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Hi all!!
Is there a way to use forms with buttons in rtf files??
Or, does richTextBox supports buttons, like ms word?
If I am not clear, I know that in ms word you can create sosmething like a form with command buttons and everything, and I want to use this kind of ability in an editor I am trying to make. And these 2 are the only things I can imagine to accomplish this.
Any suggestions??
Thanks all!!!!
modified on Thursday, April 24, 2008 8:19 AM
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No, you can't do that.
Christian Graus
Please read this if you don't understand the answer I've given you
"also I don't think "TranslateOneToTwoBillion OneHundredAndFortySevenMillion FourHundredAndEightyThreeThousand SixHundredAndFortySeven()" is a very good choice for a function name" - SpacixOne ( offering help to someone who really needed it ) ( spaces added for the benefit of people running at < 1280x1024 )
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No - but the WPF classes like FlowDocument can have rich text and buttons (and in fact any kind of WPF control) embedded in them...
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How can I save the current TreeView nodes into a new TreeNode, apply my modification to that treeNode and then set it back to the TreeView control..
Please help![Rose | [Rose]](https://www.codeproject.com/script/Forums/Images/rose.gif)
All generalizations are wrong, including this one!
(\ /)
(O.o)
(><)
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Just do exactly what you just said
// Create the new node.
TreeNode newNode = new TreeNode();
// Copy any appropriate properties.
newNode.Text = oldNode.Text;
newNode.OtherStuff = oldNode.OtherStuff;
// Apply your modification
newNode.Text += "This text has been changed by me";
// Add the new node to the treeview.
treeView.Nodes.Add(newNode);
Simon
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When saving the TreeNode as a new object you should use the Clone() member.
TreeNode workNode=TreeView.Nodes[0].Clone();
When setting it back to the TreeView you should remove the old node and add the new.
TreeView.Nodes.RemoveAt(0);<br />
TreeView.Nodes.AddAt(0,workNode);
/Ruben
RJJournal
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I've put a SQL Data Access class together which returns a DataSet.
I wanted it to be generic, therefore wrote a method to return a dataset. I am using typed datasets within my application however and the cast throws an error;
MyDefinedSchemaDataSet myDS = (MyDefinedSchemaDataSet)myDataAccessClass.DoSelectStoredProcedure("procStoredProcedureName");
If i use DataAdapter.Fill on a MyDefinedSchemaDataSet.MyDefinedDataTable everything works and there are no errors, however that would throw the idea of a generic method out of the window...
what to do!?
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Try this
DataSet utDataset = myDataAccessClass.DoSelectStoredProcedure("procStoredProcedureName");
MyDefinedSchemaDataSet myDS = new MyDefinedSchemaDataSet();
myDS.Load(utDataset.Tables[0].CreateDataReader(), LoadOption.OverwriteChanges, myDS.myTableName);
Just change the values where appropriate.
Broken Bokken
You can't carry out a ninja-style assasination dressed as an astronaut. It's the luminous fabric; too visible. - Tripod
http://www.brokenbokken.com
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works perfectly! thanks thats what i've been looking for!!!!
think i'll pass parameters in as an arraylist... although not certain yet...
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you should look into using the params keyword instead of an arraylist.
public void MyMethod(params object[] parameters)
{
}
When you call it you can pass them in without having to create a list. You can add as many parameters as you want and is great when you need to pass a list as a parameter to a method.
Broken Bokken
You can't carry out a ninja-style assasination dressed as an astronaut. It's the luminous fabric; too visible. - Tripod
http://www.brokenbokken.com
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Hi,
How to convert the "CCITT u-Law" audio format file to PCM audio format?
Please help me.
Thanks,
Gopal.S
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You could also start a process and call SOX[^] with the correct parameters for your input and output files.
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Dear all;
i recently start programming with C#, and am developing a database project using ms access 2003 and C#... i did the connection using ADO.NET libraries ... locally everything is ok... but when i tried to move the database to another computer within the workgroup and run the application an error concerning the connections appears..
am wondering if access is a good choice to use or if its support this kind of network connection??????
any help....
regards
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Can you use SQL Server instead of MS Access? If yes, I would suggest you to use SQL Server.
However to connect to MS Access on a shared folder, you can create DSN and use ODBC model in your .net application
Regards,
Dave
Dave Traister
Software Engineer
ComponentOne LLC
www.ComponentOne.com
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Hello everyone,
I have verified that the result of 100/0 will not occur any exception, and it will be infinite.
Does it mean there is no exceptions like divide by zero in C#?
thanks in advance,
George
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Eh? How did you do this. If I run the following code, I get a divide by zero exception:
int value1 = 100;
int value2 = 0;
try
{
int output = value1 / value2;
}
catch (DivideByZeroException dbz)
{
Console.WriteLine("I'm here");
}Cunningly, the code hits the DivideByZeroException.
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Here is my code, no exception. Any comments, Pete? 
static void Main(string[] args)
{
try
{
float a = 100;
float b = 0;
float c = a / b;
}
catch (Exception ex)
{
Console.WriteLine("{0}", ex.ToString());
}
return;
}
}
regards,
George
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Wow, very interesting. I never knew that. Yes, I can reproduce that effect with your code.
There are 2 constants:
float.PositiveInfinity
float.NegativeInfinity
and a method:
float.IsInfinity()
I suspect this is related to the imprecision[^] of floating point numbers stored in binary.
Anyone know the full reason for this?
Simon
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Thanks Simon,
I understand how float number is stored in binary format, but why do you think the binary format impacts the result -- other than throw exception, infinity value will be got -- compared with integer type?
regards,
George
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George_George wrote: Any comments, Pete?
Yup. I divided 100 by 0, and you didn't. You divided a float with a value of 100 by a float with a value of 0, which aren't actually 100 and 0. It's a subtle one, but there it is. The int class doesn't have the concept of NaN or Infinity so will yield a divide by zero exception. The converse applies to the float class.
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Great, thanks Pete!
regards,
George
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For int, there is exception, but for float, there is no exception. Can you reproduce?
regards,
George
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