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GeneralRe: Please determine the output Pin
Christian Graus27-Sep-06 18:06
protectorChristian Graus27-Sep-06 18:06 
GeneralRe: Please determine the output Pin
Sushant Duggal27-Sep-06 18:31
Sushant Duggal27-Sep-06 18:31 
GeneralRe: Please determine the output Pin
Sushant Duggal27-Sep-06 18:47
Sushant Duggal27-Sep-06 18:47 
GeneralRe: Please determine the output Pin
Christian Graus27-Sep-06 19:00
protectorChristian Graus27-Sep-06 19:00 
AnswerRe: Please determine the output Pin
Christian Graus27-Sep-06 19:12
protectorChristian Graus27-Sep-06 19:12 
GeneralRe: Please determine the output Pin
Sushant Duggal27-Sep-06 19:38
Sushant Duggal27-Sep-06 19:38 
GeneralRe: Please determine the output Pin
Christian Graus27-Sep-06 19:45
protectorChristian Graus27-Sep-06 19:45 
QuestionRe: Please determine the output [modified] Pin
Sushant Duggal27-Sep-06 21:03
Sushant Duggal27-Sep-06 21:03 
The ++ operator occurs in both languages AFTER x is given it's final <BR>value. The difference is that in Java, the values are by reference, so <BR>the value that x is assigned to, is the value that still has a ++ operator outstanding. so, x gets set to 18. y gets incremented, to 7,<BR> and x also gets incremented, but it's the same x that is 18, not a <BR>copy of x which is 16.


I can understand that in java, the values are by reference. that means X is incremented direectly where it is stored, it sets it to 12 + 6 = 18.

Confusion ..... when the X is going to incremented? and why it is not reflected(X's value is still 18).

Thanks For your Patience,

Sushant Duggal.


-- modified at 3:39 Thursday 28th September, 2006

Sushant Duggal.

AnswerRe: Please determine the output Pin
Nish Nishant28-Sep-06 5:57
sitebuilderNish Nishant28-Sep-06 5:57 
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