Re: Problem in firing the Linkbutton Click Event - ASP.NET Discussion Boards

POST is not secure and not encrypted! It is still sent as plain text in the HTTP request and is easily viewable.

With Regards,

Sakthi

hi srilakshmi

take this link it is easy with example

http://aspnet.asp101.com/samples/getpost.aspx[^]

Regards,
Sylvester G
sylvester_g_m@yahoo.com

hi,
i designed one login page in asp.net with vb.net. i that i want to put one Captcha image verification, i search for it in google,but i cont get the right one, so plz help me

jai prakash

Captcha Image[^]

With Regards,

Sakthi

Hi Friends,
I have created a module which will load the directories in the given root directory in a TreeView. When we choose an item it will load the Folders and files in the right side pane (Panel). Everything works fine. For loading the Folders and files in the right pane, I am using LinkButton for each item nested inside a Server-side Table control. I added Click event to that LinkButtion to open the clicked item. But this Click event is not firing, but the page is postbacking. This LinkButtons are generated dynamically, where the ID is assigned dynamically.

Can anyone help me with this problem?

Regards,
Venkatesh Mookkan.
Software Engineer, India
My: Website | Yahoo Group | Blog Spot

Can you please send a bit of code, that you have written. Can't guess on the fly exactly where is the problem in your code Smile | :)

Cheers,

Here is the code,

Protected Sub LoadFileFolders(ByVal FileFolderPath As String, Optional ByVal _FileType As FileType = FileType.Folder)
     If _FileType = FileType.File Then
         Dim HtmlString As New StringBuilder
         HtmlString.Append("<iframe width=""100%"" height=""100%"" frameborder=""0""")
         HtmlString.Append(" src=""" & FileFolderPath & """>" & vbCrLf)
         HtmlString.Append("</iframe>" & vbCrLf)
         Dim LblContent As New Label
         LblContent.Text = HtmlString.ToString
         PnlFoldersFiles.Controls.Clear()
         PnlFoldersFiles.Controls.Add(LblContent)
     Else
         Dim TblMain As New Table
         Dim TrMain As TableRow
         Dim TcMain As TableCell

         TblMain.CellPadding = 2
         TblMain.CellSpacing = 2
         TblMain.BorderWidth = 0

         Dim _Dir As New IO.DirectoryInfo(FileFolderPath)
         Dim _DirectoryInfo() As IO.DirectoryInfo = _Dir.GetDirectories

         Dim ICount As Integer = 0

         Dim LkbFolder As LinkButton
         For Each _D As IO.DirectoryInfo In _DirectoryInfo
             LkbFolder = New LinkButton

             TrMain = New TableRow

             TcMain = New TableCell
             TcMain.Text = "<img src=""images/folderClosed.gif"" />"
             TrMain.Cells.Add(TcMain)

             TcMain = New TableCell
             LkbFolder.ID = "Lkb_Folder" & ICount
             LkbFolder.Text = _D.Name
             TcMain.Controls.Add(LkbFolder)
             AddHandler LkbFolder.Click, AddressOf FolderFile_Click

             TrMain.Cells.Add(TcMain)
             TblMain.Rows.Add(TrMain)
             ICount += 1
         Next

         _Dir = New IO.DirectoryInfo(FileFolderPath)

         Dim LkbFile As LinkButton
         For Each _File As IO.FileInfo In _Dir.GetFiles
             Dim _Ext As String = _File.Extension
             Dim FileImage As String = "unknownimg.gif"

             Select Case _Ext
                 Case ".htm", ".html", ".mht"
                     FileImage = "htmlimg.gif"
                 Case ".asp"
                     FileImage = "aspimg.gif"
                 Case ".aspx"
                     FileImage = "aspximg.gif"
                 Case ".resx"
                     FileImage = "resximg.gif"
                 Case ".vbproj"
                     FileImage = "vbprojimg.gif"
                 Case ".vb"
                     FileImage = "aspxvbimg.gif"
                 Case ".asa", ".asax", ".webinfo"
                     FileImage = "asaimg.gif"
                 Case ".pdf"
                     FileImage = "pdfimg.gif"
                 Case ".config"
                     FileImage = "configimg.gif"
                 Case ".vsdisco"
                     FileImage = "vsdiscoimg.gif"
                 Case ".sln"
                     FileImage = "solimg.gif"
                 Case ".txt"
                     FileImage = "textimg.gif"
                 Case ".gif"
                     FileImage = "gifimg.gif"
                 Case ".jpg", ".jpeg"
                     FileImage = "jpgimg.gif"
                 Case ".dll", ".ocx"
                     FileImage = "dllimg.gif"
                 Case ".pdb"
                     FileImage = "pdbimg.gif"
                 Case ".mdb"
                     FileImage = "mdbimg.gif"
                 Case ".doc"
                     FileImage = "docimg.gif"
                 Case ".inc"
                     FileImage = "incimg.gif"
                 Case ".xls", ".csv"
                     FileImage = "excelimg.gif"
                 Case ".sql"
                     FileImage = "sqlimg.gif"
                 Case ".zip"
                     FileImage = "zipimg.gif"
                 Case ".exe"
                     FileImage = "exeimg.gif"
                 Case ".bmp"
                     FileImage = "bmpimg.gif"
                 Case ".js", ".vbs"
                     FileImage = "scriptimg.gif"
                 Case ".pps", ".ppt"
                     FileImage = "pptimg.gif"
             End Select

             TrMain = New TableRow

             TcMain = New TableCell
             TcMain.Text = "<img src=""images/" & FileImage & """ />"
             TrMain.Cells.Add(TcMain)

             LkbFile = New LinkButton
             TcMain = New TableCell
             LkbFile.Text = _File.Name
             LkbFile.ID = "Lkb_File" & ICount
             AddHandler LkbFile.Click, AddressOf FolderFile_Click
             TcMain.Controls.Add(LkbFile)

             TrMain.Cells.Add(TcMain)

             TblMain.Rows.Add(TrMain)
             ICount += 1
         Next
         PnlFoldersFiles.Controls.Add(TblMain)
     End If
 End Sub

Here PnlFoldersFiles is the Right side Pane (Panel)

Additionally I have the Click Event separately. I believe you don't need that event.

Regards,
Venkatesh Mookkan.
Software Engineer, India
My: Website | Yahoo Group | Blog Spot

Hi,

You should create an handlere to handle event of linkbutton and assign that handler to the click event of dynamically generated linkbuttons at runtime.
Have a look at following.

The following is the handler to handle command event of your link button.
Command event will fire when u click on the linkbutton.
We consider command event because in this event you can differentiate which linkbutton is clicked and depend on commandname and commandargument you can execute accordingly.
protected void lnk_Command ( object sender, CommandEventArgs e )
{
string strCommand = e.CommandName;
string strArgument = e.CommandArgument;
}

In the following code I m creating a linkbutton dynamically, assigning ID, CommandName, CommandArgument and EventHandler to it.

LinkButton Lnk = new LinkButton();
Lnk.ID = "ID";
Lnk.CommandName = "urcommandName";
Lnk.CommandArgument = "urCommandargument";
Lnk.Command +=new CommandEventHandler(lnk_Command);

This way you can create as many linkbuttons and assign unique commandargument and commandname to each of them.

I hope this will help you.

Thanks and Regards,
Chetan Ranpariya

Did you said,

Chetan Ranpariya wrote:
Lnk.Command +=new CommandEventHandler(lnk_Command);

I am afraid, LinkButton does not have a Property/Method as Command. Its an Event, where we can't assign by direct method.

I have already added the Click Event for that LinkButton using AddHandler method. If you want to know more about the code see that code I posted for the previous reply.

Regards,
Venkatesh Mookkan.
Software Engineer, India
My: Website | Yahoo Group | Blog Spot

Hi,

I applogize for not seeing your code properly.

Command is not a property/method of linkbutton but its an event and u can use addhandler method for it as u do with the click event.

I suggested the command event not the click event because in command event u can decide what code to execute depend on the commandname and commandargument.

but if u want to use click event then that's fine.

According to my observation of your code it is correct and as u r adding handler for each of the linkbutton it should work fine.

There may be some other problem. Did u tried by debugging or puting some output statement in the event handler?

Thanks and Regards,
Chetan Ranpariya

Chetan Ranpariya wrote:
I applogize for not seeing your code properly.

Its ok.

Chetan Ranpariya wrote:
Did u tried by debugging or puting some output statement in the event handler?

Yes. I do have. Additionally I added another table with the same logic to load the files, and added LinkButton with the Click event. There the event is firing. I don't understand why?

Regards,
Venkatesh Mookkan.
Software Engineer, India
My: Website | Yahoo Group | Blog Spot

hi all,

I have created a web application project in asp.net 2.0 and i have created the .msi installable file using the web deployment method of VS 2005.

I installed the project and tried to run it using the virtual directory name i gave during the installation process.

I got the parser error as

Parser Error

Description: An error occurred during the parsing of a resource required to service this request. Please review the following specific parse error details and modify your source file appropriately.

Parser Error Message: Could not load type 'SampleDemo._Default'.

Source Error:

Line 1: <%@ Page Language="vb" AutoEventWireup="false" CodeBehind="Default.aspx.vb" Inherits="SampleDemo._Default" %>
Line 2:
Line 3:

Source File: /deploydemo/default.aspx Line: 1

--------------------------------------------------------------------------------
Version Information: Microsoft .NET Framework Version:2.0.50727.42; ASP.NET Version:2.0.50727.210

then I came to know that the .DLL file in not extracted into the bin folder instead its been extracted to the main folder where other aspx files been extracted.

I need to solve this problem.

When we follow the steps in VS 2003 its working good.but in 2005 the .DDL file has been extracted to main folder.I don't know its there any problem in the steps i have executed OR its the default procedure of VS 2005 .

can any one solve this problem

PS:. i need .DLL must be extracted to bin folder.because we ll give that .msi file to our client.it should be in working condition if we execute the .msi file.

thanks in advance

Senthilraj K

Hi,
i have an asp.net application which has pages in different folders like
supervisors, managers etc.

and each folder has n number of pages(aspx). it is finding difficulty for me to check the user rights for each page. so is it possible to restrict the user if he does not have the manager rights to all the pages in the manager folder?

Please help.

Biju S

You must have a list of users, roles and UserRoles. You will have to use windows security to load the roles for the current user. Then ;

protected void Page_Load(object sender, EventArgs e)
CheckRole()
{
if(!IsPostBack)
{
//Do Something
}

public void CheckRole()
{
if (!Context.User.IsInRole("Manager"))
{
thow new Exception("Access Denied");
}
}
}

You can usethe windows security using the following:

using System.Security.Principal;
and then

IIdentity identity;
String[] roles = {"manager","employee"};
GenericPrincipal g = new GenericPrincipal(identity, roles);

You will have to fix the IIdentity part above.

only two letters away from being an asset

Use the web.config file to set security for the folders, similar to below

<configuration>
<location path="Folder1">
<system.web>
<authorization>
<deny roles="group"/>
<allow roles="admin"/>
<allow users="?"/>
</authorization>
</system.web>
</location>
</configuration>

only two letters away from being an asset

I create a datable in the event of button1
how can I use it in the event of button2? please help me

I do this :
in button1
Session["temptable"]=dt;

in button2
dt=(DataTable)Session["temptable"];

when I debug it
messege show it is not exit dt in event of button2

Your question makes no sense. Are you sure the table does not exist ? dt is null, or you get a message that the variable does not exist ? If the latter, then you're in release mode.

Christian Graus - Microsoft MVP - C++
Metal Musings - Rex and my new metal blog
"I am working on a project that will convert a FORTRAN code to corresponding C++ code.I am not aware of FORTRAN syntax" ( spotted in the C++/CLI forum )

Put the datatable in the session again and then use it in the cleck event of the second button.

Apurva Kaushal

good day everyone..

again i need your help... on how to include my separate report made from crystal report 9 to asp.net 2003?

pls send me link on where i could use as a refenrence.... thank you...

start a new beginning in every ending; thats what life for......

Get it[^]

Regards,

Satips. Rose | [Rose]

Hi all,

I'm a programmer in Web developer with ASP.NET 2.0, C# basic. I have this issue and it cost me lots of time on investigating the solution. Let me explain the scenario in the easiest way to understand. Let say i have site A and site B, both of them have Response.Cache.SetCacheability(NoCache), reason of disable caching is prevent user from hitting back button to go back to their previous viewed pages after they signed out. And i succeed in this prevention. But i've got the issue of Page has expired. When i deal with surfing like go to Page A, then B, then hit back button to Page A, then back button to B again and again, there's nothing happen because they are 2 different pages. but when i work on Page A only, let say i have a multiview menu in Page A, then i switch from tab X to tab Y, then hit back button, that throw Page has expired. Im so sick with this. As far as i know that because the post back url point to the same page, and this is just a warning from IE from duplicating request to one page, but this is disturbing end user a lot. Is there any work around this?

Please assist me on this, any of your solutions are appreciated.
Thank you very much.

-- modified at 19:58 Thursday 14th June, 2007

I moved this to the ASP.NET forum, please in future respect the notice that says 'do not post programming questions in the lounge'.

There is no END ROAD in the world, the end of this road is the beginning of another road...

Hi, I have made changes to my code according to the responses I was getting the last time I post a question about the exception " Object reference not set to an instance of an object". I still get the same exception after the changes. It's saying that the line

strGoodPassword = CType(myCommand.ExecuteScalar, String)

is the cause of the problem. I don't know what else to to, please take a look at my code below. Thank you in advance for your help.

Private Sub lblRegister_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles lblRegister.Click
        Dim bResult As Boolean = False
        Dim myConnection As OdbcConnection
        Dim myCommand As OdbcCommand
        Dim strInsert As String
        Dim strGoodPassword As String
        Dim strSQL As String
        strSQL = String.Empty
        
        myConnection = New OdbcConnection("Driver={MySQL ODBC 3.51 Driver};Server=localhost;Database=myDb;User=myUSERassword=myPW;Option=3;")
        strSQL = String.Format("SELECT myUserName FROM myTable WHERE (email='{0}');", txtUserName.text)
        myConnection.Open()
        strGoodPassword = CType(myCommand.ExecuteScalar, String)
        If Not strGoodPassword Is Nothing Then
            If strGoodPassword = txtUserName.Text Then
                bResult = True
            Else
                lblMessage.Text = "That user name is already taken!"
                lblMessage.Text &= "  Please choose another user name."
            End If
        Else
            lblMessage.Text = "That user name is already taken!"
            lblMessage.Text &= "  Please choose another user name."
        End If
        strInsert = "INSERT into membersinfotbl (FirstName,LastName,Password,Phone,Email,Profession,StrAddress,City,State,ZipCode)value (?,?,?,?,?,?,?,?,?,?)"
        
        myCommand As New OdbcCommand(strInsert,myConnection)
        myCommand.Parameters.Add("@FirstName", txtFirst.Text)
        myCommand.Parameters.Add("@LastName", txtLast.Text)
        myCommand.Parameters.Add("@Password", txtPassword.Text)
        myCommand.Parameters.Add("@Phone", txtPhone.Text)
        myCommand.Parameters.Add("@Email", txtEmail.Text)
        myCommand.Parameters.Add("@Profession", txtProfession.Text)
        myCommand.Parameters.Add("@StrAddress", txtAddress.Text)
        myCommand.Parameters.Add("@City", txtCity.Text)
        myCommand.Parameters.Add("@State", txtState.Text)
        myCommand.Parameters.Add("@ZipCode", txtZipCode.Text)        
        myCommand.ExecuteNonQuery()
        myConnection.Close()
End Sub

-- modified at 20:03 Thursday 14th June, 2007

If you post 20 lines of code, tell us which one has the error

ASPnoob wrote:
strSQL = String.Format("SELECT myUserName FROM myTable WHERE (email='{0}');", txtUserName.text)

You need to read up on SQL injection attacks. Odds are good that if you give me the URL of this site, I can delete your entire database.

I can't see which line could fail, let us know where to look.

Christian Graus - Microsoft MVP - C++
Metal Musings - Rex and my new metal blog
"I am working on a project that will convert a FORTRAN code to corresponding C++ code.I am not aware of FORTRAN syntax" ( spotted in the C++/CLI forum )