ASP.NET Discussion Boards

Enabling other controls on the page on doubleclick of a row in the GirdView control

Janu_M22-Dec-07 17:14

22-Dec-07 17:14

Hi,

I am developing a webproject in C#.net using .net2005.

My project contains two pages. First page displays data from the database in a datagrid view. when i double clicks a row in the datagrid it directs to the second page.

for this i am writing the following code in the rowcreated event of the datagrid.

e.Row.Attributes.Add("ondblclick", String.Format("window.location='" + Columns[i].ToString() + "'"));

here the arraylist Columns contains the following sample data

Columns.Add( "frmOtherPage.aspx?ListType=Empty&ViewType=Invoice&UniqueId=" + uniqueid.ToString());

In the datagrid i am not displaying this unique id.

on double click of the row i am getting the uniqueid of that particular row in the second page.

In second page i am displaying the data of the selected row in detail and diplaying the sub activities of this row in a data grid. In this grid also i am not displaying the activityid.

Here i have to display some controls to create a new sub activity. I am placing all these controls in a panel and displaying (.visible = true) them when user clicks the create sub activity button.

Here what i want is, on doubleclicking a row on the sub activities grid the panel for creating activity must be visible and i have to display the data of that row in those controls of the panel.

Please Help me. Its urgent.

Thanks in Advance

Ramu

How to make photos "appear clickable" ?

scm22ri22-Dec-07 10:46

scm22ri

22-Dec-07 10:46

Hi Everyone,

(I apologize for my terrible terminology)

Do you know when you "wave" your cursor over a photo or a url link and it appears as I would like to put it "clickable" or the cursor changes into a "hand". My issue is this, on my site I have a photo that I've changed the source code to and the photo is actually "clickable" but if you "wave" your cursor over the photo it dosen't appear "clickable" Does anyone know how I would fix that ? The source code is below.

<asp:hyperlink id="HyperLink1" runat="server" imageurl="~/Ringtone-Carrier-Photos/alltel-Complimentary Ringtones.jpg">

onClick="makeUrl('http://fbgdc.com/click/?s=8785&c=53726&subid=yahoo=flycell=alltel')"

Target="_blank"Alltell 15 Complimentary Ringtones</asp:hyperlink>

http://tinyurl.com/2tca8w (This is the page, just "wave" your cursor over the "alltell photo" and you will know what I'm talking about.)

Thanks everyone for there help.

Re: How to make photos "appear clickable" ?

Christian Graus22-Dec-07 10:53

Christian Graus

22-Dec-07 10:53

Handle the onmouseover and onmouseout events and change the cursor accordingly.

Christian Graus - Microsoft MVP - C++

"also I don't think "TranslateOneToTwoBillion OneHundredAndFortySevenMillion FourHundredAndEightyThreeThousand SixHundredAndFortySeven()" is a very good choice for a function name" - SpacixOne ( offering help to someone who really needed it ) ( spaces added for the benefit of people running at < 1280x1024 )

Re: How to make photos "appear clickable" ?

Venkatesh Mookkan23-Dec-07 15:39

Venkatesh Mookkan

23-Dec-07 15:39

You can use either ways:
* Use CssClass to set the Image's cursor:pointer (Use StyleSheet here)
or
* HyperLink1.Style.Add("cursor","pointer") in the code behind.

Regards,
Venkatesh Mookkan.
Software Engineer, India
My: Website | Yahoo Group | Blog Spot

paypal ver iam wrong

Mogaambo22-Dec-07 6:03

Mogaambo

22-Dec-07 6:03

// iam testing in sandbox enviroment and it is shows the following error

//"ErrorCode=10501&Desc=Invalid Configuration
//&Desc2=This transaction cannot be processed due to an invalid merchant configuration."
// ver iam wrong i enter all the correct details

using System;
using System.Data;
using System.Configuration;
using System.Collections;
using System.Web;
using System.Web.Security;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Web.UI.WebControls.WebParts;
using System.Web.UI.HtmlControls;
using com.paypal.sdk.services;
using com.paypal.sdk.profiles;
using com.paypal.sdk.core;
using com.paypal.sdk;
using com.paypal.sdk.util;
using System.ComponentModel;
using System.Web.SessionState;
public partial class paymantapi : System.Web.UI.Page
{
protected void Page_Load(object sender, EventArgs e)
{

}
protected void Button1_Click(object sender, EventArgs e)
{
com.paypal.sdk.services.NVPCallerServices caller = new com.paypal.sdk.services.NVPCallerServices();
IAPIProfile profile = ProfileFactory.createSignatureAPIProfile();
profile.APIUsername = "seller_1197901374_biz_api1.rediffmail.com";
profile.APIPassword = "1197901386";
profile.Subject = string.Empty;
profile.APISignature = "AJPRAFDEADN4KU5-uQOlH6F4lndTAo8rfA-5axq.xADfGzVZNCtI.U-A";
caller.APIProfile = profile;
NVPCodec encoder = new NVPCodec();
encoder["METHOD"] = "DoDirectPayment";
encoder["PAYMENTACTION"] = "sale";
encoder["AMT"] = "59.45";
encoder["CREDITCARDTYPE"] = "VISA";
encoder["ACCT"] = "4356645484999804";
encoder["EXPDATE"] = "1/2026";
encoder["CVV2"] = "125";
encoder["FIRSTNAME"] = "Test";
encoder["LASTNAME"] = "User";
encoder["STREET"] = "1 Main St";
encoder["CITY"] = "San Jose";
encoder["STATE"] = "CA";
encoder["ZIP"] = "95131";
encoder["COUNTRYCODE"] = "US";
encoder["CURRENCYCODE"] ="USD" ;
encoder["NOTIFYURL"] = "www.paypal.yashsoftech.com/ipn.aspx";
string pStrrequestforNvp = encoder.Encode();
string pStresponsenvp = caller.Call(pStrrequestforNvp);

NVPCodec decoder = new NVPCodec();
decoder.Decode(pStresponsenvp);
Response.Write(pStresponsenvp);
string strAck = decoder["ACK"];
if (strAck != null && (strAck == "Success" || strAck == "SuccessWithWarning"))
{
string pStrResQue = "TRANSACTIONID=" + decoder["TRANSACTIONID"] + "&" +
"AMT=" + decoder["AMT"] + "&" +
"AVSCODE=" + decoder["AVSCODE"] + "&" +
"CVV2MATCH=" + decoder["CVV2MATCH"];
Response.Redirect("DoDirectPaymentReceipt.aspx?"+pStrResQue);

}
else
{
string pStrError = "ErrorCode=" + decoder["L_ERRORCODE0"] + "&" +
"Desc=" + decoder["L_SHORTMESSAGE0"] + "&" +
"Desc2=" + decoder["L_LONGMESSAGE0"];

Response.Redirect("APIError.aspx?"+pStrError);

}
}
}

Re: paypal ver iam wrong

Christian Graus22-Dec-07 9:23

Christian Graus

22-Dec-07 9:23

Good Lord, tell me you didn't just post all the details of your paypal account to CP ?

Re: paypal ver iam wrong

Paul Conrad22-Dec-07 9:33

Paul Conrad

22-Dec-07 9:33

Kind of looks like it Eek! | :eek:

"Real programmers just throw a bunch of 1s and 0s at the computer to see what sticks" - Pete O'Hanlon

Re: paypal ver iam wrong [modified]

Mogaambo22-Dec-07 20:27

Mogaambo

22-Dec-07 20:27

I posted all the details , the details are those which i collected from books and also from codeproject, just type the paypal in search box u will get the code from ajith r nair article.

Actually the credit card which iam giving is a sandbox generated credit card.

my developer.paypal.com, username="megha_3983@rediffmail.com password=chandra550

my seller password = 197901323
my buyer password = 197901255
plz tell me ver iam missin the details

hope u reply me soon

modified on Sunday, December 23, 2007 4:06:07 AM

Re: paypal ver iam wrong

Christian Graus22-Dec-07 22:34

Christian Graus

22-Dec-07 22:34

chanu007 wrote:
Actually the credit card which iam giving is a sandbox generated credit card.

I know, it was the paypal account details, that you reiterate here, that left me incredulous.

Have you tried asking paypal ?

problem with javascript

morteza5722-Dec-07 5:43

morteza57

22-Dec-07 5:43

Hi, i used from this javascript code in my website an it works correctly by IE.
But it dos not work with Firefox.
what is it's equivalent compatible with Firefox?
Thank you.

$get('Panel1').style.left=100;
$get('Panel1').style.top =100;
$get('Panel1').style.posWidth=100;
$get('Panel1').style.posHeight=100;

Re: problem with javascript

Christian Graus22-Dec-07 9:25

Christian Graus

22-Dec-07 9:25

What is $get ? I've never seen that. document.getElementById is how you find an element, and you should do it once, check the returned value, then use that variable.

Re: problem with javascript

morteza5722-Dec-07 9:54

morteza57

22-Dec-07 9:54

Dear Christian Graus,
$get is a function in ASP.NET AJAX that it's functionality is the same document.getElementById

Re: problem with javascript

Christian Graus22-Dec-07 10:03

Christian Graus

22-Dec-07 10:03

OK, but it doesn't use AJAX, right ? SO, I'd just do it properly as per what I outlined. I'd also do what I suggested to see if it fixes FF, and if it doesn't, you can use Firebug in FF to debug your code and work out what the property is ( but what you have looks right to me )

Enable linkButton form outer page

Knowledgestudent22-Dec-07 0:48

Knowledgestudent

22-Dec-07 0:48

hi there,
I am designing ASP.net over VB
I have a linkButton in the master page and it is disabled, in the login page the login Button must enable that linkButton
when I use it immediately like this:

stdMaster.ChangeModeBtn.enable(True)
it does not work , it gives me something about the protected withEvents "is not accessible in this context because it is protected"

I know that I am missing something but I do not know what is it
please tell me

urgent help please Hmmm | :|

There is always something to learn

Re: Enable linkButton form outer page

Paul Conrad22-Dec-07 9:29

Paul Conrad

22-Dec-07 9:29

Knowledgestudent wrote:
urgent

No. Must have patience.

"Real programmers just throw a bunch of 1s and 0s at the computer to see what sticks" - Pete O'Hanlon

Re: Enable linkButton form outer page

Venkatesh Mookkan23-Dec-07 16:01

Venkatesh Mookkan

23-Dec-07 16:01

Knowledgestudent wrote:
stdMaster.ChangeModeBtn.enable(True)
it does not work , it gives me something about the protected withEvents "is not accessible in this context because it is protected"

ChangeModeBtn control, you are using is not a public control to access from the child page (Login). To access that control add a public subroutine or function in the Master Page which would enable or disable your control, like:

In MasterPage:

Public Sub EnableLink(value As Boolean)
    ChangeModeBtn.Enabled = value
End Sub

Access the Link from your child page like:

stdMaster.EnableLink(True)

I hope this would help you.

Regards,
Venkatesh Mookkan.
Software Engineer, India
My: Website | Yahoo Group | Blog Spot

ASP.Net "is not accessible in this context because it is Protected"

JEP_Dude10-Feb-09 16:16

JEP_Dude

10-Feb-09 16:16

I also have this problem. My research has shown that is is caused by ASP.Net opening two files and copying what's typed in one form into the other automatically. Yet when you attempt to reference a control from one form it states the above error.

My findings revealed that this problem has been around for sometime. It seems like there should be one simple correction to prevent this type of error from ever occurring. But thats just a dream.

I like to think that I understand the major parts of what causes the error. Yet the bigger question still remains ... how do I fix it?

Please help ... Thanks in advance.

Re: ASP.Net "is not accessible in this context because it is Protected"

Knowledgestudent11-Feb-09 0:03

Knowledgestudent

11-Feb-09 0:03

I think the problem occurs just like "Venkatesh Mookkan" said , in the post reply
if your problem similer to mine, I think the method solution by Venkatesh Mookkan should solve the preventing, but taking care for the access control identifier to proper according to your application,

actually I did not fully understand your problem Confused | :confused:

, is it with button or with another control, is it from master page or something else,

clarify plz

There is always something to learn

Check IsNumeric

SreejithAchutan21-Dec-07 21:42

SreejithAchutan

21-Dec-07 21:42

How to check if a data is to be entered using insert query statement,check the field we entered is muneric or not if numeric save it into database.Otherwise print a msg

Re: Check IsNumeric

Christian Graus21-Dec-07 21:58

Christian Graus

21-Dec-07 21:58

Use int.TryParse to see if a string contains a number.

Re: Check IsNumeric

SreejithAchutan21-Dec-07 22:05

SreejithAchutan

21-Dec-07 22:05

If a field datatype is represented as tinyint.By mistakenly if a user enter the data as a string value then an exception will be catched in sql.How to avoid the exception .Or if posiible to declare a msg inorder for this exception ..How i check the field as mumeric or not in code.

Re: Check IsNumeric

pmarfleet21-Dec-07 22:36

pmarfleet

21-Dec-07 22:36

SreejithAchutan wrote:
By mistakenly if a user enter the data as a string value then an exception will be catched in sql.

You don't perform basic data validation like this in your database. You perform it in your web pages or in your middle tier. It is bad practice to send invalid input like this all the way to your database to be validated. Errors like this should be caught and handled far earlier in your application.

Paul Marfleet

"No, his mind is not for rent
To any God or government"
Tom Sawyer - Rush

Re: Check IsNumeric

Paul Conrad22-Dec-07 9:35

Paul Conrad

22-Dec-07 9:35

pmarfleet wrote:
It is bad practice to send invalid input like this all the way to your database to be validated. Errors like this should be caught and handled far earlier in your application.

I agree. It is amazing how much bad practice I see around here sometimes.

"Real programmers just throw a bunch of 1s and 0s at the computer to see what sticks" - Pete O'Hanlon

how to provide a link to forms using coding

Sandep H S21-Dec-07 20:28

Sandep H S

21-Dec-07 20:28

Hello Sir\Madam,
Please provide me info on how to link to the various forms in a project using coding but not by using properties window.
for e.g:
if(condn)
{
then to next form ;( pl provide code how to achieve this)
}

Thank you!

Re: how to provide a link to forms using coding

Michael Sync21-Dec-07 20:41

Michael Sync

21-Dec-07 20:41

Response.Redirect("http://yourdomain.com/nextpage.aspx")

Thanks and Regards,
Michael Sync ( Blog: http://michaelsync.net)

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