Password Generator

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5.00/5 (1 vote)

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Hi I made password generator

VB

Public Function RndWord(ByVal WordLength As Integer) As String
       Dim TempWord As String
       Dim loopvar As Integer
       For loopvar = 1 To WordLength
           TempWord = TempWord & Mid("abcdefgABCDEFG", Int(Rnd() * 14) + 1, 1)
       Next loopvar
       RndWord = TempWord
   End Function

and every time I use first use it generates the same first 3 passwords every time! how can I fix this???

Posted 20-May-10 10:43am

Code Master38

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3 solutions

Solution 1

Why are you calling Rnd() in a .NET class ? Why not use the .NET methods ? I have no idea how Rnd() is seeded, but your issue is that the seed is the same. There's no such thing as random numbers on a PC.

Posted 20-May-10 10:46am

Christian Graus

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Code Master38 19-Jun-10 0:54am

Reason for my vote of 2
you don't know what your talking about

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**Dalek Dave** · Accepted Answer · 2010-05-20T10:56:00

Before using Rnd(), use Randomize().

In VB, Rnd() uses a maths equation to produce the next 'random' number.

But, because the actual operation is known you can predict the next value.

However given an arbitray start value the numbers have good distribution - these are 'pseudo-random' numbers.

To keep Rnd() from startng at the same number (and hence giving the same sequence of numbers every time), Randomize() should be called to use the machine clock to set the initial value (called a seed).

In the .Net use System.Random instead if you can.

CPallini · Accepted Answer · 2010-05-20T11:36:00

What about documentation [^]:

For any given initial seed, the same number sequence is generated because each successive call to the Rnd function uses the previous number as a seed for the next number in the sequence.
Before calling Rnd, use the Randomize statement without an argument to initialize the random-number generator with a seed based on the system timer.

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Password Generator

3 solutions

Solution 2

Solution 3

Solution 1

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