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Static Control Prob. Pls reply me TobetheWinner10-Jun-07 18:49 TobetheWinner 10-Jun-07 18:49  Im Create a static control inorder to use it as a label CStatic *temp = new CStatic(); temp->Create("YYYYY" ,SS_SIMPLE ,CRect(0,0,25,25) ,this); My requirement is if my text which should display inside static control exceeds the rectangle limits it should take a new line automatically. It Must be multiline static control. so how can i do it. bhw Re: Static Control Prob. Pls reply me Rajkumar R10-Jun-07 19:02 Rajkumar R 10-Jun-07 19:02  Use MultiLine Edit Control and make it readonly. Re: Static Control Prob. Pls reply me TobetheWinner10-Jun-07 19:07 TobetheWinner 10-Jun-07 19:07  Thanks bhw Static Control Prob. Pls reply me TobetheWinner10-Jun-07 19:40 TobetheWinner 10-Jun-07 19:40  In the read only edit box how to stop the blinking |. bhw Re: Static Control Prob. Pls reply me Christian Graus10-Jun-07 20:16 Christian Graus 10-Jun-07 20:16  Don't let it have the input focus. Christian Graus - Microsoft MVP - C++ Metal Musings - Rex and my new metal blog "I am working on a project that will convert a FORTRAN code to corresponding C++ code.I am not aware of FORTRAN syntax" ( spotted in the C++/CLI forum ) Multithreaded download http files victording10-Jun-07 16:07 victording 10-Jun-07 16:07  Hi ereryone, I need a multithreaded downloading module for my project in vc++.net now. Would you like give me the code about it? Or give me some advice to do this. Thanks a lot! Accessing the parent's data members Vancouver10-Jun-07 15:26 Vancouver 10-Jun-07 15:26  I subclassed a control (actually, a CStatic) and want to access from it's functions some data members of the parent. Let's say the new class of the control is CMyOwnCtl, and the parent, the main dialog, is CMyOwnDlg. I am defining a pointer to the parent in CMyOwnCtl.h: CMyOwnDlg *Parent; This works only with #include "CMyOwnDlg.h" #include "CMyOwnCtl.h" in this sequence. However, CMyOwnDlg.h requires the definition of CMyOwnCtl, i.e. the includes have to be in the other sequence. I solved this by placing the pointer to the parent in the global definitions. However, I wonder if it could be done more elegantly. Re: Accessing the parent's data members Christian Graus10-Jun-07 16:29 Christian Graus 10-Jun-07 16:29  You can put the includes in the cpp files, and then forward declare the class - so put class CMyOnwCtl; in the top of CMyOwnDlg.h and vice versa. This tells the compiler that a class exists, and it will find the details out during the compile process. I should add - this works because you have a *pointer* to CMyOwnDlg in CMyOwnCtl - this is fine, all the compiler needs to do when compiling the header, is allocate space for a pointer. If you put an instance of the object in the header, it would not work. Christian Graus - Microsoft MVP - C++ Metal Musings - Rex and my new metal blog "I am working on a project that will convert a FORTRAN code to corresponding C++ code.I am not aware of FORTRAN syntax" ( spotted in the C++/CLI forum ) Re: Accessing the parent's data members Vancouver10-Jun-07 18:01 Vancouver 10-Jun-07 18:01  I tried this already before asking, but it causes an error, when assigning the address of the parent to the pointer. If ctl_MyControl is the member variable of the instance of the subclassed control, and Parent is defined in MyOwnCtl.h as class Parent; then ctl_MyControl.Parent = this; in the parent's OnInitDialog causes error C2440: '=' : cannot convert from 'class CMyOwnDlg *const ' to 'class $S217 *' However, if the pointer is defined (in the globals) as CMyOwnDlg *Parent; then Parent = this; works fine from OnInitDialog. Re: Accessing the parent's data members Christian Graus10-Jun-07 18:16 Christian Graus 10-Jun-07 18:16  Vancouver wrote: ctl_MyControl.Parent = this; This means that ctl_MyControl is not a pointer, which means it won't work, like I said. If ctl_MyControl is a member variable, a forward declaration will only work if it's a pointer to an instance of your control. Christian Graus - Microsoft MVP - C++ Metal Musings - Rex and my new metal blog "I am working on a project that will convert a FORTRAN code to corresponding C++ code.I am not aware of FORTRAN syntax" ( spotted in the C++/CLI forum ) Re: Accessing the parent's data members Vancouver10-Jun-07 18:25 Vancouver 10-Jun-07 18:25  Sorry, I mistyped it in the post. Of course I declared it as a pointer and it created the mentioned error. Re: Accessing the parent's data members Christian Graus10-Jun-07 18:46 Christian Graus 10-Jun-07 18:46  Was the code to set it in the header or the cpp file ? I've done this many times, it's definately the correct way to do things. http://www.google.com.au/search?sourceid=navclient&ie=UTF-8&rlz=1T4ADBS_enAU225AU226&q=C%2b%2b+forward+declare[^] for google hits on the subject of forward declaring. I don't do c++ nowadays, perhaps I'm missing a detail. Christian Graus - Microsoft MVP - C++ Metal Musings - Rex and my new metal blog "I am working on a project that will convert a FORTRAN code to corresponding C++ code.I am not aware of FORTRAN syntax" ( spotted in the C++/CLI forum ) Re: Accessing the parent's data members Vancouver10-Jun-07 19:01 Vancouver 10-Jun-07 19:01  class *Parent; is in CMyOwnCtl.h. If it was not there, I would not have any problem: in the function itself CMyOwnDlg can be used. because both headers are known there (and then John M. Drescher's suggestion works). Re: Accessing the parent's data members Rajkumar R10-Jun-07 19:16 Rajkumar R 10-Jun-07 19:16  When you use forward declaration. The forward declared variable cannot be accessed in the declaration file, since compiler only knows the pointer and allocates the size of pointer when you access it, compiler won't have enough information to do this. ctl_MyControl.Parent = this; Is this statement is in declaration file, if so, use this in a function definition is cpp file. Since the dialog is immediate parent, you know the level of the parent class, you can use john's method (dynamic cast the parent window). Best Regards Raj Re: Accessing the parent's data members John M. Drescher10-Jun-07 17:42 John M. Drescher 10-Jun-07 17:42  One thing you could do is to make *Parent a class member of CMyOwnCtl and pass it in a constructor or a SetParent member. Actually you do not need to store the pointer though as you can always do a GetParent() in the control and DYNAMIC_CAST or (dynamic_cast) the CWnd pointer to CMyOwnDlg. I do this 90% of the time and use dynamic_cast syntax over DYNAMIC_CAST as my programs are compiled with RTTI and I avoid the MFC macros as much as I can. John Re: Accessing the parent's data members Vancouver10-Jun-07 19:07 Vancouver 10-Jun-07 19:07  This appeared to be all right, at least syntactically. However, CMyOwnDlg *Parent = dynamic_cast <CMyOwnDlg *> (GetParent()); in the function of the control caused an error: RTDynamicCast threw an exception. Re: Accessing the parent's data members John M. Drescher11-Jun-07 21:23 John M. Drescher 11-Jun-07 21:23  Did you set the compiler option to enable RTTI (Run time type info)? If not use DYNAMIC_CAST as this will work without the compiler option. John Constructors tom groezer10-Jun-07 11:57 tom groezer 10-Jun-07 11:57  What is the implication of using virtaul constructors?how to acchieve the model of the same even thogh C++ does not have them? Re: Constructors toxcct10-Jun-07 12:04 toxcct 10-Jun-07 12:04  tom groezer wrote: virtaul constructors such a thing doesn't exist... so I don't know where you're taking your questions from, but they're erroneous [VisualCalc][Binary Guide][CommDialogs] | [Forums Guidelines] Re: Constructors Stephen Hewitt11-Jun-07 18:40 Stephen Hewitt 11-Jun-07 18:40  It depends on what you mean. It's true that C++ doesn't support virtual constructors per se, but there is a design pattern called the virtual constructor idiom[^] which may be what the OP is after. Many programmers and designers use the term "virtual constructor" to refer to this idiom and are not talking about literally making constructors virtual. Steve Re: Constructors Rajkumar R10-Jun-07 19:34 Rajkumar R 10-Jun-07 19:34  What is your requirement, If you want to hide the details of Object creation, Refer Factory, builder, .. patterns(Design Patterns) Contructors are required to identify the class whose object is created. Making it virtual is meaning less. Best Regards Raj Re: Constructors Stephen Hewitt11-Jun-07 18:41 Stephen Hewitt 11-Jun-07 18:41  It depends on what you mean. It's true that C++ doesn't support virtual constructors per se, but there is a design pattern called the virtual constructor idiom[^] which may be what the you're after. Many programmers and designers use the term "virtual constructor" to refer to this idiom and are not talking about literally making constructors virtual. Steve What is in-class constant? tom groezer10-Jun-07 11:30 tom groezer 10-Jun-07 11:30  How to use it in C++? Re: What is in-class constant? Mark Salsbery10-Jun-07 11:50 Mark Salsbery 10-Jun-07 11:50  A constant variable is one that can't be changed (at least the compiler won't let you do it directly). In-class means it is a member of a class. For usage, the section "How do I define an in-class constant?" in Bjarne Stroustrup's C++ Style and Technique FAQ[^] may help Mark "Posting a VB.NET question in the C++ forum will end in tears." Chris Maunder C++ gotchas tom groezer10-Jun-07 11:12 tom groezer 10-Jun-07 11:12  why is v[i] = i++; and f(v[i],i++); deemed inappropiate in C++

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