why i commented it out and did a normal loadlib call

:/

---
"all's fair in love and war but in love there is no geneva convention"

Re: heh ... progress but...

1-Apr-02 9:42

Have you tried the sample at <href url=""> http://msdn.microsoft.com/downloads/samples/internet/default.asp?url=/downloads/samples/Internet/messaging/wabtool/Default.asp

I ran it and the WABOpen call didn't fail but had no entries for the address book.

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