C#

rowdykuttan wrote:

I need a help, i have a number for eg :- 9.5 i want it to be 9.05 while taking to database cause if use round of it will give 9.50 but i want 9.05. am using C# 2005.

Pete O`Hanlon wrote:

It seems that he wants to redefine how mathematics works.

double d = 9.5;<br />
      d = Math.Floor(d) + ((Math.Floor(d) + 1) - d) / 10;<br />

jgasm wrote:

I simply want to count
how many decimals are in the string, unfortunately everything in regex seems to involve
replacing the decimals...and regex seems really heavy way of doing something that should
be simple.

Int32 decimalCount = text.Split('.')[1].Length

Int32 decimalCount = text.IndexOf('.') > -1 ? text.Split('.')[1].Length : 0;

[System.STAThreadAttribute]
static void Main(string[] args)
{
    int d ;
 
    args [ 0 ] = args [ 0 ].Trim( new char[] { '0' } ) ;
    d = args [ 0 ].IndexOf ( '.' ) ;
 
    if ( d >= 0 )
    {
        d = args [ 0 ].Length - d - 1 ;
    }
    else
    {
        d = 0 ;
    }
 
    System.Console.WriteLine ( d ) ;
}

int d ;

args [ 0 ] = args [ 0 ].Trim( new char[] { '0' } ) ;

System.Console.WriteLine
(
    ( d = args [ 0 ].IndexOf ( '.' ) ) == -1 ? 0 : args [ 0 ].Length - d - 1
) ;

int pos = text.IndexOf('.');
int decimalCount;
if (pos == -1) {
   decimalCount = 0;
} else {
   decimalCount = value.Length - pos - 1;
}

int pos = text.IndexOf('.');
int decimalCount = (pos == -1) ? 0 : value.Length - pos - 1;

fuziononline wrote:

Before going throught the hassle of creating ours from cradle to grave I was hoping to see what others have already created?