Why pointer from override class use operator== and operator!= from base class

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C++

vector

I have Iterator template for class and class for use in the for statement.

template<class T>
class Itr2 {
public:
	 Itr2()  { }
	~Itr2()  { }

	typedef typename Itr2 type;
	typedef typename T& reference;

	virtual type& operator++()						{ return *this; }
	virtual T&	  operator*()						{ return ((reference)*((type*)this)); }
	virtual bool  operator==(const type& o) const { return true; }
	virtual bool  operator!=(const type& o) const { return false; }
};


template<class T>
class I2
{
public:
	typedef I2<T> type;
	typedef T	  value;
	typedef T& reference;
	typedef typename Itr2<T> iterator;

	virtual iterator& begin() { return *(new iterator()); }
	virtual iterator& end()   { return *(new iterator()); }
};

Next, I created class for standard std::vector<>.

template<class T>
class ItrSTD : public Itr2<T> {
public:
	typedef typename Itr2<T> base_type;
	typedef typename ItrSTD<T> type;
	typedef typename T& reference;
	typedef typename std::vector<T>::iterator std_itr;
protected:
	std_itr itr_;
public:
	ItrSTD(const type& o)								{ itr_ = o.itr_; }
	ItrSTD(const std_itr& o)							{ itr_ = o; }

	virtual base_type&  operator++()					{ itr_++; return *this; }

	virtual T&			operator*()						{ return ((reference)(*this->itr_)); }
	bool  operator==(const base_type& o) const override { return (((const type&)o).itr_ == this->itr_); }
	bool  operator!=(const base_type& o) const override { return (((const type&)o).itr_ != this->itr_); }
};



template<class T>
class VSTD : public I2<T> {
protected:
	std::vector<T>  arr_;
public:
	typedef typename ItrSTD<T>  iterator;

	VSTD(const VSTD& o)  { arr_ = o.arr_; }
	template<typename ...E>	VSTD(E&&...e) : arr_({ std::forward<T>(e)... }) {  }

	iterator& begin()  _NOEXCEPT  override{ return (*new iterator(arr_.begin())); }
	iterator& end()    _NOEXCEPT  override{ return (*new iterator(arr_.end())); }

};

If i use direct statement for(int i:v). It is works fine, but when I try to do this from the pointer compiler use base class operator!= (not override operator!=) and code doesn't work :(.

int v_i = 0;
VSTD<int> vstd_a = { 1, 2, 3 };
I2<int> *i2 = &vstd_a;

for (int j : *i2) //DOESN't work :( use operator!= from base class
{
v_i += j;
}
for (int j : vstd_a) //work fine :)  use operator!= from VSTD.
{
 v_i += j;
}

Why this happen. It is possible to use for statement for template pointer ?
begin(), end() functions works fine. Only operator work different.
P.S. I use VS2013 compiler.


Some additional info:

If i simplify the code:

template<typename T>
class I3
{
public:
	T i;
	virtual bool  operator==(const I3& o) const { return false; }
};

template<typename T>
class I3O : public I3<T>
{
public:
	virtual bool  operator==(const I3& o) const override { return true; }
};

Both result are fine (return true) and compare from override class (only for( : ) work bad :():

I3O<int> i3_a, i3_b; I3<int> *i3_ap, *i3_bp;

i3_ap = &i3_a; i3_bp = &i3_b; bool i3_c;

i3_c = (i3_a == i3_b);
i3_c = ((*i3_ap) == (*i3_bp));