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i have hide a div using jquery like $("#div1").hide(); in $(document).ready{};
when mypage loads this div shows once then hide.
One person's data is another person's program.
--J.Walia
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I guess the code takes a second to run. If you want it hidden on load, hide it in the code behind.
Christian Graus
Driven to the arms of OSX by Vista.
Read my blog to find out how I've worked around bugs in Microsoft tools and frameworks.
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hi,
if u want the div to be hidden on page load, good thing will be to add
style="display:none;" to the div.
e.g.,
<div id='div1' style="display:none;">your content here.</>
and later u can show it by using $('#div1').show();
Regards.
Atif Ali Bhatti
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thanks for reply
i will try this
One person's data is another person's program.
--J.Walia
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I completed my personal web page. and I hosted that in a free webhosting site. Now my Problem is
1. How to show my web page content topmost in Search Engine like Google, Yahoo, Msn etc...
2. I m searching my website name then also i can't search in any above search engine.
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non-bugging Errors wrote:
1. How to show my web page content topmost in Search Engine like Google, Yahoo, Msn etc...
Pay them. Modern search engines are not as easy to fool, and if there is a way, you'd use it today and someone else would use it to be above you tomorrow.
Christian Graus
Driven to the arms of OSX by Vista.
Read my blog to find out how I've worked around bugs in Microsoft tools and frameworks.
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im using repeater control retrieving a table with four rows from sql.
one column is to active or inactive the users, when i click on linkbutton to active or inactive single user all users are activated or deactivated.
following is the code....
in sql table i had column active with values '1'(active) and '0'(inactive)
help me what im missing or any sample code....
in repeater item command
if(commandname=="inactive")
foreach (DataRow row in dt.Rows)
{
if (row["Active"].ToString() == "0")
{
update tb_staff set Active=1 where Active=0
}
if (row["InActive"].ToString() == "1")
{
update tb_staff set Active=0 where Active=1
}
}
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Hi,
You have to update the table with 'update tb_staff set Active=0 where ID=command argument'. Please send the id of the corresponding record to the link button as commmand argument.
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table with columns id, username, pwd, active, email
update table tb_staff set active=1 where active=0
how should i give command argument as link id in query..
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How did you bind the repeater control.Have you used #Eval("id") or databinde r.use the same in the linkbutton.
<asp:linkbutton id="lnkbtnactive" text="Active" commandargument='<%#Eval("id")%>' commandname="xxx" runat="server">
at the codebehind ,
Use item command method to get the commandargument(e.commandargument).you can now get the id.Now you can update the table.Why you have written the query in the page itself.Please prefer to write stored procedures.
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now its completely not workin
if (e.CommandName == "act" && e.CommandArgument=="StaffId")
{
DataSet ds = new DataSet();
DataTable dt = new DataTable();
OleDbDataAdapter ad = new OleDbDataAdapter(cm);
ad.Fill(ds, "tb_staff");
dt = ds.Tables["tb_staff"];
foreach (DataRow row in dt.Rows)
{
if (row["Active"].ToString() == "1")
{
SqlCommand cmd = new SqlCommand("update_staff_active", cnn);
cmd.CommandType = CommandType.StoredProcedure;
cmd.Parameters.Add("@StaffId", SqlDbType.Char).Value = "StaffId";
cmd.Parameters.Add("@Active", SqlDbType.Char).Value = "active";
SqlCommand cmd = new SqlCommand("update_staff_active", cnn);
cmd.CommandType = CommandType.StoredProcedure;
cmd.Parameters.Add("@StaffId", SqlDbType.Char).Value = "TextBox1.Text";
cmd.Parameters.Add("@Active", SqlDbType.Char).Value = "TextBox2.Text";
cnn.Open();
cmd.ExecuteNonQuery();
cnn.Close();
}
}
}
procedure
create PROCEDURE [dbo].[update_staff_active]
(
@StaffId int ,
@Active [char]
)
AS
update tb_staff
set
Active=@Active
where
StaffId=@StaffId
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hi,
you will have to find the row no of that row and then use query
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Hi all,
I want to convert my asp.net application to run on trust level "Medium".
How can i configure my application to run in "Medium" trust level.
Which changes in need to do in code? I have made changes trust level
medium in my web.config file. Which changes in need to do?
Thanks
Rahul
People Laugh on me Because i am Different but i Laugh on them
Because they all are same.
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Wow, look what I found[^] !!!
Christian Graus
Driven to the arms of OSX by Vista.
Read my blog to find out how I've worked around bugs in Microsoft tools and frameworks.
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Hi
I have already gone through that link and make the changes in web.config file as i mentioned in thread. Do i need to change any other changes in code for this one?
Thanks
Rahul
People Laugh on me Because i am Different but i Laugh on them
Because they all are same.
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Yes, Microsoft wrote an article on what you need to do, but they left stuff out, just to make it hard. What makes you think that what Microsoft told you to do in that article is not enough ? Do you have a specific issue ?
Christian Graus
Driven to the arms of OSX by Vista.
Read my blog to find out how I've worked around bugs in Microsoft tools and frameworks.
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In my application i had headings in between the grid rows when i export the grid to excel the headings were not displayed i used the code like this
Response.Clear();
Response.Charset = "";
Response.ContentType = "application/vnd.ms-excel";
System.IO.StringWriter stringWrite = new System.IO.StringWriter();
System.Web.UI.HtmlTextWriter htmlWrite = new System.Web.UI.HtmlTextWriter(stringWrite);
htmlWrite.WriteLine("<b><font size=5 color=red>" + Heading.ToString() + "</font></b> <b><font size=4 color=blue>TDP IT-Department</font></b>");
//System.Web.UI.WebControls.DataGrid dg = new System.Web.UI.WebControls.DataGrid();
//dg.DataSource = dv.Table;
//dg.DataBind();
gv.RenderControl(htmlWrite);
Response.Write(stringWrite.ToString());
Response.End();
help me out to solve this
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Not shown at all, or just not styled ?
Christian Graus
Driven to the arms of OSX by Vista.
Read my blog to find out how I've worked around bugs in Microsoft tools and frameworks.
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not shown at all an empty row is being displayed
i used the code like this to add a row to grid
DataTable dt1 = dv1.ToTable(true, "nDepartmentID", "sDepartmentName");
int i = 2;
// Session["i"] = ds.Tables[0].DefaultView;
for (int m = 0; m <= dt1.Rows.Count - 1; m++)// foreach (DataRow dr in dt1.Rows)
{
DataTable dt = dv1.ToTable("dt", false);
object objCount = dt.Compute("count(nDepartmentID)", "nDepartmentID in (" + int.Parse(dt1.Rows[m]["nDepartmentID"].ToString()) + ")");
if (dt.Rows.Count > 0)
{
GridViewRow gvRow = new GridViewRow(i, 0, DataControlRowType.DataRow, DataControlRowState.Insert);
TableCell tblCell = new TableCell();
//Add Summary Row
tblCell.Text = dt1.Rows[m]["sDepartmentName"].ToString();
tblCell.ColumnSpan = 6;
tblCell.BorderWidth = 2;
tblCell.HorizontalAlign = HorizontalAlign.Left;
tblCell.ForeColor = System.Drawing.Color.Red;
tblCell.Font.Bold = true;
tblCell.Font.Size = 12;
gvRow.Cells.Add(tblCell);
gridView.Controls[0].Controls.AddAt(i, gvRow);
i = i + int.Parse(objCount.ToString()) + 1;
}
}
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use this code.
Dim attachment As String = "attachment; filename=MyFile.xls"
Response.ClearContent()
Response.AddHeader("content-disposition", attachment)
Response.ContentType = "application/ms-excel"
Dim sw As New StringWriter()
Dim htw As New HtmlTextWriter(sw)
Dim frm As New HtmlForm()
GridViewEmployeeRegistrationDetails.Parent.Controls.Add(frm)
frm.Attributes("runat") = "server"
frm.Controls.Add(GridViewEmployeeRegistrationDetails)
frm.RenderControl(htw)
Response.Write(sw.ToString())
Response.End()
Thanks and Regards
Sujit Kr. Mandal
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Dear all, Thank you. I have made it.
modified on Thursday, October 8, 2009 3:37 AM
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Yonathan1111 wrote: Forum: ASP.NET
Subject: TableInsideTableRow [modified]
Sender: Yonathan1111
Date: Thursday, October 8, 2009 1:21 PM
Dear all, Thank you. I have made it.
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what u hv made??????????
Thanks and Regards
Sujit Kr. Mandal
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Hello Sujit Kr.Mandal. I have made a Table that contains for another table inside one of its row. This can help to have a good layout of controls on the displayable page. The page is done with ASP.Net.
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