ASP.NET

Re: video gallery problem...

13-Aug-09 23:57

sneha Choudhary wrote:
will this work in my scenerio?

sorry i am helpless... Frown | :(

Padmanabhan
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Coding C#14-Aug-09 2:26

Coding C#

14-Aug-09 2:26

sneha Choudhary wrote:
<embed src="~/VISUALISE.SWF" style="HEIGHT: 331px; LEFT: 83px; TOP: 171px; WIDTH: 538px" />

will this work in my scenerio?

Yes - It should work for you, just change the source on each hyperlink click.

Coding C#

www.excitetemplate.com

input string was not in a correct format

haleemasher13-Aug-09 22:33

Re: input string was not in a correct format [modified]

13-Aug-09 22:33

i have a dropdown list i it has a different datafield(CouponName) and datavalue(CouponTypeID). i want that when i select a datafield it save datavalue in database so i make this code but it show error
input string was not in a correct format

protected void btnSubmit_Click(object sender, EventArgs e)
    {
        try
        {
            ErrorMessage.Text = "";
            cnx.Open();
            SqlCommand insertCmd = new SqlCommand("insert into CouponTransaction(CouponTypeID)values(@id)", cnx);
                        
            insertCmd.Parameters.Add("@Id", SqlDbType.TinyInt);
            insertCmd.Parameters["@Id"].Value =Int32.Parse (ddlCType.SelectedValue);
           
          
            insertCmd.ExecuteNonQuery();
            ErrorMessage.Text = "Records inserted successfully";
            cnx.Close();
        }
        catch (Exception ex)
        {
            ErrorMessage.Text = ex.Message;
        }

Vimalsoft(Pty) Ltd13-Aug-09 22:55

13-Aug-09 22:55

Good day haleemasher

Change your code to

protected void btnSubmit_Click(object sender, EventArgs e)
    {
        try
        {
            ErrorMessage.Text = "";
            cnx.Open();
            SqlCommand insertCmd = new SqlCommand("insert into CouponTransaction(CouponTypeID)values(@id)", cnx);
                        
            insertCmd.Parameters.Add("@Id", SqlDbType.int);
            insertCmd.Parameters["@Id"].Value = Convert.ToInt32(ToddlCType.SelectedValue);
                   
            insertCmd.ExecuteNonQuery();
            ErrorMessage.Text = "Records inserted successfully";
            cnx.Close();
        }
        catch (Exception ex)
        {
            ErrorMessage.Text = ex.Message;
        }

You must put a break point and check what results you get from the selected value. it might have returned an empty string that is why you got that error. You must stop assuming the input from the user is correct.

Try it and tell me what it does

Vuyiswa Maseko,

Few companies that installed computers to reduce the employment of clerks have realized their expectations.... They now need more and more expensive clerks even though they call them "Developers" or "Programmers."

C#/VB.NET/ASP.NET/SQL7/2000/2005/2008
http://www.vuyiswamaseko.somee.com
vuyiswa@its.co.za
http://www.itsabacus.co.za/itsabacus/

modified on Friday, August 14, 2009 5:37 AM

haleemasher13-Aug-09 23:14

13-Aug-09 23:14

when i change my code as u suggested it show error System.convert.Tonint32(object) is a method, which is not valid in the given context

the datatype of my ID is tinyint.

Vimalsoft(Pty) Ltd13-Aug-09 23:39

13-Aug-09 23:39

i have change the bold part , go to the thread and check again.

haleemasher13-Aug-09 23:47

13-Aug-09 23:47

same problem showing

Vimalsoft(Pty) Ltd14-Aug-09 0:29

14-Aug-09 0:29

Where is happening exactly. what line ?

padmanabhan N13-Aug-09 22:56

13-Aug-09 22:56

haleemasher wrote:
input string was not in a correct format

in which line it shows this error

Padmanabhan
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haleemasher13-Aug-09 23:05

13-Aug-09 23:05

insertCmd.Parameters.Add("@Id", SqlDbType.Int );

it show error at this line

padmanabhan N13-Aug-09 23:14

13-Aug-09 23:14

insertCmd.Parameters.Add("@Id", SqlDbType.Int );
insertCmd.Parameters["@Id"].Value =Int.Parse(ddlCType.SelectedValue);

if the error still occurs check the ID is integer or not....

Padmanabhan
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haleemasher13-Aug-09 23:19

13-Aug-09 23:19

my id datatype is tinyint

padmanabhan N13-Aug-09 23:29

13-Aug-09 23:29

i dono whether i am correct but try to create a interger and parse your tineyint and assing it to the interger which you have crated, then pass the interger value as a parameter....

Padmanabhan
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haleemasher13-Aug-09 23:59

13-Aug-09 23:59

sorry not getting your point

padmanabhan N14-Aug-09 0:03

14-Aug-09 0:03

insertCmd.Parameters.Add("@Id", SqlDbType.TinyInt); insertCmd.Parameters["@Id"].Value =Int32.Parse (ddlCType.SelectedValue);

instead of this...

insertCmd.Parameters.Add("@Id", SqlDbType.TinyInt);
int id = int.parse(ddlCType.SelectedValue);
insertCmd.Parameters["@Id"].Value =id;

Padmanabhan
My Articles:
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My latest Article:
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haleemasher14-Aug-09 0:14

14-Aug-09 0:14

still showing same error

DoctorMick14-Aug-09 0:32

DoctorMick

14-Aug-09 0:32

Put a break point on the line with the error. What is the value of ddlCType.SelectedValue when the error occurs?

bind a girdview with a form view

Coding C#14-Aug-09 2:39

Coding C#

14-Aug-09 2:39

Check if what ever you are trying to convert to int is int actually.

Check if the value in SelectedValue is actually a integer.

Coding C#

www.excitetemplate.com

haleemasher13-Aug-09 22:26

Re: bind a girdview with a form view

13-Aug-09 22:26

i want to bind a girdview with a formview so when i select data in gridview it show in form view and there i edit and insert data.
any link of article??

Vimalsoft(Pty) Ltd13-Aug-09 23:01

Re: bind a girdview with a form view

13-Aug-09 23:01

You cannot bind a gridview with a form view, because the form view is not a Data source. You can Bind a Grid and on selectedindexchange of the grid you bind the Form View based on the selection that is made.

padmanabhan N13-Aug-09 23:31