DataGrid paging not working - C# Discussion Boards

Luc Pattyn2-Jul-07 3:08

2-Jul-07 3:08

Hi,

there basically are two approaches:

1.
use an array; when it needs to grow, create a new one and copy the contents
(e.g. using Array.Copy)
Thats what ReDim does behind the scenes.

2.
use a collection, such as an ArrayList or a List. These act like stretchable arrays,
but are a bit slower in accessing their elements.

So to choose one or the other you must balance the add/remove operations against the
read/write operations.

Smile | :)

Luc Pattyn

[My Articles] [Forum Guidelines]

Re: how to change this in C# ?

Martin#2-Jul-07 3:19

Martin#

2-Jul-07 3:19

Hello Luc,

For strings I like to use the dynamic:
System.Collections.Specialized.StringCollection dynstringarray = new System.Collections.Specialized.StringCollection();

All the best,

Martin

Re: how to change this in C# ?

Luc Pattyn2-Jul-07 3:29

Luc Pattyn

2-Jul-07 3:29

Hi Martin,

I did not know StringCollection.
I created my own StringList back in the 1.x times, and am still using it...
Thanks for the info.

Smile | :)

Luc Pattyn

[My Articles] [Forum Guidelines]

Re: how to change this in C# ?

Martin#2-Jul-07 3:32

Martin#

2-Jul-07 3:32

Glad I could give you a info!
Doesn't happen so often.

All the best,

Martin

Re: how to change this in C# ?

Luc Pattyn2-Jul-07 3:54

Luc Pattyn

2-Jul-07 3:54

Luc Pattyn

[My Articles] [Forum Guidelines]

How to read the words from a pdf?

Tomerland2-Jul-07 2:19

Tomerland

2-Jul-07 2:19

Dear gurus,

I want to make a statistics on the words of any text within a pdf-file.

Do you know how I can access a pdf for my purpose?

thanks in advance

Re: How to read the words from a pdf?

CPallini2-Jul-07 3:43

CPallini

2-Jul-07 3:43

Hint: try to search CP articles containing the word pdf.

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.

DataGrid paging not working

Jax_qqq2-Jul-07 1:26

Jax_qqq

2-Jul-07 1:26

Hi all,

I am reandering a Data Grid from my web part containing a paging event its giving me post back but grid is rendering twise on the page.

Any suggestion???

<br />
        protected override void CreateChildControls()<br />
        {<br />
            DataTable data = null;<br />
            string[] columnArray = null;<br />
            bool IsColumns = false;<br />
            DataTableValidationStatus tableStatus;<br />
<br />
            try<br />
            {<br />
                if (!String.IsNullOrEmpty(Columns))<br />
                {<br />
                    columnArray = Columns.Replace(" ", "").Split(',');<br />
                    IsColumns = true;<br />
                }<br />
<br />
                data = GetDataTable();<br />
                tableStatus = Utility.ValidateDataTable(data, true, true, IsColumns, columnArray);<br />
<br />
                if (tableStatus == DataTableValidationStatus.Valid)<br />
                {<br />
                    data.Locale = System.Globalization.CultureInfo.InvariantCulture;<br />
<br />
                    grid.EnableViewState = true;<br />
                    grid.AutoGenerateColumns = false;<br />
                    grid.AllowPaging = true;<br />
                    grid.PageSize = PageSize;<br />
                    grid.CurrentPageIndex = currentpageindex;<br />
                    grid.PagerStyle.Mode = PagerMode.NextPrev;<br />
                    grid.PagerStyle.CssClass = PagerStyleCssClass;<br />
<br />
                    grid.CssClass = GridCssClass;<br />
                    grid.AlternatingItemStyle.CssClass = AlternatCssClass;<br />
                    grid.HeaderStyle.CssClass = HeaderCssClass;<br />
                    grid.ItemStyle.CssClass = ItemCssClass;<br />
<br />
                    grid.Width = System.Web.UI.WebControls.Unit.Percentage(100);<br />
<br />
                    grid.PageIndexChanged += new DataGridPageChangedEventHandler(this.grid_PageIndexChanged);<br />
<br />
                    grid.DataSource = data;<br />
                    grid.DataBind();<br />
                    Controls.Add(grid);<br />
                }<br />
}<br />
<br />
        private void grid_PageIndexChanged(object source, System.Web.UI.WebControls.DataGridPageChangedEventArgs e)<br />
        {<br />
            currentpageindex = e.NewPageIndex;<br />
            BindGrid();<br />
        }<br />

Anuj

Line code

merwa2-Jul-07 1:16

merwa

2-Jul-07 1:16

Hi All,
I want to use the outlook application in my program i want to use it's option without opening it.

I hear about a line code but i need more help about that.

merwa

Re: Line code

Jimmanuel2-Jul-07 2:36

Jimmanuel

2-Jul-07 2:36

Here's[^] an example on MSDN of how to use MS Outlook in C#.

TCP channel v/s HTTP channel

amitcoder832-Jul-07 0:35

amitcoder83

2-Jul-07 0:35

in remoting, the choice of the channel for intranet application without firewall protection or allowing communication thru some port, is mostly TCP.we can achieve our functionality by http channel as well.but by using TCP we get performance gain since TCP is faster than HTTP.

Can anyone clarify why communication over TCP channel is Faster than on Http channel

Re: TCP channel v/s HTTP channel

originSH2-Jul-07 2:40

originSH

2-Jul-07 2:40

Any particualr reason you need to ask again?

http://www.codeproject.com/script/comments/forums.asp?msg=2068843&forumid=1649&XtraIDs=1649&searchkw=tcp+http+remoting&sd=3+Apr+2007&ed=2+Jul+2007&stype=1#xx2068843xx[^]

Problem with symetric algorithm (Rihndael)

FernandoCR2-Jul-07 0:20

FernandoCR

2-Jul-07 0:20

I am try crypt and decrypt the same text. I am use a symetric algorithm (Rijndael), but I don´t understand what happend whit my code. This is the test.
1. I write a text in a textbox (txtSrc).
2. I read the text, crypt it and write it in a label (lblCph1).
3. I read the text in the label and again crypt it y write the result in other label (lblCph2).
In the point 2, I expect the text of the label with strange simbols (cipher it), and in the pint 3 I expect the text of the label in plain text, but it is in strange simbols too. I don´t undertand, I think what if I crypt a text with the same key a pair of time, it will be decrypted. ¿Someone can explain to me?

I have write a example code.

<br />
using System;<br />
using System.Collections.Generic;<br />
using System.ComponentModel;<br />
using System.Data;<br />
using System.Drawing;<br />
using System.Text;<br />
using System.Windows.Forms;<br />
using System.Security.Cryptography;<br />
using System.IO;<br />
<br />
namespace PruebaSimetrica<br />
{<br />
    public partial class Form1 : Form<br />
    {<br />
        public Form1()<br />
        {<br />
            InitializeComponent();<br />
        }<br />
<br />
        private void Form1_Load(object sender, EventArgs e)<br />
        {<br />
<br />
        }<br />
<br />
        private void btnCph1_Click(object sender, EventArgs e)<br />
        {<br />
            //Gererate a Key and IV<br />
            byte[] RellenoKey = new byte[] { 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, 0x88, 0x99, 0x00, 0xAA, 0xBB, 0xCC, 0xDD, 0xEE, 0xFF, 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, 0x88, 0x99, 0x00, 0xAA, 0xBB, 0xCC, 0xDD, 0xEE, 0xFF };<br />
            byte[] RellenoIV = new byte[] { 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, 0x88, 0x99, 0x00, 0xAA, 0xBB, 0xCC, 0xDD, 0xEE, 0xFF };<br />
            // Create a new Rijndael object.<br />
            Rijndael RijndaelAlg = Rijndael.Create();<br />
            RijndaelAlg.Key = RellenoKey;<br />
            RijndaelAlg.IV = RellenoIV;<br />
            //Get the plain text<br />
            byte[] bytePlainText = Encoding.Default.GetBytes(txtSrc.Text);<br />
            byte[] byteCryptText;<br />
            <br />
            bytePlainText = Encoding.Default.GetBytes(txtSrc.Text);<br />
<br />
            MemoryStream mStream = new MemoryStream();<br />
            // Create a CryptoStream using the MemoryStream <br />
            // and the passed key and initialization vector (IV).<br />
            CryptoStream cStream = new CryptoStream(mStream, RijndaelAlg.CreateEncryptor(RijndaelAlg.Key, RijndaelAlg.IV), CryptoStreamMode.Write);<br />
<br />
            cStream.Write(bytePlainText, 0, bytePlainText.Length);<br />
            cStream.FlushFinalBlock();<br />
                        <br />
            byteCryptText = mStream.ToArray();<br />
<br />
            lblcph1.Text = System.Text.Encoding.Default.GetString(byteCryptText);<br />
            <br />
            cStream.Close();<br />
            mStream.Close();<br />
        }<br />
<br />
        private void btnCph2_Click(object sender, EventArgs e)<br />
        {<br />
            //Gererate the same Key and IV<br />
            byte[] RellenoKey = new byte[] { 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, 0x88, 0x99, 0x00, 0xAA, 0xBB, 0xCC, 0xDD, 0xEE, 0xFF, 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, 0x88, 0x99, 0x00, 0xAA, 0xBB, 0xCC, 0xDD, 0xEE, 0xFF };<br />
            byte[] RellenoIV = new byte[] { 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, 0x88, 0x99, 0x00, 0xAA, 0xBB, 0xCC, 0xDD, 0xEE, 0xFF };<br />
            Rijndael RijndaelAlg = Rijndael.Create();<br />
            RijndaelAlg.Key = RellenoKey;<br />
            RijndaelAlg.IV = RellenoIV;<br />
            byte[] bytePlainText  ;<br />
            byte[] byteCryptText=Encoding.Default.GetBytes(lblcph1.Text);<br />
<br />
            byteCryptText = Encoding.Default.GetBytes(lblcph1.Text);<br />
<br />
            MemoryStream mStream = new MemoryStream();<br />
<br />
            CryptoStream cStream = new CryptoStream(mStream, RijndaelAlg.CreateEncryptor(RijndaelAlg.Key, RijndaelAlg.IV), CryptoStreamMode.Write);<br />
<br />
            cStream.Write(byteCryptText, 0, byteCryptText.Length);<br />
            cStream.FlushFinalBlock();<br />
<br />
            bytePlainText = mStream.ToArray();<br />
<br />
            lblCph2.Text = System.Text.Encoding.Default.GetString(bytePlainText);<br />
<br />
            cStream.Close();<br />
            mStream.Close();<br />
        }<br />
 <br />
    }<br />
}

Thanks,
Fernando

Re: Problem with symetric algorithm (Rihndael)

Abisodun2-Jul-07 2:41

Abisodun

2-Jul-07 2:41

To return encrypted text to plain text use CreateDecryptor().

Re: Problem with symetric algorithm (Rihndael)

FernandoCR3-Jul-07 1:13

FernandoCR

3-Jul-07 1:13

Yes, it is true, they finally work.
I was a week doing changes.

Thank
Fernando

Reading color of each entity in DXF file

a_david1232-Jul-07 0:16

a_david123

2-Jul-07 0:16

Dear All
Regards!
I have a program that opened and read a DXF file format in C# and then draw all the entities in DXF file using openGL, but i can't read the color of these entities which are given in DXF file,
so need program in C# Sigh | :sigh:

to read the color of each entity i.e circle, polyline,arc etc..,of DXF file and then draw each entitiy i.e circle, polylines etc, in that specific color, as for each entity there is color in DXF file.

kindly help me while writng program for it.
Thanks
David

david

writing a hardware lock

logicaldna1-Jul-07 23:36

logicaldna

1-Jul-07 23:36

hey,
i'm writing a hardware lock for my new tailor made software,
my approch is,
For every DML i'll check for the existance of hardware lock,
for this i'll query the hardware to send me some GUID,
comapre this GUID with one from software side,
if it matches then continue else stop

(the hardware for this will be designed according requirments given)

now questions :->
Should i use serial port or usb ? (in terms of processing time)
use a function to generate this GUID ?(well i will surely do tht, but whts the general practice/ algorithm)
will this ID be machine dependent?
becoz what i want is one installation CD with one hardware lock which can work on any machine?

give me an idea, as i'm thinking tht it wont be as simple as wht i'm thinking Smile | :)

regards,
logicaldna

Chase your dreams !
http://eminencetech.net[^]

Re: writing a hardware lock

Luc Pattyn1-Jul-07 23:50

Luc Pattyn

1-Jul-07 23:50

I will answer the hardware part only:

it has to be USB, since a modern PC (desktop or laptop) has 2, 4, 6 or more USB ports
and often 0 serial ports.
furthermore, if I need several hardware locks, its much easier to add USB ports (using
a USB hub), than it is to add serial ports.
and lastly you can easily have USB ports at a distance, such as the USB ports found on
many desktop monitors.
The performance issue AFAIK is irrelevant since an app will typically check the hardware
lock only once (at startup), or a couple of times (when saving something),
certainly not all the time.

BTW there are companies such as WIBU[^] that sell
USB hardware locks; they are organized in such a way
that they can hold a number of keys plus a couple KB of app data; so a new software
can be linked to either an existing key or a new, empty key, and that is how it should be.

And of course, companies that offer hardware keys also have the necessary software
to support them, including an API to integrate it in the app itself.

To sum it up, whatever your software product is going to be, if it comes with a
serial port hardware lock I wont buy it. If it works with a USB key, it better be
from a trusted hardware source and able to combine with other protected packages...
So I dont see the point in reinventing stuff that exists and performs well.

Smile | :)

Luc Pattyn

[My Articles] [Forum Guidelines]

Re: writing a hardware lock

logicaldna2-Jul-07 0:19

logicaldna

2-Jul-07 0:19

Luc Pattyn wrote:
So I dont see the point in reinventing stuff that exists and performs well.

cost !

i have resources which will give me the hardware and i can write software, if i do it neatly,then i have something to sell :->

you won't belive, but i might have to install software on machines where they dont have USB port
so now i'm thinking of putting a switch as it should work on both (serial and USB)

thanks anyways !

regards,
logicaldna

Chase your dreams !
http://eminencetech.net[^]

Exporting data from database to a file, zipping it and mailing

I.explore.code1-Jul-07 23:22

I.explore.code

1-Jul-07 23:22

Hi,

I need to export data from DB (SQL Server 2005) to a file (eg. Excel, text file or any other format, .CSV) at the same time preserving the rows and column schema of the DB. Then I need to zip it and mail it across to a mail id.

One approach is to use File object to create a text or excel file, but the data will be scrambled when it will be written on to the file.

I need to do all this programmatically.Please help.

Re: Exporting data from database to a file, zipping it and mailing

nitikin2-Jul-07 0:16

nitikin

2-Jul-07 0:16

Why not use the "FOR XML" with the SELECT statment? This way you get a XML representation, which could be saved to file etc etc.. ?

namaste,
Nitin Koshy
http://devwaves.blogspot.com
...and I thought I knew

Problem in closing the login window

I.explore.code1-Jul-07 23:15

I.explore.code

1-Jul-07 23:15

hi, I have a login window that opens up before any other window of the application. the problem is that I m not able to close the login window upon authentication and then load the parent window of the system.

I use the following code to hide the login window:

this.FindForm().Visible=false;

but hiding the window is a very bad approach as though the form is not visible but it still is consuming memory.

the following code to close the window closes all the windows of the application, including the MDI parent form

this.FindForm().Close();

Please help

Re: Problem in closing the login window

logicaldna1-Jul-07 23:41

logicaldna

1-Jul-07 23:41

Use MDI container , open the login as the child of tht MDI, on successful login close the form as its a child it wont close the parent, open a new form which you want to show !
does tht help ?

regards,
logicaldna

Chase your dreams !
http://eminencetech.net[^]

Re: Problem in closing the login window

Martin#1-Jul-07 23:44

Martin#

1-Jul-07 23:44

Hello,

Maybe a splash screen would help you out.
http://www.codeproject.com/csharp/applicationcontextsplash.asp[^]

All the best,

Martin

Re: Problem in closing the login window

Navneet Hegde2-Jul-07 1:56

Navneet Hegde

2-Jul-07 1:56

Hi,
There is simple approach to this problem create MDI form
and on MDI Form_load event

formLogin.Showdialog() --for .Net--
OR
formLogin.show(vbmodal) --for VB classic--

[ remember formLogin is not a child Form ]

and At Last on Successful Login Close formLogin.Close

Thanks & Wishes
Navneet Hegde
Nashik(City Of Pilgrimage)

Develop2Program & Program2Develop

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