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(VC6.0, Excel 2000)
Range range;
Borders borders;
range = sheet.GetRange(COleVariant("A1"), COleVariant("L6"));
borders = range.GetBorders();
borders.SetLineStyle(COleVariant((short)1));
This sample is applied to all cells ..
but I want only outline
plese help me.... I want reference source...
reply to: lgs99@dreamwiz.com
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Can you please advise how can we find the CPU utizilation of a particuar process or application running in WIN 98/ME OS..
Thanks in advance..
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I was wondering if anyone had it coded or if someone could get me started
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I'm sure this has been plenty of people's homework before it was yours. We tend to prefer that you start yourself ( thinking about it first is the most important step in coding ), and then we'll help if you get stuck.
Christian Graus - Microsoft MVP - C++
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thats the problem, I need help getting started.
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We are using DAO in our application for db support. One of our customers is looking for a server based deployment WITHOUT client installation of DAO, MDAC or whatever.
Is there a way to do this? It's ok, if we have to recode into something more modern than DAO.
Thanks,
-- Harald
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I've looked around trying to find this information, but there's nothing I can find that fits my situation.
I have two separate classes: Print and PropertySheet that are part of a larger program. I didn't write the code for either one and making any radical changes is out.
All I need to do is add a function to the PropertySheet class that will access the Print class and print out certain information obtained from PropertySheet.
Here's the problem: All of the print functions in Print (such as starting a new document, starting a new page, etc) are virtual functions and I can't access them from the PropertySheet class. I've never cared for vf's and haven't worked with them or used them before, so I'm lost on how to do this.
Here's the question: How can I access those virtual functions in Print from PropertySheet without re-writing the program (I just want to add the code to print in the PropertySheet class)?
I apologize if this has been addressed before, but, as I said, I couldn't find anything for this situation.
I appreciate any help and say thank you in advance anyone that responds.
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If you can't access them, that probably means they are protected or private, not virtual, necessarily.
If they are protected, derive a class from Print to gain access. Make sure this is the right thing to do, they are probably protected for a reason.
bcemick wrote:
I've never cared for vf's
Why - do you hate object orientation ?
Is it possible to put code that defines the interaction between these two objects into a third class, so that they don't become tightly coupled ?
Christian Graus - Microsoft MVP - C++
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The functions I need to access are public and declared as virtual. That's the first thing I checked.
public:<br />
UINT virtual NewDocument();
It's not that I hate object orientation; I've just never understood the point of virtual functions. I don't understand why you would want to use them.
Christian Graus wrote:
Is it possible to put code that defines the interaction between these two objects into a third class, so that they don't become tightly coupled ?
Not at this time, although that is a possibility later on. For right now, though, I have to get it working this way.
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What do you mean by: I can't access them ? Compilation error/warning ? Failing assertion ? Crash ?
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My apologies; I should have been clearer on that point.
When I click on the Print button on the property sheet, it gives me an access violation (Error code: 5) when I'm in debug mode.
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That's not a problem of virtual, private nor public function. Access violation means you violated the memory you accessed, i.e. address of memory wasn't valid.
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Have you placed any breakpoints to determine exactly where the access violation occurs (When you try to call the function, or inside the function...may trying to manipulate another object that isn't there anymore). How does this Print Object get instantiated?
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bcemick wrote:
Not at this time, although that is a possibility later on. For right now, though, I have to get it working this way.
It's NEVER a good idea to 'do it this way for now and change to a good design later'. I suggest you stop coding and read a book called 'Code Complete'. Seriously.
If the function is not pure virtual ( has no body for you to call anyhow ), I don't see why you can't call it.
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Plz tell me about an api that enlists the status of NIC?( keyboard ,Hard disk and RAM)
Wheather they are installed or not ? Plz also provide its example
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Status is a vague term but perhaps the IP helper API is what you are after. See here for starters.
"Ideas are a dime a dozen. People who put them into action are priceless." - Unknown
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How can we get the list of applications runned by a particular user?
like MS Word, MS powerpoint, notepad used by administrator and also provide examples. Plz help me out pals
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Hey all,
I'm kind of lost here, I want to listen to a file-creation event in my computer.
Not that simple I know but according to the few documents on the web I understand there is an API function (ShellNotifyRegister) that suppose to solve my problem
(you can check: http://www.geocities.com/SiliconValley/4942/notify.html to learn about it)
Anyway, I have the known error:
unresolved external symbol "void * __stdcall SHChangeNotifyRegister..."
in the linking phase..
Does anyone know how to solve it..?
Thanks.
RoyRose78
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You might also want to check out ReadDirectoryChangesW() and FindFirstChangeNotification().
"Ideas are a dime a dozen. People who put them into action are priceless." - Unknown
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I have put this question before but it was misunderstood.
I need to declare a pointer to MFC class CMyView in CMyDialog but including myview.h in mydialog.h leads to errors (propably because mydialog.h is also included in myview.h).
Any solutions ?
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Do not include myview.h in mydialog.h.
Put the following line right before your class definition for CMyDialog:
class CMyView;
And include myview.h in your cpp file after the include for mydialog.h.
John
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Use forward declaration of a class. For example:
class CMyView;<br />
class CMyDialog<br />
{<br />
CMyView *m_pView;<br />
};<br />
.<br />
.<br />
.<br />
class CMyView<br />
{<br />
};
That works.
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Do you really need to declare a pointer to CMyView or will a pointer to a CView suffice? Remember, you can always cast the pointer to a CMyView* in MyDialog.cpp.
/ravi
My new year's resolution: 2048 x 1536
Home | Articles | Freeware | Music
ravib@ravib.com
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