I'm trying to reverse each number in an integer array and sort the final array.

Question

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For instance if my array is {34,12,56} first each number to be reversed that is {43,21,65} then the reversed array must be sorted and the final result will be : {21,43,65}.

I am getting few errors in while executing this code I dont know because of what I am getting those errors. Please check

What I have tried:

Java

import java.util.*;
public class ReverseSort
{
    public static int reversearray(int[] a, int n)
    {
         StringBuilder sb = new StringBuilder();
         for(int i=0; i<n ; i++)
         {
             a[i] = Integer.parseInt(sb.append(a[i]).reverse().toString());
             sb.setLength(0);
         }
         Arrays.sort(a);
         System.out.println(Arrays.toString(a));
    }

    //main
    public static void main(String args[])
    {
        int a[], n;
        Scanner sc = new Scanner(System.in);
        n = sc.nextInt();
        for(int i=0; i<n; i++)
        {

            a[i] = sc.nextInt();
        }
        System.out.println(a);
        ReverseSort.reversearray(a,n);
    }
}

Posted 21-Apr-21 22:43pm

chaitanya chitturi

Updated 21-Apr-21 23:46pm

v2

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Comments

Richard Deeming 22-Apr-21 4:45am

You seem to have forgotten to ask a question. What is the problem with the code you have written?

chaitanya chitturi 22-Apr-21 4:51am

hey Richard, I am getting few errors while executing this code I don't know because of what I am getting those errors. Please check

Richard Deeming 22-Apr-21 4:53am

If you want someone to help you fix those errors, then you need to provide the details of the errors. You can't simply say "I'm getting some errors" and expect us to work out what the problem is!

chaitanya chitturi 22-Apr-21 5:45am

sorry I am new here that's why I post it like that.

CPallini 22-Apr-21 7:40am

Do you realize that reversing the array has no effect on the final result?

chaitanya chitturi 22-Apr-21 9:23am

read the description carefully

CPallini 22-Apr-21 10:51am

You are right, my bad.

2 solutions

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Richard MacCutchan · Accepted Answer · 2021-04-21T23:07:00

Try this:

Java

public static void reversearray(int[] a, int n) // method does not return a value
{
     StringBuilder sb = new StringBuilder();
     for(int i=0; i<n ; i++)
     {
         a[i] = Integer.parseInt(sb.append(a[i]).reverse().toString());
         sb.setLength(0);
     }
     Arrays.sort(a);
     System.out.println(Arrays.toString(a));
}

public static void main(String args[]) }
    Scanner sc = new Scanner(System.in);
    int n = sc.nextInt();
    int a[] = new int[n]; // must create the array of n elements
    for(int i=0; i<n; i++)
    {

        a[i] = sc.nextInt();
    }
    System.out.println(Arrays.toString(a));
    reversearray(a,n); // no need for class name on the call to reversearay

}

chaitanya chitturi · Accepted Answer · 2021-04-21T23:46:00

Java

import java.util.*;
public class ReverseSort
{
public static int[] reversearray(int[] a, int n)
{
StringBuilder sb = new StringBuilder();
for(int i=0; i<n ; i++)
{
a[i] = Integer.parseInt(sb.append(a[i]).reverse().toString());
sb.setLength(0);
}

Arrays.sort(a);
System.out.println(Arrays.toString(a));

return a;
}
//main
public static void main(String args[])
{
int n;
Scanner sc = new Scanner(System.in);
n = sc.nextInt();
int a[] = new int[n];
for(int i=0; i<n; i++)
{

a[i] = sc.nextInt();
}

ReverseSort.reversearray(a,n);
}
}

I'm trying to reverse each number in an integer array and sort the final array.

2 solutions

Solution 2

Solution 3

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