#include<stdio.h>
#include<stdlib.h>
int valid_date(int date, int mon, int year);
int main(void)
{
int day1, mon1, year1,
day2, mon2, year2;
int day_diff, mon_diff, year_diff;
printf("Enter start date (MM/DD/YYYY): ");
scanf("%d/%d/%d", &mon1, &day1, &year1);
printf("Enter end date (MM/DD/YYYY): ");
scanf("%d/%d/%d", &mon2, &day2, &year2);
if(!valid_date(day1, mon1, year1))
{
printf("First date is invalid.\n");
}
if(!valid_date(day2, mon2, year2))
{
printf("Second date is invalid.\n");
exit(0);
}
if(day2 < day1)
{
if (mon2 == 3)
{
if ((year2 % 4 == 0 && year2 % 100 != 0) || (year2 % 400 == 0))
{
day2 += 29;
}
else
{
day2 += 28;
}
}
else if (mon2 == 5 || mon2 == 7 || mon2 == 10 || mon2 == 12)
{
day2 += 30;
}
else
{
day2 += 31;
}
mon2 = mon2 - 1;
}
if (mon2 < mon1)
{
mon2 += 12;
year2 -= 1;
}
day_diff = day2 - day1;
mon_diff = mon2 - mon1;
year_diff = year2 - year1;
printf("Difference: %d years %02d months and %02d days.", year_diff, mon_diff, day_diff);
return 0;
}
int valid_date(int day, int mon, int year)
{
int is_valid = 1, is_leap = 0;
if (year >= 1800 && year <= 9999)
{
if ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0))
{
is_leap = 1;
}
if(mon >= 1 && mon <= 12)
{
if (mon == 2)
{
if (is_leap && day == 29)
{
is_valid = 1;
}
else if(day > 28)
{
is_valid = 0;
}
}
else if (mon == 4 || mon == 6 || mon == 9 || mon == 11)
{
if (day > 30)
{
is_valid = 0;
}
}
else if(day > 31)
{
is_valid = 0;
}
}
else
{
is_valid = 0;
}
}
else
{
is_valid = 0;
}
return is_valid;
}
What I have tried:
I got this code in c that calculates day between 2 dates but I need to. modify it to find 1) 100th day. 2)I need to input the date today in the code.