How to show /Hide an image button that is inside gridview Item Template

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Posted 20-Apr-14 19:52pm

Member 10578683

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Tadit Dash (ତଡିତ୍ କୁମାର ଦାଶ) · Accepted Answer · 2014-04-20T20:17:00

Solution 1

Solution

Inside the RowDataBound Event, find the control.
Run your logic and set Visible property to true/false.

Example

C#

protected void gridView_RowDataBound(object sender, GridViewRowEventArgs e)
{
    if (e.Row.RowType == DataControlRowType.DataRow)
    {
        if(someCondition)
        {
            ImageButton imgBtn= (ImageButton)e.Row.FindControl("imageButtonId");
            imgBtn.Visible = false;
        }
    }
}

Posted 20-Apr-14 20:17pm

Tadit Dash (ତଡିତ୍ କୁମାର ଦାଶ)

Updated 20-Apr-14 20:21pm

v2

Comments

Member 10578683 21-Apr-14 2:35am

i did like this but not coming. please check the code

protected void gdvProducts_RowDataBound(object sender, GridViewRowEventArgs e)
{
try
{
if (e.Row.RowType == DataControlRowType.Footer)
{
}
if ((e.Row.RowState & DataControlRowState.Edit) > 0)
{
string txt_ddlStatus = e.Row.FindControl("ddlStatus").ClientID;
string txt_ddlSubStatus = e.Row.FindControl("ddlSubStatus").ClientID;

ImageButton lnlUpdate = (ImageButton)e.Row.FindControl("lnkUpdate");
lnlUpdate.Attributes.Add("onclick", "javascript:return Validate('" + txt_ddlStatus + "','" + txt_ddlSubStatus + "')");
}
if (e.Row.RowType == DataControlRowType.DataRow)
{
Label lblId = (Label)e.Row.FindControl("lblID");
string id = lblId.Text;
Label lblProductName = (Label)e.Row.FindControl("lblProduct");
Label lblSerial = (Label)e.Row.FindControl("lblSerial");
Label lblStatus = (Label)e.Row.FindControl("lblStatus");
TextBox txtBox1 = (TextBox)PlaceHolder1.FindControl("tb1");
string subProductName = lblProductName.Text;
string subSerial = lblSerial.Text;
string subStatus = lblStatus.Text;

if (Session["Role"] != null && !string.IsNullOrEmpty(Session["Role"].ToString()))
{
con.Open();
using (SqlCommand comm = new SqlCommand("select [Edit] from Role1 where Role_Name=@Role and Pages=@Pages", con))
{
string Role = (string)(Session["Role"]);
// 2. define parameters used in command object
SqlParameter para = null;
para = new SqlParameter();
para.ParameterName = "@Role";
para.Value = Role;
comm.Parameters.Add(para);

//Pass @Pages parameter
para = new SqlParameter();
para.ParameterName = "@Pages";
para.Value = "Checkin";
comm.Parameters.Add(para);
SqlDataReader reade = comm.ExecuteReader();
while (reade.Read())
{
Session["Edit"] = Convert.ToString(reade["Edit"]);
}
//Button Add = (Button)PreviousPage.FindControl("Button2");
if (Session["Edit"].ToString() == "Y")
{

ImageButton img = (ImageButton)e.Row.FindControl("lnkEdit");
img.Visible = true;
}
else
{
ImageButton img = (ImageButton)e.Row.FindControl("lnkEdit");
img.Visible = false;

}
}

}
con.Close();
}
}

catch (Exception ex)
{
}
}
and the mark up is
<itemtemplate>

<asp:ImageButton CssClass="txtBtn" ID="lnkEdit" runat="server" CommandName="Edit"
ImageUrl="~/images/edit.gif" ToolTip="Edit" />
<asp:ImageButton CssClass="txtBtn" ID="lnkDelete" runat="server" CommandName="Delete"
CommandArgument='' OnClientClick="javascript:return confirm('Are you sure you want to delete the record?')"

Tadit Dash (ତଡିତ୍ କୁମାର ଦାଶ) 21-Apr-14 2:38am

Did you debug and see if it satisfying the condition or not?

Member 10578683 21-Apr-14 2:52am

that condition is not executing

Tadit Dash (ତଡିତ୍ କୁମାର ଦାଶ) 21-Apr-14 3:01am

You mean the below condition, right?

if (Session["Edit"].ToString() == "Y")

But why???

One more thing here. Always check for null before getting the value like...

if(Session["Edit"] != null && !string.IsNullOrEmpty(Session["Edit"].ToString()))
{
if (Session["Edit"].ToString() == "Y")
{
// Do whatever you want.
}