C# Discussion Boards - CodeProject

Re: Convert -> Long Integer to Char??

11-Aug-04 13:36

In C# you can do:
long value = ...;
char[] chars = value.ToString().ToCharArray();

that is if you want char array for 123 to hold '1', '2', '3'

Anonymous11-Aug-04 15:06

Anonymous

11-Aug-04 15:06

well, he means byte (8), not char (16)

Re: Convert -> Long Integer to Char??

Werdna11-Aug-04 16:02

Does C# have the C++ equivalent of a friend class?

11-Aug-04 16:02

He said character array, not byte array.

Joe Woodbury11-Aug-04 11:53

Joe Woodbury

11-Aug-04 11:53

Does C# have the C++ equivalent of a friend class?

I have a class where I want to prevent all by one class (in the assembly) from calling certain methods. In C++ I'd declare them protected and then make that one class a friend. Am I out of luck with C# as I suspect?

Anyone who thinks he has a better idea of what's good for people than people do is a swine.
- P.J. O'Rourke

Re: Does C# have the C++ equivalent of a friend class?

Christian Graus11-Aug-04 12:18

Christian Graus

11-Aug-04 12:18

Sadly no, and I was only lamenting the fact last night. Remember, C# is also supposed to attract VB programmers, so a lot of things that can be useful for a good programmer are missing because they are a danger to idiots.

In my case, I wrap an event in a class, and I wanted to only allow the class that sends events to be able to construct them, so that they were then unable to be modifed by clients. I can make it so a client must create a new event, they cannot modify the one they have, but I cannot hide the constructor.

Christian

I have drunk the cool-aid and found it wan and bitter. - Chris Maunder

Re: Does C# have the C++ equivalent of a friend class?

Werdna11-Aug-04 13:38

Re: Does C# have the C++ equivalent of a friend class?

11-Aug-04 13:38

I came across of this few times too.
Best thing I could come up with was to inherit:
class A
{
protected int x;
}

class ToolsForA : A
{
public int DoSomethingWithX(A a)
{
... can access a's protected members here...
}
}

Daniel Turini12-Aug-04 2:32

Daniel Turini

12-Aug-04 2:32

The only way of doing something similar to C++ friend classes is by isolating your classes in an assembly (e.g., a DLL), and use them as 'internal', which makes a member public only to an assembly.

Yes, even I am blogging now!

Re: Does C# have the C++ equivalent of a friend class?

eggie512-Aug-04 7:22

eggie5

12-Aug-04 7:22

I think it's internal.

/\ |_ E X E GG

Printer Properties Dialog

Werdna11-Aug-04 11:07

how to jump from 'for' statment

11-Aug-04 11:07

Does anyone know how to display printer properties dialog?
It's the one that show when you click "Properties" from PrintDialog next to
dropdown with printer names.

I have printer name and need to display it's properties dialog without
showing PrintDialog or PageSetupDialog

Adel83k11-Aug-04 10:26

Adel83k

11-Aug-04 10:26

i have a lines of code just like the following and i whould like to jump after checking a specified condition and incressing the i ... somthing like that ...

<br />
for(int i=0;i<=10;i++)<br />
{<br />
    //<br />
    // some code..<br />
    //<br />
    if(ok)<br />
       // here if true i wanna jump and re enter<br />
       // the 'for' but with value   of i++<br />
<br />
    //<br />
    // codes will only excute if ok=false;<br />
    //<br />
<br />
}<br />

how can i do something like that...

ADEL K Khalil

Re: how to jump from 'for' statment

Michael P Butler11-Aug-04 10:51

Michael P Butler

11-Aug-04 10:51

I think you want the continue keyword.

Michael

CP Blog [^]

Re: how to jump from 'for' statment

Nick Parker11-Aug-04 11:14

Nick Parker

11-Aug-04 11:14

You are correct.

- Nick Parker
My Blog | My Articles

Open-files-problem

Member 80940911-Aug-04 7:57

11-Aug-04 7:57

Hi!

I've got a problem and would be thankful for some help!

I can't open more than approximately 200-300 files.
When I have chosen the files and pressed OK this row throws a System.InvalidOperationException.

if( _openFileDialog.ShowDialog() == DialogResult.OK )
{
...

Does anyone know what I'm doing wrong?

Thanks!
Erik

sreejith ss nair11-Aug-04 8:22

sreejith ss nair

11-Aug-04 8:22

hi,
Tell me how you select more than a file using OpenFileDialog class. Is it possible to show me that code. I need to know how did you code that. OMG | :OMG:

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S r e e j i t h N a i r
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Nick Parker11-Aug-04 9:36

Nick Parker

11-Aug-04 9:36

You can do this by simply setting the Multiselect property of your OpenFileDialog instance to true.

- Nick Parker
My Blog | My Articles

Member 80940911-Aug-04 10:14

11-Aug-04 10:14

Hi!
Sure, here's the code:

_openFileDialog.Multiselect = true;

if( _openFileDialog.ShowDialog() == DialogResult.OK )
{
string[] keys = _openFileDialog.FileNames;
...

/Erik

Dave Kreskowiak11-Aug-04 10:39

Dave Kreskowiak

11-Aug-04 10:39

Don't read much .NET class documentation, do you? Set the Multiselect property of the OpenFileDialog object to true before you call ShowDialog.

RageInTheMachine9532
"...a pungent, ghastly, stinky piece of cheese!" -- The Roaming Gnome

sreejith ss nair11-Aug-04 16:52

sreejith ss nair

11-Aug-04 16:52

Hi,
You wrote >> Don't read much .NET class documentation, do you?

What you mean by this ?
OMG | :OMG:

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S r e e j i t h N a i r
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Dave Kreskowiak12-Aug-04 0:24

Dave Kreskowiak

12-Aug-04 0:24

It took me all of 5 seconds to find this answer ... it was pathetically easy to find! Doing research to solve your own problems is a very important skill that you MUST have in this business in order to survive, advance your career, and most importantly, LEARN!

The only reason you didn't find this one was because you didn't even try and find it in the docs for the OpenFileDialog class. Please don't tell me this was your "level best" attempt at solving your own problem.

RageInTheMachine9532
"...a pungent, ghastly, stinky piece of cheese!" -- The Roaming Gnome

sreejith ss nair12-Aug-04 1:13

sreejith ss nair

12-Aug-04 1:13

hi,
I won't say it's my level best. But you need to know one painful reality that i am not the founder of any language which we are dealing here(eg. C#). Frown | :(

It may very easy for you. But don't think it is easy for others. This point doesn't mean that you are altimate for all. You can ask yourself that how much you know and how much you need to know.

I politly ask that submitter to show the code.Now i know it is a matter of property.
And next thing is how much i want to cover to fix a problem is purly depend upon me and the depth of a problem.

I never feel hesitation to ask any doubts which is unknown for me.

I don't know what's wrong with you if i ask some code to that queary submitter. Mad | :mad:

So my word to you is , Dear friend Blush | :O

You can critisize me. Provided it must be technical not other.

Blush | :O

See for past couple of day's i am trying to figureout one problem. Is it possible for you to help out ? Blush | :O

.

**************************
S r e e j i t h N a i r
**************************

Nick Parker11-Aug-04 9:33

Nick Parker

11-Aug-04 9:33

I haven't found the exact number that is allowed however your best bet right now would be to wrap the call in a try catch block, it is throwing a InvalidOperationException exception.

DialogResult dr;
try
{
    dr = open.ShowDialog();
    if(dr == DialogResult.OK)
    {

        string[] files = open.FileNames;
        if(files != null)
        {
            foreach(string file in files)
            {
                box.Items.Add(file);
            }
        }
    }
}
catch(InvalidOperationException ex)
{
    MessageBox.Show(ex.ToString());
}

- Nick Parker
My Blog | My Articles

Member 80940911-Aug-04 10:25

11-Aug-04 10:25

Hi!

Thanks for the answer!

I've allread done the try, catch thing.
The problem is that i want my program to be able to open more than 200-300(or whatever it is) files.

Is it not possible to open that many files in another way?

Erik

Dave Kreskowiak11-Aug-04 10:44

Dave Kreskowiak

11-Aug-04 10:44

A quick search on MSDN found this[^] KB artcile on the problem. Believe it or not, this behavior is by design! You can't select more than 200 filenames using the OpenFileDialog class. You would have to write your own dialog to get around this "feature".

RageInTheMachine9532
"...a pungent, ghastly, stinky piece of cheese!" -- The Roaming Gnome

Member 80940911-Aug-04 10:52