ASP.NET

30-Mar-09 11:25

I am not sure ( as I don't have VS 2008 yet), but I have done it in VS2005. See if this[^] helps

Yusuf

Oh didn't you notice, analogous to square roots, they recently introduced rectangular, circular, and diamond roots to determine the size of the corresponding shapes when given the area. Luc Pattyn[^]

Re: Debuggubd ashx file

OrsaPoison30-Mar-09 11:43

OrsaPoison

30-Mar-09 11:43

OK so this turnes out to be some sort of glitch in debugger.

MyPage.ashx?blahblahblah=blahblahblah&/&14 does enter debugger.
MyPage.ashx?blahblahblah=blahblahblah&/& does not enter debugger.

Or some variation of it.
I can not give exact line but simce any slight variation of it work I'd say it is a glitch.

Thank you for help.

Re: Debuggubd ashx file

Yusuf30-Mar-09 12:00

Visual Studio 2008 Code Behind Interface

30-Mar-09 12:00

OrsaPoison wrote:
MyPage.ashx?blahblahblah=blahblahblah&/&14 does enter debugger.
MyPage.ashx?blahblahblah=blahblahblah&/& does not enter debugger.

In your second example the you have & which is query string delimiter. May be it that is the issue?

janetb9930-Mar-09 9:20

janetb99

30-Mar-09 9:20

If I upgrade a VS2005 website, or just view a VS2005 in 2008 without converting, code-behind pages reflect page/controls so that I can use the pull-down to select a page or control and then the declarations pull-down reflects the appropriate events for the selection on the left pull-down.

I created a new VS2008 website in verison 3.5 for Ajax. How do I get the page and other controls to appear in the VS2008 code behind interface?

Thanks, jb

Re: Visual Studio 2008 Code Behind Interface

Shahdat Hosain30-Mar-09 9:32

Shahdat Hosain

30-Mar-09 9:32

Just unchecked at project loading

shahdat

Re: Visual Studio 2008 Code Behind Interface

janetb9930-Mar-09 9:35

janetb99

30-Mar-09 9:35

What was unchecked? I have five projects - only the new one created in VS2008 has this problem.

randomly fetching multiple records from database using asp.net

smady1830-Mar-09 8:49

smady18

30-Mar-09 8:49

I am working on online examination project. I face a problem during the databe contain no. of question wth its four option.
how can fetch record in formview cointaing label & radiobuttonlist from database in random order.

if i am select on option, how it can compare wuth correct option.

So plese help me with any sample program or any demo project..... on my email id sanz_smady@rediffmail.com

Re: randomly fetching multiple records from database using asp.net

Colin Angus Mackay30-Mar-09 13:29

Colin Angus Mackay

30-Mar-09 13:29

First, you don't access a database with ASP.NET. ASP.NET is for creating web applications. ADO.NET is the part of .NET that is concerned with databases.

smady18 wrote:
how can fetch record ... from database in random order

To return rows from a database in random order use something like ORDER BY NEWID() (assuming you are using SQL Server)

smady18 wrote:
if i am select on option, how it can compare wuth correct option.

Presumably you know which is the correct option already. Check that the ID for the radio button group being returned matches the ID of the correct answer. (Of course, this assumes much about how you have designed your database)

smady18 wrote:
on my email id...

No. If you want an answer it stays on the forum. That way everyone benefits.

*Developer Day Scotland - Free community conference Delegate Registration Open

How capture the event and go to some validation for Wizard Control .

Shahdat Hosain30-Mar-09 8:24

Shahdat Hosain

30-Mar-09 8:24

In wizard control,how pass one step to another by clicking next button after satisfying
a specific condition say,if(name=="ahsa"){}?
Plz help.

shahdat

submitting form with select - question

shukow30-Mar-09 8:04

shukow

30-Mar-09 8:04

How can i detect, that the select submitted the form?

when i do this:

Re: submitting form with select - question

Christian Graus30-Mar-09 15:25

Christian Graus

30-Mar-09 15:25

View the source of your page to see the script that ASP.NET generates, and that you need to call.

Christian Graus

Driven to the arms of OSX by Vista.

"I am new to programming world. I have been learning c# for about past four weeks. I am quite acquainted with the fundamentals of c#. Now I have to work on a project which converts given flat files to XML using the XML serialization method" - SK64 ( but the forums have stuff like this posted every day )

Update in Gridview not working

chilly44230-Mar-09 6:22

30-Mar-09 6:22

I have a Web Form (VB) that a user can bring in data based on drop down boxes. If the data in the grid needs changed, then the user can click on the edit button for the row and make a change. The problem is, that the change is not reflected in the DB. I know that I am missing something somewhere.

This fills the Grid with the info that the user has selected:

Dim sql As String = "SELECT ID FROM TEST"
        Dim da As New OleDbDataAdapter(Sql, Con)
        Con.ConnectionString = connString
        Con.Open()
        da.Fill(ds, "Events")
        GridView1.DataSource = ds
        GridView1.DataBind()
        count = ds.Tables("Events").Rows.Count
        Con.Close()

This is the update that I am trying to use:

Dim sql As String
        sql = "UPDATE TEST SET ID = @ID WHERE (ID=@ID)"
        Using con As New OleDbConnection("Provider=Microsoft.Jet.OLEDB.4.0;Data Source=E:\WebSite1\App_Data\ODRT.mdb")
            Using cmd As New OleDbCommand(sql, con)
                cmd.CommandText = sql
                cmd.Parameters.AddWithValue("@ID", ID)
                con.Open()
                cmd.ExecuteNonQuery()
                con.Close()
                GridView1.EditIndex = -1
                DataBind()
            End Using
        End Using

Any Ideas??? Mad | :mad:

Thanks,
Chilly

Yusuf30-Mar-09 6:42

30-Mar-09 6:42

chilly442 wrote:
cmd.Parameters.AddWithValue("@ID", ID)

what is the value of ID? did you debug it to see you are using the right value?

chilly44230-Mar-09 6:45

30-Mar-09 6:45

The value that is returned is "__Page" Confused | :confused:

. It should be an assigned number.

Yusuf30-Mar-09 7:31

30-Mar-09 7:31

chilly442 wrote:
The value that is returned is "__Page"

there you have your problem

chilly44230-Mar-09 7:37

30-Mar-09 7:37

How do I fix the problem. What is this telling me? I have never done an update in gridview before. Confused | :confused:

Yusuf30-Mar-09 9:36

30-Mar-09 9:36

How are you getting the value of ID, show us the your code

chilly44230-Mar-09 9:42

30-Mar-09 9:42

Here is the code that I am using on the front end:

<asp:GridView 
     ID="GridView1" 
     runat="server" 
     Font-Size="X-Small" 
     Font-Names="Arial"
     AutoGenerateColumns="False" 
     OnRowEditing="GridView1_RowEditing" 
     OnRowUpdating="GridView1_RowUpdating" 
     OnRowCancelingEdit="GridView1_RowCancelingEdit" 
     OnRowDataBound="GridView1_RowDataBound" BorderColor="Black">
      <Columns>
       <asp:CommandField ShowEditButton="True" />
       <asp:BoundField DataField="ID" HeaderText="ID" InsertVisible="False" ReadOnly="True"/>     
      </Columns>
     </asp:GridView>

Here is the code that I am using on the back end:

Dim sql As String = "SELECT ID FROM TEST"
       Dim da As New OleDbDataAdapter(Sql, Con)
       Con.ConnectionString = connString
       Con.Open()
       da.Fill(ds, "Events")
       GridView1.DataSource = ds
       GridView1.DataBind()
       count = ds.Tables("Events").Rows.Count
       Con.Close()


Dim sql As String
       sql = "UPDATE TEST SET ID = @ID WHERE (ID=@ID)"
       Using con As New OleDbConnection("Provider=Microsoft.Jet.OLEDB.4.0;Data Source=E:\WebSite1\App_Data\ODRT.mdb")
           Using cmd As New OleDbCommand(sql, con)
               cmd.CommandText = sql
               cmd.Parameters.AddWithValue("@ID", ID)
               con.Open()
               cmd.ExecuteNonQuery()
               con.Close()
               GridView1.EditIndex = -1
               DataBind()
           End Using
       End Using

Chilly

Yusuf30-Mar-09 9:45

30-Mar-09 9:45

chilly442 wrote:
cmd.Parameters.AddWithValue("@ID", ID)

where are you getting/setting ID?

chilly44230-Mar-09 9:46

30-Mar-09 9:46

Maybe that is the problem. I am not sure. Where should I be doing it? How should it look?

Yusuf30-Mar-09 9:56

30-Mar-09 9:56

I have no freaking clue. You have the code, not me.

chilly44230-Mar-09 11:33

30-Mar-09 11:33

Why ask all the questions then???

Yusuf30-Mar-09 11:52

30-Mar-09 11:52

chilly442 wrote:
Why ask all the questions then???

Look, we all do this because we love to help. But I can't do your work. It is expected you will be doing most of the heavy lifting.

I asked you where is ID set and how is it set. You said you don't know. Well, what the hell do you want me to do then? I don't have an access to your source code. I am blindly debugging your code, heck you were suppose to debug your code in the first place. If you have slight idea of how to debug, you would not have run into this in the first place.

Now get your arse off that chair get a decent book and learn the fundamentals of programming, before asking such trivial questions.

chilly44230-Mar-09 12:02

30-Mar-09 12:02

I provided all the code that deals with this problem. I do know how to debug. There is no value getting passed to ID. We have already established that. My question is how to set ID. Not asking for a miracle. Just a bit of experience. You are here to help, and I am here to learn. I don't want you to do the work for me, just help to guide me in the right direction.

Chilly Wink | ;)

Yusuf30-Mar-09 12:35