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QuestionThreadsafe "for" without lock() Pin
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AnswerRe: Threadsafe "for" without lock() Pin
Guffa5-Nov-07 12:07
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AnswerRe: Threadsafe "for" without lock() Pin
szolDat5-Nov-07 12:31
szolDat5-Nov-07 12:31 
"You have "solved" a problem that doesn't exist"

Please explain why the following situation isn't possible (I'm somewhat clear about the heap and the stack):
Thread1 enters the cycle, increments i by 1.
The control is passed to Thread2 and it enters the cycle too, incrementing i by 1. i now equals 2.
Thread1 gets control again and tries to access an array's element (or perform any action) using the cycle variable. There you have it, a race condition where the value of i depends on the order of the threads' access to the cycle.

Another thing is, every calculation will give bad results which depends on the number of executions and there are variables involved which are mutually modifiable by the threads. In this situation you have to use a lock, or you can use the method I proposed.

Thank you for your attention.
GeneralRe: Threadsafe "for" without lock() Pin
PIEBALDconsult5-Nov-07 16:02
mvePIEBALDconsult5-Nov-07 16:02 
AnswerRe: Threadsafe "for" without lock() Pin
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GeneralRe: Threadsafe "for" without lock() Pin
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AnswerRe: Threadsafe "for" without lock() Pin
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