Managed C++/CLI

Re: illegal call of non-static member function

15-Aug-05 4:25

I have added reference of COM: "Microsoft DAO 3.6 Object Library"

Object *pLang = S"dbLangGeneral";<br />
Object *pSrc = S".\\Data\\Database.mdb";<br />
Object *pDes = S".\\Data\\Database.com";<br />
dao::DBEngine::ompactDatabase(pSrc->ToString(), pDes->ToString() , pLang, 0, NULL);

I Got "error C2352: 'dao::_DBEngine::CompactDatabase' : illegal call of non-static member function"

How can i correct it.

Christian Graus15-Aug-05 13:24

Christian Graus

15-Aug-05 13:24

Saksida Bojan wrote:
dao::DBEngine::ompactDatabase

Should that read CompactDatabase ?

Saksida Bojan wrote:
I Got "error C2352: 'dao::_DBEngine::CompactDatabase' : illegal call of non-static member function"

The function you're trying to call is not static, and so needs an instance of the class to call it.

Christian Graus - Microsoft MVP - C++

Re: illegal call of non-static member function

Saksida Bojan15-Aug-05 21:42

Re: illegal call of non-static member function

15-Aug-05 21:42

I don't know how to do it. Can you please give an example.

Thanks in advance.

PS: Yes, It Shoud be CompactDatabase.

S. Senthil Kumar16-Aug-05 4:55

S. Senthil Kumar

16-Aug-05 4:55

You need to create an instance of the DBEngine class before calling the CompactDatabase function.

Regards
Senthil
_____________________________
My Blog | My Articles | WinMacro

Thanks

Saksida Bojan16-Aug-05 8:37

16-Aug-05 8:37

Thanks That Worked.

I have found DBEngine And DBEngineClass also exist

Cursor positions

richiemac15-Aug-05 0:15

richiemac

15-Aug-05 0:15

Hi all,

I have a form where I want to set some regions. When the mouse moves over these regions I want the cursor image to change.

My idea is to set up some rectangles and use the mousemove event (somehow) to check against the current position of the cursor.

I just want to know what properties do I need to use for this and is there a better way.

I suppose I'm basically asking how I can check if the mouse is over a certain area of a form.

Thanks in advance
Rich

Saksida Bojan15-Aug-05 4:40

15-Aug-05 4:40

Try override event MouseMove to get mouse position.

Or use MouseEnter, MouseHover or MouseLeave event to evulate if mouse is in or on certian controls.

richiemac15-Aug-05 22:18

richiemac

15-Aug-05 22:18

So I've got a rectangle that defines an area. How do I then check whether the mouse position is in that area. I've tried using,

<br />
myRec.Contains ( this->MousePosition );<br />

but it doesn't seem to use the whole area. It only seems to work at a certain spot.

I'm obviously misunderstanding something.

Saksida Bojan16-Aug-05 0:49

16-Aug-05 0:49

I have found the problem. MousePosition gets you position, point 0,0 top left of the creen, not the form.

There is work around this problem.

#include <windows.h>			//Win32 header

RECT *rect = new RECT();		//Create Rectangle Win32 Syntax
HWND hWnd = GetActiveWindow();		//Gets Handle of current Form
GetWindowRect(hWnd, rect);		//Gets Position of the form

// Get Mouse position and calculate to form cordinate
int x = this->MousePosition.X - rect->left - 4; 
int y = this->MousePosition.Y - rect->top - 30;

//Check if the mouse is insade the rectangle
if (myRec->Contains(x, y) == true)
	label1->Text = S"True";
else
	label1->Text = S"False";

ps: Overridng Those event like MouseEnter, and other i have posted will work only if it is a control. I have reread and now i anderstand what you have ment.

richiemac16-Aug-05 2:54

richiemac

16-Aug-05 2:54

Thanks for the help.

I'm having trouble firstly with the drawing or placement of the rectangle. It's not in the correct place - for instance, if I draw a picturebox with the same coordinates they are in different positions on the screen. Very confused as to why this is - so I assume from your previous post they are being drawn with different relative positions.

So I've tried to use the work around you posted but if I include the windows header I have a lot of problems with my message boxes and some other components that I need. Is there no way of doing the same thing without the need for the win32 api.

Saksida Bojan16-Aug-05 8:33

unsigned char (3 bytes) to long

16-Aug-05 8:33

Sorry, I can't get that error. Try to make another unmanaget class with old syntax:

#ifndef _MPOINT_H_
#define _MPOINT_H_
#include <Windows.h>

struct pointMData
{
	int x;
	int y;
};

class MPoint
{
public:
	MPoint(void){}
	~MPoint(void){}

	void GetPoint(pointMData *pData)
	{
		RECT *rect = new RECT();
		HWND hWnd = GetActiveWindow();
		GetWindowRect(hWnd, rect);
		pData->x = rect->left;
		pData->y = rect->top;

		return;
	}

};
#endif

This is unmanaged class, so i have created pointMData for retreaving, because i have a problem using Rectangle in umanaged class. If this doesn't work, then try Creating Win32 DLL.

quote:
Is there no way of doing the same thing without the need for the win32 api.

I couldn't find in framework for this workaround, so i used Win32 api. I don't know if exist.

ps: i hope this works

Anonymous14-Aug-05 16:50

Re: unsigned char (3 bytes) to long

14-Aug-05 16:50

Hello,

I'am new to c++ and i want to convert 3 bytes unsigned character to 4 bytes long.

unsigned char UniqueID[3];
long converted;
converted=??;

How can I convert this?

Thanks.

Christian Graus14-Aug-05 17:11

Christian Graus

14-Aug-05 17:11

What do you expect to do ? What do the three bytes contain ? There's no obvious conversion here, that I can see. If it's a number, then you need to know what significance each byte has. If it's just left to right, this should do it

long converted = UniqueID[0] + (UniqueID[1] << 8) + (UniqueID[2] << 16);

Christian Graus - Microsoft MVP - C++

Re: unsigned char (3 bytes) to long

Anonymous14-Aug-05 20:44

Event sink on Exchange via MAPI/Exchange SDK

14-Aug-05 20:44

Thanks, it does what i need.

More Power to you.

Client Server in C/C++

gauravz13-Aug-05 23:21

gauravz

13-Aug-05 23:21

Dudes...

I want a code in either c or c++ that enables SERVER to multiple client communication. I also want the libraries required to do so.

GAURAV ZIBBU

Member 50520613-Aug-05 2:34

Member 505206

13-Aug-05 2:34

Hello.

Please suggest how to create an Event Sink registation for Exchange Server Folder on some COM+ component via MAPI and/or Exchange SDK.
Please do not suggest to do this using CDO, coz CDO is not alowed in my project.

Please give a code example or a link to the article.

call by reference with reference

Anonymous12-Aug-05 2:45

12-Aug-05 2:45

Is it possible to produce a code something like the one below, or do I have to change the changeValue functions parameter to (int *& valueReference)?

int value1 = 1;<br />
int value2 = 2;<br />
<br />
void changeValue(int && valueReference)<br />
{<br />
   valueReference = value2;<br />
}<br />
<br />
void main()<br />
{<br />
   int & valueReference = value1;<br />
   changeValue(valueReference);<br />
   cout << valueReference;		// "2"<br />
}

raytotti5712-Aug-05 3:41

raytotti57

12-Aug-05 3:41

I suppose this question should be in the C++ forum
Code is OK if you change
void changeValue(int && valueReference)
to
void changeValue(int & valueReference)

&& is the AND operator, int *& is wrong. It may be best to start off getting to grips with C pointers before mixing them with C++ references.

For example, if your code was :-

int value1 = 1;
int value2 = 2;
void changeValue(int *p)
{
p = &value2;
}
int _tmain()
{
int valueReference = value1;
changeValue(&valueReference);
cout << value1; // 1 instead of 2 this time.
}

then valueReference would not be changed, only the local copy of p in changeValue() is set to point to value1.

Saksida Bojan13-Aug-05 1:41

13-Aug-05 1:41

quote:
int valueReference = value1;
changeValue(&valueReference);
cout << value1; // 1 instead of 2 this time.

it shoud be:
cout << valueReference; // valueReference instead value 1

raytotti5714-Aug-05 22:46

raytotti57

14-Aug-05 22:46

No it shouldn't be cout << valueReference
You miss my point completely, I wanted to show that value1 wasn't changed because this time a pointer was passed to changeValue. Pointers are passed by value, whereas references are passed byref, hence the different result when a pointer is used instead of a reference.

Saksida Bojan15-Aug-05 4:37

15-Aug-05 4:37

then change

this:

int valueReference = value1;<br />
changeValue(&valueReference);<br />
<br />
to:<br />
<br />
int *valueReference = &value1;<br />
changeValue(valueReference);

value1 didn't change, because you didn't pass address of value1 to pointer valueReference.

Anonymous13-Aug-05 5:29

13-Aug-05 5:29

Tanks for your answer, my question was a bit unclear. What I’m really is looking for is a way to modify the referee itself not the “thing” it refers to, so I believe I have to do something like this.

<br />
const int value1 = 1;<br />
const int value2 = 2;<br />
<br />
void changeReference(const int *& p)<br />
{<br />
   p = &value2;<br />
}<br />
<br />
void main()<br />
{<br />
   const int * valueReference = &value1;<br />
   changeReference(valueReference);<br />
   std::cout << value1 << ", " << value2 << ", " << *valueReference;<br />
}<br />

Actually I felt quite familiarly with references in C++, until I started thinking about this particular task.