How to override a javascript function's default behavior

Question

1.00/5 (1 vote)

See more:

I am learning JavaScript. And this is an object that has two properties; 'color' & 'machine' and one method named 'particulars'

JavaScript

Car = {
  color: 'Red',
  machine: 12,
  particulars: function() {
   return console.log(this.color);
   return  console.log(this.machine);
  }
}
Car.particulars();

Actually, I want to remove the 'undefined' value that comes in the output of this code when you run the above code, without the return statements.

What I have tried:

I have added two return statements against each console log, as it came into my learning that when you explicitly return anything from a function then it will return that thing otherwise in JavaScript, it will give you undefined as a value as its implicit or default behavior but here it doesn't prints the value for machine property just color.
I want to run this code that it prints both the values of color and machine with no undefined to be seen in the output

Thank you!!

Posted 1-Jun-23 7:42am

Shazma Batool

Updated 18-Jul-23 6:26am

Add a Solution

Comments

[no name] 1-Jun-23 15:14pm

For starters, you can "never" have 2 or more "unconditional" returns; only the first ever gets executed.

Member 15627495 2-Jun-23 2:48am

as you tag your topic OOP, use the 'Class' statement for your car Class.
add one or more constructors , 'getters' and 'setters' too.

as it is, your code is missing few lines.

class car = {
  constructor(){
    this.color = 'Red';
    this.machine = 12;
  }

  function particulars(){

   console.log(this.color);
   console.log(this.machine);

  }
}

var audi = new car();
audi.particulars();

JS is low typed, and that grant coders to go through all types very easily.
Integers can be fetch as an array, or as a string with indexes.

coders can write 'mixed arrays' combining datas, functions, objects with self vars in.
the code you write is not a 'Class' as await, but you write a 'mixed array'.

It's not a fault, by the JS reliability between types, you can go far with 'mixed arrays', it's a really powerful use.
and that works well !

Member 10601191 18-Jul-23 8:49am

@Richard Deeming,have removed my entry. afaics the user is using a class function, but always happy to learn when mistaken.

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Member 10601191 · Answer 1 · 2023-07-18T06:26:00

Solution 3

try the following.

JavaScript

Car = {
  color: 'Red',
  machine: 12,
  particulars: function() {
   return console.log(this.color, this.machine);
  }
}
Car.particulars();

Posted 18-Jul-23 6:26am

Member 10601191