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where is the dropdown SelectedIndexChanged event... write your code in that event 
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thanmks sir,
its workin now... 
Regard's
parikshit
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Just do one thing............open ur internet explorer browser and type www.google.co.in and then find out the solution...........simple
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The thing is if DropDown Autopostback = true, the page will be posted back to the server. It will generate Page_Load event and the respective DropDown.SelectedIndexChanged event.
As I can see you have populated Dropdown inside the !IsPostBack statement, I think the post back event will not run any line from Page_Load (Which I think is perfect).
The only reason that may come, if you have written something inside dropdown.selectedIndexChanged event which changes the original selection with the initial value.
Please check if PopulateDDL1 is called from elsewhere or not.
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Hi,
There is a web form and after user select certain option - the page reloads.
There are like 3-4 such options where page reloads according to the user selection but everytime after page reloads - page focus moves to the top. But i want that to the same loaction where user select that option.
How can i achieve this page focus bit.
Thank You
Andyyy
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You have to use Ajax. in your Visual Studio toolbox there is a Ajax Section and the is an Update panel. Please Google Update panel.
Vuyiswa Maseko,
Few companies that installed computers to reduce the employment of clerks have realized their expectations.... They now need more and more expensive clerks even though they call them "Developers" or "Programmers."
C#/VB.NET/ASP.NET/SQL7/2000/2005/2008
http://www.vuyiswamaseko.somee.com
vuyiswa@its.co.za
http://www.itsabacus.co.za/itsabacus/
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AndyInUK wrote: There is a web form and after user select certain option - the page reloads
after finishing that option set the focus to the desired location by using focus() method.
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try this MaintainScrollPositionOnPostback="true" in page directive
Coding C#
www.excitetemplate.com
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Hi to all,
I am working on asp.net web application. In this there is a module "video gallery". It should be database driven. I did this by using a flash player. Everything was working fine in the development enviroment ie on localhost. When I uploaded it to the server, the flash player is not visible on the page. Then I checked the "view source" and the control is something like this:
<br />
<div id="FlashVideo1"><br />
<input id='FlashVideo1_objectHasPlayer' name='FlashVideo1$objectHasPlayer' type='hidden' value='false' /><script type="text/javascript"><br />
activex_direct_inject('ŷŻǂƸƠƏƐƓŽŬƛŶſŮźƁƝŽŬżſŬƹƻƨƺƹƷǁŧǀǁǂǀǁǂǀǁǂǀǁǂǀǁŬſůǂŷŽǂƣǁƻƚŵƁŭŹƌŷŽŽűưƃűſŸŻžŮƘƀůƐŵƁŧżŰƹƦǂǀǁǂǀǁǂǀǁǂǀǁǂŷŻǂƸŽųŽŬŵŻųŮƲźŽŬƜŶŻŴŽŲŭƠŧƘžǀƻƼǀŽųŽŬŵŻųŮƲźŽŬƜŶŻŴŽŲŭƠŧƘžƸŸžƷƸǂǀǁǂǀǁǂǀǁǂǀǁǂťǁǂǀǁǂǀǁǂǀǁǂǀǁǂǀǁǂżŲſūŴŽŲŭƴŹżŮƛŵŽųżŴŬƟũƗŽƺŷŽƹƲūƁŴŬŽǀƤǂƹŭŰūżƻƥǁǂǀǁǂǀǁǂǀǁǂǀǁťƟžŮŷūŽƈƂƞŷůŽŽŭƃƛŴƀŻŽƺƹƛŶſŮźƊŸžŻŲƱƹƵǀÖòĥĕĝĘēĤØĞęòÙøĞĐĪğĊĝĘĖĠâĕĜĢĔĦě×ÐįĞęĩĚïÙäççÛÔĜĖĚĘĞĪóÚçãà×ØĩĮĥėïÙĐħħĠĝėĒĥĚĥĤåīàĦĘğěĠĬĖĨėßĕģĘħĜÛÑĕĒĪėóÚěħĤĠòääĬĩĩàēĜİħĝâĔĠĞäėīâĊĘĒĂĝĨĤĪĤĕėÝĘįĘóĘî÷ěĦĥċùċāöęèāÿûõĞĥãøĝĎëĭĖēăĐČéĊäàĔöċħģăýĤýĠøúćĕøěåéĥ÷ģćėĉđħıëĜýĆèĖğāİīĬĈĄīĀİĂāĭýěñåħûæûâīĨąĪĎćþĞäĔėĀĨāăčĘĩąąæÛĖğĢíģôíççìåèáîîçäèéçâíååÜÒðÒëħĘĦĕġÑğĒģěóÚĠĢĦęĝÜÕīēĞħĔôÞĜĨĨġëàåĭĭĪáėĕĩīĞãĘġğàĐĬæċęĖăĖĤĥīĨĖĘáđĨĜôęòøĜĢĞČýČĂúĚáýĀüùğĦçñĖĒìĮĚĔĄČąêĎåáĘ÷ĄģĤĄāĥþĤñóċĖùğæêġðĤċĘĊĕĨĪçĝþĊéėģúĩįĭĉĈĬāĬûĂıþĜõæĠ÷çüæĬĩĉģćċÿğèĕĘüġĂćĎęĭĆþâÜėģģîħíæëèíééâêçèèéêëãæáæÝÖâñÓìĠęħĖĢÒĠēĜĜôÛĚĠĒĤęĬėĨĦÚÓĦđĤĪĚòÙēĥğĥĜĨĚĠĒĤęĕęĥġħĥğĜāùòûĞēĥėčĠĘęģâ×ĒģĦñôğğğħþĪġġąĕĤĔĜĥñĨĦĦĖ×ėģĦîôĨĤğĈġĖĮïĦĤĤĜÝĕġĤìóĦĜĜěĥćĜĝĕõêÛĖğĢíøĤĘěęĉăýîÜėģģîĆēđĤĚĂĤĖėïĢīĩęĨėęĥĠĜğĪÙĔĠĠëċĝĤĬõġĠģĩĦĠĄĕğĖĝóĪĨĨĘÙđĝĨðĈĠěĠćāăôÙæĚĈĖēĈěĩĢĨĥēĕæĖĭę×åĘēÜêĘúĞġĠĆüĎĄùĜãüúþøġĨæóĘĉîİęĖĆċćäčçãėùĆĢĞĆĀħĀģóõĂĘûĞèìĠòĞĊĚČĔĪĬæėĀĉëĬĜđúðĖĜõĥħĄĕûĎèĦĦČæěāĨĝêĜëēĦĥçäċæëĥĆâīøĮëæĢáÕêëĩÚåĖèâêïèëäééâçëìêåèààÞĖĢĥíĈěēĜĦĉĆĀîęĥĪĦÛæĔØâĖÝçěĬĩĩàēĜİħĝâĔĠĞäėīØåęĆęĜĚĤĨ×äĘĢğĠĪĕâėĝħÜėģģîĉğĜĭĢĚòãââÕĘĤĤïÛÑàïÖòĦĔĥĔĝÐĦĖĢĚïÙģĤĘģĝĨĭØÑħėĢīĘðÚĘęğĝÜÕáðÒëħĘĦĕġÑğĒģěóÚĦĖđĜĝÜÕīēĞħĔôÞĢģħĔĒĝěÝÖâñÓìĠęħĖĢÒĠēĜĜôÛĕĠĝĠĨĩęĨĜģħđēěĚĨĨÙÒĨĐģĬęñÛĒĝĨėįĩÚÓâîÐôĥĖħēğÒĝĘĤęñÛĨĞĠĚěÝÓĩĔĜĥĝòÜĤĢēģĤĜÞÔãòíġĒĨėģÓġĔĝĕõÜĢĚĠħÙÏĭĘĠĩęîØĥĨīěÚÓâîìĨĖħĖğÒĠĐĤĜñÛĕĝĝĠĭüīğğĆēĢĝĚģÜÒĨēěĬĜñÛĨģĦĖÝÖåñïâğĒĢĚĘĩðîēÏğĩęĚñØęĥĪĦðââĪħħæĖĨĥĠėĦĕģĘħĜĪĚĕĖĥäęĢĠâđģĨģĚĩĘĞēĢğĭĝĘęĠĐāīĨęěĔĦĕďĄĞĘĚĠĥėÝĘĪĤĬÛÑĥĚĪĢěðÚôăĀĆĚĩûĞēĥėčĠĘęģÑąģğėĢÚÓĦĤĩĤĚòÜĨěĥĘęĠĠĝĨĪëħğĩğĕğĘëğĮĚħěĞġĩé×ĭĝħĝēĝĖñÖĦĢĦĜĤęħģïħėĞēģĠĭęïÔīÞĚĤĚěīíäâçêðÕīěĥěđĠģĝĨĭëħĚĩğĘğĘîÐĔġĨĥġēīìđģĦėğïØïÑòĘĨÓâñìęĥĜÕĨĤĕïÖæĎęĖĆĖĤĠīĨęĘáĔĨĔ÷ęòûĜĢġĄýďĂúĝáýûüùĢĦçôĖĊïĮĚėĄČĈâĎèáĘúĄģğĄāĨþĤôóăęùğéêġóĜċěĊĕīĪçĘþĊìäÿêôñĥĘĞĭâğöĢğéĢĩíôĨĀĊüĠĝĢèĩĕĚĖöüĤĕĀáĘĉĪćĬĦĊãāíĨĥ÷öďåĐìĥîĖę÷ħĦÿåĤþåğīĦĞíĈčĔĥħåêĆùāğĚôøéÚĨñçääîêíãëëááíëìççââÖ×ęģĦĘĖģîÝæÝÓâñìßęóƿƹƥŭŰŧŦūŷųžűŪƴƚŵƁŭŹƌŷŽŽűưƃźŵƁŭŹǂƣǁơƍƑƔŻŭƜŴƀůŸƳƜŷųžƚŵƁŭŹƕűūŹŻƹƻƚŵƁŭŹƌŷŽŽűưƻƷƦǂƟƎƒƒżŮƓżžŷƀƴƚŵƁŭŹƌŷŽŽűƒƀŶżſŬŮƇƹƛŶſŮźƊŸžŻŲƱƹƄǂƣǁŴŻŪǂƟƎƒƒżŮƓżžŷƀƴƚŵƁŭŹƌŷŽŽűƑŰűŭųƸƺƜŴƀůŸƋŹżżųƯƺƹƥǁŹźǁƺƿƠƏƐƓŽŬƛŶſŮźƁƝŽŬżſŬƹƻƧƺƹƷǁŧǀǁǂǀǁǂǀǁǂǀǁǂǀǁǂǀǁǂǀǁǂǀǁǂǀǁǂǀǁǂǀǁǂǀǁǂǀƠƏƐƓŽŬƛŶſŮźƲƛŹŲŽƜŴƀůŸƔųŪŸŽƸƺƜŴƀůŸƋŹżżųƯƺƹƲŽƁŬƀƥƹƲƋŻſƐŻŮųūůſŻƳƁŨŽƣżƤƜŶűųƋƛƊƒƛŹưƕƘƚƞŶŭƭơźƇƫŧżƀƎƇƌƭƊƱƳŽƜƍůŴƒƖŰƕŰơƝƎƁƜŷƮƨŲơųƍžƊƀūŧƫŻƘƍƬżűƘŧŪŪƌƎŨƑŧƖƕŧƘŸƠƭűƛƱƞžũƛſƁƆƂŵƕŽƕƖſŴŶƂƀƜưƘƛưƼŬƤƬƭƮƪƬƪƲƨƩƱƯƬƬƩƯƭưƱƻƥǁǂǀǁǂǀǁǂǀǁǂǀǁǂǀǁǂǀǁǂǀǁǂǀǁǂǀǁǂǀǁǂǀǁǂǀǁơƍƑƔŻŭƜŴƀůŸƳƜŷųžƚŵƁŭŹƕűūŹŻƹƻƚŵƁŭŹƌŷŽŽűưƻƷƳſŸŸŶżƓųżżůƅưƅƲƀŮŬůŹžŬŮŻŮƇưƄƴŪƀŶūżƥƹƲƋŻſƐŻŮųūůſŻƳƁŨŽƣżƤƜŶűųƋƛƊƒƛŹưƕƘƚƞŶŭƭơźƇƫŧżƀƎƇƌƭƊƱƳŽƜƍůŴƒƖŰƕŰơƝƎƁƜŷƮƨŲơųƍžƊƀūŧƫŻƘƍƬżűƘŧŪŪƌƎŨƑŧƖƕŧƘŸƠƭűƛƱƞžũƛſƁƆƂŵƕŽƕƖſŴŶƂƀƜưƘƛưƼŬƤƬƭƮƪƬƪƲƨƩƱƯƬƬƩƯƭưƱƻƥǁǂǀǁǂǀǁǂǀǁǂǀǁǂǀǁǂǀǁǂǀǁǂǀǁǂǀǁǂǀǁǂǀǁǂǀǁžűžŭųżŴŬƳŻŻŭƝŴżŵŻųŮƞŨƙżƹƻƚŵƁŭŹƌŷŽŽűưƻƷƳŹŲųŽŮƙƎƓƕǂƣǁžűžŭųżŴŬƳŻŻŭƝŴżŵŻųŮƞŨƙżƹƻƚŵƁŭŹƌŷŽŽűưƻƷƳŹŲųŽŮƙƎƓƕƧǀǁǂǀǁǂǀǁǂǀǁǂǀǁǂǀǁǂǀǁǂǀǁǂǀǁǂǀǁǂǀǁǂǀŤťŽƀŮŽŹƺŻƸŧţŤŽŴŮŽǀŦǂǀǁǂǀǁǂǀǁǂǀǁǂǀūƁŮǁŹżǁƥǀƺƜŴƀůŸƋŹżżųƯƂųžŷŽŽŭƚſŮƒŴƀũŻůƻƥǁǂǀǁǂǀǁǂǀǁǂǀǁŹźǁƺżŲſūŴŽŲŭƴŹżŮƛŵŽųżŴŬƟũƗŽǂƺƻǂżŲſūŴŽŲŭƴŹżŮƛŵŽųżŴŬƟũƗŽƺŷŽƹƷǁǂǀǁǂǀǁǂǀǁǂǀǁŧǀǁǂǀǁǂǀǁǂǀǁǂǀǁǂǀǁžűžŭųżŴŬƳŻŻŭƝŴżŵŻųŮƞŨƙżƹŹżƸƴŪƀŶūżǂƣǁƻźƀŶŭżƻƥǁǂǀǁǂǀǁǂǀǁǂǀǁťǀŤ');</script><br />
</div><br />
<br />
Is it correct? Please assist me....
cheers
sneha
cheers,
sneha
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use embed will solve your problem, i think
<embed src="~/VISUALISE.SWF" style="HEIGHT: 331px; LEFT: 83px; TOP: 171px; WIDTH: 538px" />
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Hi Padmanabhan,
Thanks for replying. Actually the gallery is database driven. I am using hyperlinks in datalist control. When user will click any link then the corresponding video will be played in the player.
padmanabhan N wrote: <embed src="~/VISUALISE.SWF" style="HEIGHT: 331px; LEFT: 83px; TOP: 171px; WIDTH: 538px" />
will this work in my scenerio?
cheers,
sneha
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sneha Choudhary wrote: <embed src="~/VISUALISE.SWF" style="HEIGHT: 331px; LEFT: 83px; TOP: 171px; WIDTH: 538px" />
will this work in my scenerio?
Yes - It should work for you, just change the source on each hyperlink click.
Coding C#
www.excitetemplate.com
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i have a dropdown list i it has a different datafield(CouponName) and datavalue(CouponTypeID). i want that when i select a datafield it save datavalue in database so i make this code but it show error
input string was not in a correct format
protected void btnSubmit_Click(object sender, EventArgs e)
{
try
{
ErrorMessage.Text = "";
cnx.Open();
SqlCommand insertCmd = new SqlCommand("insert into CouponTransaction(CouponTypeID)values(@id)", cnx);
insertCmd.Parameters.Add("@Id", SqlDbType.TinyInt);
insertCmd.Parameters["@Id"].Value =Int32.Parse (ddlCType.SelectedValue);
insertCmd.ExecuteNonQuery();
ErrorMessage.Text = "Records inserted successfully";
cnx.Close();
}
catch (Exception ex)
{
ErrorMessage.Text = ex.Message;
}
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Good day haleemasher
Change your code to
protected void btnSubmit_Click(object sender, EventArgs e)
{
try
{
ErrorMessage.Text = "";
cnx.Open();
SqlCommand insertCmd = new SqlCommand("insert into CouponTransaction(CouponTypeID)values(@id)", cnx);
insertCmd.Parameters.Add("@Id", SqlDbType.int);
insertCmd.Parameters["@Id"].Value = Convert.ToInt32(ToddlCType.SelectedValue);
insertCmd.ExecuteNonQuery();
ErrorMessage.Text = "Records inserted successfully";
cnx.Close();
}
catch (Exception ex)
{
ErrorMessage.Text = ex.Message;
}
You must put a break point and check what results you get from the selected value. it might have returned an empty string that is why you got that error. You must stop assuming the input from the user is correct.
Try it and tell me what it does
Vuyiswa Maseko,
Few companies that installed computers to reduce the employment of clerks have realized their expectations.... They now need more and more expensive clerks even though they call them "Developers" or "Programmers."
C#/VB.NET/ASP.NET/SQL7/2000/2005/2008
http://www.vuyiswamaseko.somee.com
vuyiswa@its.co.za
http://www.itsabacus.co.za/itsabacus/
modified on Friday, August 14, 2009 5:37 AM
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when i change my code as u suggested it show error System.convert.Tonint32(object) is a method, which is not valid in the given context
the datatype of my ID is tinyint.
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i have change the bold part , go to the thread and check again.
Vuyiswa Maseko,
Few companies that installed computers to reduce the employment of clerks have realized their expectations.... They now need more and more expensive clerks even though they call them "Developers" or "Programmers."
C#/VB.NET/ASP.NET/SQL7/2000/2005/2008
http://www.vuyiswamaseko.somee.com
vuyiswa@its.co.za
http://www.itsabacus.co.za/itsabacus/
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Where is happening exactly. what line ?
Vuyiswa Maseko,
Few companies that installed computers to reduce the employment of clerks have realized their expectations.... They now need more and more expensive clerks even though they call them "Developers" or "Programmers."
C#/VB.NET/ASP.NET/SQL7/2000/2005/2008
http://www.vuyiswamaseko.somee.com
vuyiswa@its.co.za
http://www.itsabacus.co.za/itsabacus/
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haleemasher wrote: input string was not in a correct format
in which line it shows this error
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insertCmd.Parameters.Add("@Id", SqlDbType.Int );
it show error at this line
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insertCmd.Parameters.Add("@Id", SqlDbType.Int );
insertCmd.Parameters["@Id"].Value =Int.Parse(ddlCType.SelectedValue);
if the error still occurs check the ID is integer or not....
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my id datatype is tinyint
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i dono whether i am correct but try to create a interger and parse your tineyint and assing it to the interger which you have crated, then pass the interger value as a parameter....
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sorry not getting your point
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