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i don't think i explained my problem very well. here is the deal:
I want to start debugging my code, so i did as you said i pressed F9
to set my break points, then i pressed F5.
when the program started running it a small DOS window popped on the screen asking me for input.
ok now i cannot enter all the input from the keyboard because it's abig file
;
do you know how to redirect it to go read from that file
instead of the keyboard?
thank you
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My answer remains the same - if you use an ifstream instead of cin, you can leave the rest of your code the same and it will read from the file instead of the keyboard. Isn't that what you want it to do ?
Christian
I have come to clean zee pooollll. - Michael Martin Dec 30, 2001
Picture the daffodil. And while you do that, I'll be over here going through your stuff.
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i don't think i explained my problem very well. here is the deal:
I want to start debugging my code, so i did as you said i pressed F9
to set my break points, then i pressed F5.
when the program started running it a small DOS window popped on the screen asking me for input.
ok now i cannot enter all the input from the keyboard because it's abig file
;
do you know how to redirect it to go read from that file
instead of the keyboard?
thank you
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Project settings->Debug->Program arguments:
<< name_of_your_file
Joaquín M López Muñoz
Telefónica, Investigación y Desarrollo
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are arrays passed by reference or copy
if they are passed by copy, can you tell me how would you pass an array of char by reference?
thank you
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Are you talking about this?
char szArray [10];
MyFunction (szArray);
In arrays like this, it passes the array by the pointer to the start of an array.
Now, if you are talking about STL arrays such as....
int MyFunction (std::vector <int> &vArray)
{
...
}
main ()
{
std::vector <int> v;
MyFunction (v);
}
Now if you leave off the "&" symbol in the function definition, it will pass the array by making a copy. The "&" will cause it to be passed by reference.
Tim Smith
Descartes Systems Sciences, Inc.
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Hi,
Imagine you have two classes with the following headers:
//***************** Class CFirstClass ****************
#include "SecondClass.h"
class CFirstClass
{
public:
CFirstClass();
virtual ~CFirstClass();
CSecondClass* pointer;
};
//***************** Class CSecondClass ****************
#include "FirstClass.h"
class CSecondClass
{
public:
CSecondClass();
virtual ~CSecondClass();
CFirstClass* pointer;
};
We have a situation of a circular reference and I don't know to handle that problem. I tried with a forwarding instead of '#include "SecondClass.h"', but I get the error: 'use of undefined type 'CSecondClass'' !!!
My concret problem is much more complex but I think I can summarize it with the above description. Does someone know how to solve this easily? (without building the second class into the first one)
Thanks for your help 
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Ok, the simple solution is that you can add.
class CSecondClass;
To the start of FirstClass.h. This will at least allow you to specify pointers or references to the class in CFirstClass. However, you won't actually be able to do any operations on them.
If you have to do operations on the classes, then you will have to remove the inline routines from the class definition.
Tim Smith
Descartes Systems Sciences, Inc.
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Thanks Tim,
I already tried the forwarding with 'class CSecondClass', but since I need to do some operations on the pointers, I get the error 'use of undefined type 'CSecondClass''.
I don't use the keyword 'inline' at all and I don't put any function body in the header file. What is wrong??
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Even though the compiler doesn't have to generate code when it parses that inline function, it still has to have the class definied in order to parse the function.
I have always had to move the offending inline functions out of the class definition and place them in the CPP file or in an .inl file that is included after both class definitions have been included.
Tim Smith
Descartes Systems Sciences, Inc.
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It's working now, thanks
Best regards
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I forgot to say thank YOU
so THANKS
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First, try using a debugger, it really makes finding bugs a LOT easier.
Next, check the code:
else
mi = mi;
When you get a match, lo and hi are not getting changed and thus you test the same index over and over again. Instead of "mi=mi", you should have a break statement there to get you out of the loop.
Tim Smith
Descartes Systems Sciences, Inc.
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class A{
public:
int m_var;
A(){
m_var=0;
};
}
class B{
public:
A m_var2; //I want to know where the class A's struct function can be execute? thanks!
}
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The constructor is called before B's constructor, so if it took an argument, you could not do this:
class A{
public:
A(int n){ m_n = n;};
etc.....
class B{
public:
A m_var2;
A()
{
m_var2(7);
}
You'd need to do this in your cpp file:
A::A() : m_var2(7)
{
}
Christian
I have come to clean zee pooollll. - Michael Martin Dec 30, 2001
Picture the daffodil. And while you do that, I'll be over here going through your stuff.
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the Server end send 3 times, while one recv in Client CAsyncSocket will get all 3 packets, why?
one is the other who absorbs the thoughts of others
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Sounds like you are using UDP. Since UDP is packet based instead of stream like TCP, a recv will return only 1 packet at a time.
Tim Smith
Descartes Systems Sciences, Inc.
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no, i am using TCP
the snippet is here
BOOL bOK=pSock->Create();
if(bOK)
{
pSock->AsyncSelect(FD_READ | FD_WRITE | FD_CLOSE | FD_CONNECT | FD_OOB);
retcode=pSock->Connect(m_host,m_port) ;
one is the other who absorbs the thoughts of others
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TCP is a stream based protocol, there's no relation between the number of send() calls at one end of connection and recv() calls at the other end. The network is free to split or merge "packets" as long as all bytes get transmitted and the ordering stays correct.
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when i used the class, it recves 3 packets all in one buffer, for example:
if the server send 1) "aaa" 2)"bbb" 3) "ccc" each time,
then the client should first recv "aaa" when recv next time it should be "bbb" then "ccc".
but in my program, it recves "aaabbbccc" in the recv buffer if the buffer large enough to hold them.
so I suppose the class has some problems.
which when workes properly should recv once the packet arrives.
if one server sends 3 times, then another client should recv 3 times accordingly.
one is the other who absorbs the thoughts of others
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The class is working fine. As markuk pointed out, TCP/IP is a stream based protocol, and not packet based.
In practical terms, what this means is that you will not receive packets in the client but bytes. Theoretically, in your example you could even receive 1 byte at a time (agreed that it is unlikely), but by calling recv repeatedly you will eventually receive all of the bytes that you sent, and in the same order.
So, whether the server sends "aaa" followed by "bbb" followed by "ccc", TCP/IP will treat it exactly the same as if it had sent each letter individually as "a","a","a","b","b","b","c","c","c" or even all together as "aaabbbccc". These are NOT indivdual packets but just bytes within the stream.
What you need, as a very simple solution, is to place a 'framing' character within the stream that indicates the end of each individual message. For example, write a zero into the stream after each message. You will have to modify the client to break the stream back into messages by scanning for these zero bytes. Don't forget that TCP/IP will only give the client the part of the message that has so far been received - sometimes you will have to wait for the zero byte to arrive.
Hope this helps.... Good luck with your code 
Dhar
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I tend to treat a TCP stream just like you treat a record/segment-based file. The stream is a series of segments, each segment should contain a header on it.
The segment header contains information about the segment you are reading -- most importantly the size of the segment. I also tend to mark each header with a 'signature' marker too.
struct segmentHeader
{
WORD m_Signature;
WORD m_SegmentSize;
}
So, as you read the incoming TCP stream, you read a chunk of data (which may be a partial segment, or a bunch of segments) and given what you know about your stream format, you can act accordingly.
What am I trying to say here -- well, the gist is this: Treat a TCP connection just like a flakey file connection. Make sure that the data which you feed into the stream has a defined 'format' which can be recognized at the other end of the connection.
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k here is my problem
print a table of decimal, binary, octal, and hexadecimal equivalents
this is supposed to be programmed in c not c++
graceful gal
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Why does it need to be in C ? IOStreams would do this for you pretty much for free. Is it an assignment ?
I believe sprintf allows you to specify what base a number is, I'm guessing that's what you should use.
Christian
I have come to clean zee pooollll. - Michael Martin Dec 30, 2001
Picture the daffodil. And while you do that, I'll be over here going through your stuff.
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Are you supposed to do the coversion and write a routine yourself?
because you can use printf which is in the C runtine library. It has conversions for all but binary, and that is simple enough.
Construct your string like this:
char string[100];
int x = 16;
printf(string, "decimal = %d, octal = %o, hexidecimal = %x", d, d, d);
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