Comments by sachin.vishwa90 (Top 47 by date)

hi, that can easily be done too. all you have to do is select the path of those images as well in your select statement as below.
select new
{
c.id,
c.Author,
c.BlogTitle,
c.BlogDescription,
c.ImagePath
}).OrderByDescending(d => d.id)
and then bind this path to the src tag in the string.
sb.Append(string.Format("....<img src='{3}' .....",x.Author, x.BlogTitle,x.BlogDescription,x.ImagePath));
hope that helps. may be you have to check the path of image, whether it is relative or absolute path.

you have used linq statement to select the records from database. so how this linq works is it, whatever you write here in c# code it internally creates a sql statement and when you write .ToList() then it actually fires the sql statement. in earlier case this statement was created but not executed. as soon as you wrote .ToList() it executed the query and brought you data.
for readmore i will post soon.

lol, i was about to reply the same, but do you know why you have to use .ToList there?

it is possible, if you are using cookies and javascript.

can you show us what the final html rendered in browser?

inform me too, if you find any simpler one. best of luck

you can do that by adding some header in your response, basically you have to append something unique in your response and your javascript code should keep on looking for that unique thing in your response and as soon as it finds do the UI changes.
are you facing any issue using cookie?

i thing you didn't get the question properly. applicant should not be able to perform activity on browser while code is processing on server side. it means show the loader or disable the button when the postback has happened and hide or enable the button when postback completes(when browser received the response)

how frequent does your data in listview changes? does your list view shows only name?

best reply to such questions

http://stackoverflow.com/questions/6365255/jquery-onclick-event-for-li-tags
to bind the events on list

http://stackoverflow.com/questions/10517315/checking-if-all-form-inputs-are-empty-with-jquery
above link to check all the inputbox are empty or not

if you use this code as it is it will not work.
this is a kind of algorithm. you have to be very precise with your syntax

after several call with non-technical customer care guys. i finally solved this. Now email are shooting like bullet.

I wish they hire few skilled technical peoples to help. i had spend my good plenty of hours talking to them which went useless.

as advised try to put the outcome html in div and keep your content there only.

i believe you have this button on the same page

after click of this button you want the
partial view to appear in modalpopup.
and you have given the partial view code too.

if that is the case in in the success method you have to invoke only the modal function. I reckon you don't need to update the modal
try removing the below code
// refreshes partial view
$('#modalMarkup').html(result);

and return false;

also you will have to use $scope.apply function after you update the http://jimhoskins.com/2012/12/17/angularjs-and-apply.html refer this.

$('#modalMarkup').html(result);
$('#modalMarkup').modal('show');
$scope.apply();

are you getting any error or exception?

code please?

have you tried doing anything?

what have you tried?

you have asked more question than the one who has posted this question :P

is this script running after the element generated or is it in your section?
if it is in head section and try to put script at bottom of your page.
you can try jquery syntax too. first you have to see what is the Id of element and what is the Id in your document.getElementById(..).

have you checked what is value in the hidden field control in your html view?
may be you will have to use Bind instead of Eval.

did you check if you are getting value from first gridview? is your ADO code returning you proper data?
And it is preferable to use updatepanel for such scenarios. other wise changes will happen and pageload event will reset the things again, due to which you will not see the new changes.

There are few steps which you have to check.
1)put debugger in your javascript code where you are making an ajax call, check you are getting appropriate data in your script.
2)Put debugger in your action method and check you are getting appropriate data in your action method.
3) Make sure you are returning the object which is needed in your view
ex return Json(responseObject,JsonRequestBehavior.AllowGet); or JsonResult(responseObject,JsonRequestBehavior.AllowGet);
so key is debug your code and you will get the proper answer why it is giving you 500 error.

good question

hi, Page Load event will occur each and every time, whenever postback happens. However you can avoid the entire page load by having Update Panel in your aspx pages.
try to drill down the update panel functionality and use that in your aspx page.
Are you purposely want to avoid the pageload?

http://ajax.net-tutorials.com/controls/updatepanel-control/

you can keep it very simple by having viewModel, which will consist of all the property needed in your view, this will also include the properties which you want on your post back.
check below link it will definitely help you
https://www.aspsnippets.com/Articles/Bind-Populate-DropDownList-from-database-using-Model-in-ASPNet-MVC-Razor.aspx

hey chap, this is one of the solution which would definitely help him.

you know you can debug the view as well. now you need to observe what is the value in your model.P_CategoryID, because the same value will be posted from your view. And one more thing you will observe in your code while inserting value in your table you are using following,
CategoryAdminPanel cat = new CategoryAdminPanel(); //create new object
cmd.Parameters.AddWithValue("@category", cat.Cat_ID); // putting value from cat object, since it doesnot have any value with it.

where as you should be picking categoryId from your product model as product.P_CatedoryID;
check if that works.

have you mentioned the server address in your connection string?

you need to check what is value in the cat.Cat_ID when your model is posted. i suspect that the value in cat.Cat_ID is not there is your dbo.Catagories table. thats why you are getting this error.
if that is the case then your model is not posting proper value from view. That is the problem here.
for more clarity post your view's code as well

you are making your life hard, you can use existing bootstrap framework for designing you application. if you have application which is already designed then go for table approach.

db.users.aggregate([{$match:{"_id":"yourUserId"}},{$unwind:"$roles"},{$project:{"$roleName._Id":1}},{$lookup:{from:"userRole",localField:"_id",foreignField:"_id",as:"userPermissions"}}])

can you try this query?

hi, That query was just an skeleton to show you for join the two document and pass the result to next operator, may be you will have to use $unwind operator after join.
check the link which was shared in my solution. by the time i will check data posted by you.

mark it solved

I will use that, thanks for guiding me. cheers

for getting the value it seems you have to generate own legand template by using
"legend.labels.generateLabels" function. This function will return the label html. in that HTML you can have your custom attribute with desired value.
After that on click function -> legantItem you can read the custom attribute value.
This is what i can suggest. Give it a try

you don't need to change the awesome grid script, in fact, you have to use the functionality given by awesome grid. this change will be on the view only. you can never show the progress from controller until and unless you are hitting the controller action again and again to update the view.

instead of converting this to array you can convert it to list " .ToList() "

Reason for my vote of 5 \n the code is simple with complex effect

Reason for my vote of 5 \n this topic is explained so easily. thanx alot bro