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daniel99 wrote: For each design I build on code.
:cracks a smile:
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Hello Daniel,
Like the others, I'm not really sure if I understand you write, but I try to explain what you can do with a "#define". (I'm using VisualStudio)
You can enable/disable a region during design time.
In your case:
#define PropertyStyle
#if PropertyStyle
public bool GetSomething
{
get
{
return somestuffreturningbool_1();
}
}
#else
public bool GetSomething
{
get
{
return somestuffreturningbool_2();
}
}
#endif
If you compile it that way, you get the return value from somestuffreturningbool_1.
Or:
//#define PropertyStyle
... same code
If you compile it that way, you get the return value from somestuffreturningbool_2.
Hope it helps!
All the best,
Martin
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I have some code that creates an image by putting a bunch of images together. If I return the result as a JPEG or GIF it works fine. But when I return it as a BMP it returns a bunch or characters instead of a picture.
Any ideas on why?
The only way to speed up a Macintosh computer is at 9.8 m/sec/sec.
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Can you clarify what you mean by 'return the result'. Are you using a Bitmap object?
myBitmap.Save("bitmap.bmp", System.Drawing.Imaging.ImageFormat.Bmp);
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Yes I am using a Bitmap object.
The wierd part is it works if it is a JPEG or GIF, not BMP...
myBitmap.Save(Response.OutputStream, System.Drawing.Imaging.ImageFormat.Bmp);
The only way to speed up a Macintosh computer is at 9.8 m/sec/sec.
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What object are you returning, to see a 'bunch of characters' ? Why do people ask questions like this and not post the code ? If you write code that returns a Bitmap, you'll get a bitmap. If you're not getting that, we need to see the code to say what's wrong with it.
Christian Graus - Microsoft MVP - C++
Metal Musings - Rex and my new metal blog
"I am working on a project that will convert a FORTRAN code to corresponding C++ code.I am not aware of FORTRAN syntax" ( spotted in the C++/CLI forum )
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Code Removed
-- modified at 20:30 Monday 26th February, 2007
The only way to speed up a Macintosh computer is at 9.8 m/sec/sec.
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OK, it's an ASP.NET question. You should ask those in the ASP.NEt forum, or at least make that clear.
Why on earth would you send a BMP through a web page anyhow, when gif and jpg are smaller ? I would not be surprised in the browser does not support them, I think BMP is a windows format ( it's raw data with a header which I think is Windows specific ).
Christian Graus - Microsoft MVP - C++
Metal Musings - Rex and my new metal blog
"I am working on a project that will convert a FORTRAN code to corresponding C++ code.I am not aware of FORTRAN syntax" ( spotted in the C++/CLI forum )
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I have seen that a way to make dynamic images is to use an aspx page with a Response.OutputStream and then assign that page as the ImageUrl in a Image Component. It works for JPEG and GIF. My problem is transparency. JPEG and GIF output results in a black background.
I guess I could ask, how do I get the background of my outputed JPEG or GIF image to be transparent?
Or do you know another way to make my own image and output it on a custom control?
And I did forget to mention it is a ASP.NET app, so keep that in mind.
The only way to speed up a Macintosh computer is at 9.8 m/sec/sec.
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There certainly is no transparency support in BMP. I believe PNG is the only format that has transparency built in.
Christian Graus - Microsoft MVP - C++
Metal Musings - Rex and my new metal blog
"I am working on a project that will convert a FORTRAN code to corresponding C++ code.I am not aware of FORTRAN syntax" ( spotted in the C++/CLI forum )
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.NET has a method MakeTransparent(Color), when you use that method it simply doesn't draw the pixels with the color passed to MakeTransparent.
I have another idea. How can I pass a Color from one page to another?
The only way to speed up a Macintosh computer is at 9.8 m/sec/sec.
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Ok, I made a variable and it always used the default I set to it since I commented out a line for testing. I uncommented have it works. Those are the errors I love!
The only way to speed up a Macintosh computer is at 9.8 m/sec/sec.
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Hi all,
i have two classes(one for form that i draw on it,
and other class)
so i want to make invalidate in the first class to draw by
onpaint method in the first class
Generator
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Can't be done. Instead, create a delegate between the classes, so the class that forced invalidation either calls a method that calls invalidate in the second class, or passes it's graphics object to the second class for painting. You can't make the event args in the second class contain the graphics object of the first class.
Christian Graus - Microsoft MVP - C++
Metal Musings - Rex and my new metal blog
"I am working on a project that will convert a FORTRAN code to corresponding C++ code.I am not aware of FORTRAN syntax" ( spotted in the C++/CLI forum )
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how can i create like a beep sound, but make it play through the speakers and not the computer's internal speaker? (so, obviously, Console.Beep() is not what i need).
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You can P/Invoke MessageBeep(). The declaration can be found on pinvoke.net, for example.
Regards,
mav
--
Black holes are the places where God divided by 0...
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But those are just system sounds...how can i create my own sound?
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Ok, if the standard beep isn't good enough for you  , you can still use the System.Media.SoundPlayer class.
Regards,
mav
--
Black holes are the places where God divided by 0...
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Again, i don't want to load an external file, i want to CREATE a sound at runtime
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If you said precisely what you want and what you don't want we wouldn't have to guess... 
Anyway, in that case you should start reading about the WAV format. Basically you create a buffer for the audio data, write a WAVEFORMAT (look it up in MSDN) to it and add the samples you want to play. That's the most flexible you can get.
Regards,
mav
--
Black holes are the places where God divided by 0...
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sharpiesharpie wrote: how can i create like a beep sound, but make it play through the speakers and not the computer's internal speaker?
Is this article on a simple beep[^] what you are looking for?
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i have Byte[]
and i want to convert it to image ( using System.Drawing )
how that can be done
thanks
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Just a guess:
using (MemoryStream memoryStream = new MemoryStream(bytearray))
{
Image image = Image.FromStream(memoryStream);
}
"Programming today is a race between software engineers striving to build bigger and better idiot-proof programs, and the Universe trying to produce bigger and better idiots. So far, the Universe is winning." - Rick Cook www.troschuetz.de
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it really works... good guess 
thanks allot
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Hi,
I go through a collection of toolstripmenuitems and if its the correct item, i set it to be checked.
foreach (ToolStripMenuItem sortItemDropDown in sortItem.DropDownItems)
{
if (sortItemDropDown.Name.Equals(tickSortBy))
{
sortItemDropDown.Checked = true;
}
}
The problem is that the sortedItem.DropDownItems has a Seperator in it, thus i get an exception telling me i cant convert a seperator to a menuitem. Is there a work-around ?
Regards,
Gareth.
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