C / C++ / MFC

Christian Graus28-Feb-07 10:49

Christian Graus

28-Feb-07 10:49

You've posted this to every board I have visited. Please don't. If you're using VB, what will you do with an answer in C+ ?

Christian Graus - Microsoft MVP - C++
Metal Musings - Rex and my new metal blog
"I am working on a project that will convert a FORTRAN code to corresponding C++ code.I am not aware of FORTRAN syntax" ( spotted in the C++/CLI forum )

İsmail Durmaz28-Feb-07 10:52

İsmail Durmaz

28-Feb-07 10:52

because it is not important for me, i can change codes into my system
i want to get any idea or solution who knows

Christian Graus28-Feb-07 14:47

Christian Graus

28-Feb-07 14:47

It's important to us that you don't spam the entire site.

Cant slow the program down

Mark Salsbery28-Feb-07 14:26

Mark Salsbery

28-Feb-07 14:26

Christian Graus wrote:
You've posted this to every board I have visited.

Even the PowerPoint board?

"Great job, team. Head back to base for debriefing and cocktails."
(Spottswoode "Team America")

Spartan1628-Feb-07 8:27

28-Feb-07 8:27

I cant get the program to display it appears then dispears very quickly.
someone please help
heres the code:

//Please someone help

#include <iostream>
#include <string>

using namespace std;

class Critter
{
//make following global functions friends of the Critter class
friend void Peek(const Critter& aCritter);
friend ostream& operator<<(ostream& os, const Critter& aCritter);

public:
Critter(const string& name = "");

private:
string m_Name;
};

Critter::Critter(const string& name):
m_Name(name)
{}

void Peek(const Critter& aCritter);
ostream& operator<<(ostream& os, const Critter& aCritter);

int main()
{
Critter crit("Poochie");

cout << "Calling Peek() to access crit's private data member, m_Name: \n";
Peek(crit);

cout << "\nSending crit object to cout with the << operator:\n";
cout << crit;

return 0;
}

//global friend function which can access all of a Critter object's members
void Peek(const Critter& aCritter)
{
cout << aCritter.m_Name << endl;
}

//global friend function which can access all of Critter object's members
//overloads the << operator so you can send a Critter object to cout
ostream& operator<<(ostream& os, const Critter& aCritter)
{
os << "Critter Object - ";
os << "m_Name: " << aCritter.m_Name;
return os;
}

David Crow28-Feb-07 8:31

David Crow

28-Feb-07 8:31

Run it from a command prompt (instead of double-clicking it frm within Windows Explorer).

"Approved Workmen Are Not Ashamed" - 2 Timothy 2:15

"Judge not by the eye but by the heart." - Native American Proverb

Spartan1628-Feb-07 8:37

28-Feb-07 8:37

How would i do that can u show an example??? Please.

David Crow28-Feb-07 8:45

David Crow

28-Feb-07 8:45

Spartan16 wrote:
How would i do that...

It's hard to fathom that you might actually be serious.

Click Start
Click Run
Type cmd
Click OK

Now change to the folder where your program resides and run it from there.

"Approved Workmen Are Not Ashamed" - 2 Timothy 2:15

"Judge not by the eye but by the heart." - Native American Proverb

Spartan1628-Feb-07 8:51

28-Feb-07 8:51

lol of course i know how to run cmd. but in cmd what do i type to run the program thats all i am asking.

David Crow28-Feb-07 8:53

David Crow

28-Feb-07 8:53

Spartan16 wrote:
...in cmd what do i type to run the program...

Whatever the name of your program is.

"Approved Workmen Are Not Ashamed" - 2 Timothy 2:15

"Judge not by the eye but by the heart." - Native American Proverb

Spartan1628-Feb-07 8:55

Fastest way to scale binary images??

28-Feb-07 8:55

Thank u. Sorry i sound so uneducated

pavanbabut28-Feb-07 7:49

pavanbabut

28-Feb-07 7:49

Hi,

I am looking for a fastest way to scale up/down a binary image. I may end up scaling images only in X direction. Is there any easiest/fastest way to do this in VC++?? For now my images are stored in an array (not a two-dimensional array, but just a single strip array(one row after another from the image). Since I am dealing with binary images, I hope I dont need to use interpolation.

The data that I have is the original dimensions of the image and the final dimensions of the image. For example, my original image is 9x9 and my new dimensions are 15x9.

thanks,
-Pavan.

C^hris L^osinger28-Feb-07 8:05

C^hris L^osinger

28-Feb-07 8:05

if you're not limiting your output size to certain whole multiples of the input size, you're going to have to do some interpolation (if you want reasonable-looking output).

but, bi-linear interpolation is pretty easy.

image processing toolkits | batch image processing | blogging

pavanbabut28-Feb-07 8:45

pavanbabut

28-Feb-07 8:45

Any articles on bi-linear interpolation that is easy to understand...

-Pavan

C^hris L^osinger28-Feb-07 9:25

C^hris L^osinger

28-Feb-07 9:25

in 1-D, linear interpolation looks like this:

// ratio of input size to output size
factor1 = inputPoints / outputPoints

// loop over output
for (current=0 to outputPoints-1)
{
  // center of our input pixel is here. it's probably fractional.
  inputPixelLocation = current * factor1

  // get the two pixels on either side of that center point
  input1 = pixel[floor(inputPixelLocation)]
  input2 = pixel[floor(inputPixelLocation) + 1]

  // the fractional part of this tells us how close we are to the left-most source pixel.
  factor2 = fractional_part_of(inputPixelLocation) 

  // average of the two pixels, weighted by factor2
  output = input1 * factor2 + input2 * (1.0 - factor2)
}

in 2D, you pick four pixels: two from the current pixel row (as above) and another two from the row immediately beneath. and then you combine all four with the a two-factor weighted average.

factor1X = inputPointsX / outputPointsX
factor1Y = inputPointsY / outputPointsY

// vertical loop
for (currentY=0 to outputPointsY-1)
{
  // find the vertical factor
  inputPixelLocationY = currentY * factor1Y

  // horizontal loop
  for (currentX=0 to outputPointsX-1)
  {
    // find horizontal factor
    inputPixelLocationX = currentX * factor1X

    floorX = floor(inputPixelLocationX)
    floorY = floor(inputPixelLocationY)

    // get four pixels: X,Y - X+1,Y - X,Y+1, X+1,Y+1
    input1 = pixel[floorX ][floorY]
    input2 = pixel[floorX + 1][floorY]
    input3 = pixel[floorX][floorY + 1]
    input4 = pixel[floorX + 1][floorY + 1]

    // two factors
    factor2X = fractional_part_of(inputPixelLocationX) 
    factor2Y = fractional_part_of(inputPixelLocationY) 

    factor2X_inverse = 1.0 - factor2X 
    factor2Y_inverse = 1.0 - factor2Y 

    // average of the four pixels, weighted by the 2 factor2's
    outval = input1 * factor2X * factor2Y + 
             input2 * factor2X_inverse * factor2Y + 
             input3 * factor2X * factor2Y_inverse + 
             input4 * factor2X_inverse * factor2Y_inverse

    output[currentX][currentY] = outval
  }
}

that's a basic bi-lin algorithm. there's a lot of room there for optimization in general, and even more for monochrome data.

image processing toolkits | batch image processing | blogging

/div>

tabcontrol: highlight tab

pavanbabut28-Feb-07 9:36

pavanbabut

28-Feb-07 9:36

Thanks for the info... will try to implement this as easy as I can..

-Pavan.

aei_totten28-Feb-07 5:57

aei_totten

28-Feb-07 5:57

I added a tab control to my project, but seeing which tab is selected is not really obvious. I would like to highlight the selected tab. How do I go about doing this?

Thanks,
Brandy

Re: tabcontrol: highlight tab

KaЯl28-Feb-07 6:23

KaЯl

28-Feb-07 6:23

Here[^] you go

There are two things that one must get used to or one will find life unendurable: the damages of time and injustices of men

Fold with us! ¤ flickr

Detect SCSI Devices

FoxholeWilly28-Feb-07 5:49

FoxholeWilly

28-Feb-07 5:49

As part of a large application, I need to detect which devices are available on a SCSI bus, some are hard disks, and one or more DTF tape drives.

This example works for finding the hard disks:

hDevice = CreateFile(TEXT("\\\\.\\PhysicalDrive#"), 0, FILE_SHARE_READ | FILE_SHARE_WRITE, NULL,
OPEN_EXISTING, 0, NULL);

but when I use "\\\\.\\Tape#" it does not find the tape drive (SONY GY-8240)

Am I missing something?

Note: # is set in a loop from 0 to 14.

Thanks.

Thread Problem

vibindia28-Feb-07 5:36

vibindia

28-Feb-07 5:36

Hi,

I have created an Workers Thread in my application.
It Enumerates the IP address in the Network.
If i close the Application after the thread is returned.There is no prob;

But if i close the Appliction before the enumerating all the IP Address(B4 Thread function's return is reached). I get Runtime error.

Could i know how to Terminate the Thread form the View file's OnClose(); Cry | :((

VIBIN

"Fool's run away,where angle's fear to tread"

Roger Stoltz28-Feb-07 5:38

Roger Stoltz

28-Feb-07 5:38

Have a look at this excellent article[^].

"It's supposed to be hard, otherwise anybody could do it!" - selfquote
"High speed never compensates for wrong direction!" - unknown

vibindia28-Feb-07 5:46

vibindia

28-Feb-07 5:46

Hi,

I got that article.I will check out that.
I think thats is enough for Solving my problem..... Smile | :)

VIBIN

"Fool's run away,where angle's fear to tread"

led mike28-Feb-07 5:43

led mike

28-Feb-07 5:43

You want to design for this. You basically share data across threads. The worker thread will periodically test the data while the main thread will change the data to indicate that the worker thread should end.

Also JFGI![^]

led mike