Regex: system.argumentexception: '"[0-9]*, \V[0-9]" wird analysiert - unbekannte escape-zeichenfolge \V.'

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The code

C#

string pattern = @"[0-9]*,\V[0-9]";
string input = @"1,560";
foreach (Match m in Regex.Matches(input, pattern))
{    Console.WriteLine("'{0}' found at index {1}.", m.Value, m.Index); }

ends wit Error 'Unbekannte Escape-Zeichenfolge \V.'.

What ist teh problem?

What I have tried:

Where i use <a href="https://regex101.com/">Online regex tester and debugger: PHP, PCRE, Python, Golang and JavaScript</a>[<a href="https://regex101.com/" target="_blank" title="New Window">^</a>] 
than runns this without error and match 1.

Posted 6-Aug-20 2:24am

otsch

Updated 6-Aug-20 3:05am

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Sandeep Mewara 6-Aug-20 8:41am

Not too sure of what you are trying as the details are in non-english. Posting based on what seems to be the possible cause.

3 solutions

Solution 1

"\V" is not a valid Regular expression sequence, but "\v" is. Try this:

C#

string pattern = @"[0-9]*,\v[0-9]";

But that won't match your test data at all - because it contains no vertical whitespace, and will only pick up the first digit after the comma.

Get a copy of Expresso[^] - it's free, and it examines and generates Regular expressions.

Quote:
My goal is to remove the last zeros from the string.
1,56700 --> 1,567

Try this:

[0-9]*,[0-9]+?(?=0*$)

It treats the last zeros (if any) and the end of string as a not-included suffix, but allows zeros in the "body":

1506700 -> 1,5067

Posted 6-Aug-20 2:34am

OriginalGriff

Updated 6-Aug-20 4:35am

v2

Comments

Sandeep Mewara 6-Aug-20 11:03am

My 5!

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Sandeep Mewara · Accepted Answer · 2020-08-06T02:51:00

Solution 2

There is no capital V as a sequence. It's small 'v'.

Here, a list of valid escape sequences: Regular Expression Escape Sequence[^]

@"/[0-9]*,\v[0-9]"; // should not throw an error

Posted 6-Aug-20 2:51am

Sandeep Mewara

Comments

otsch 6-Aug-20 9:05am

Yes, where i use 'v' throw not an error.
But i hve not match.
My goal is to remove the last zeros from the string.
1,56700 --> 1,567

Sandeep Mewara 6-Aug-20 10:29am

I was not sure of your requirement. Above solves the error you faced.

To remove the last zeros from the string, try:
(?=.*?)(.*?[1-9])(?!.*?\.)(?=0*$)|^.*$

There would be more ways (probably simpler way - you need to try) to do it though.

OriginalGriff 6-Aug-20 10:35am

I posted a simpler way before I saw yours - sorry!

Sandeep Mewara 6-Aug-20 11:01am

No worries. :)

OriginalGriff 6-Aug-20 10:36am

Updated my solution.

Sandeep Mewara 6-Aug-20 11:03am

:thumbsup:

Richard Deeming · Accepted Answer · 2020-08-06T03:05:00

In PHP regular expressions, \V means "anything except vertical whitespace".

That token doesn't exist in the .NET Regular Expression language:
Regular Expression Language - Quick Reference | Microsoft Docs[^]

Instead, you would need to negate the \v token:

C#

string pattern = @"[0-9]*,[^\v][0-9]";

Regex: system.argumentexception: '"[0-9]*, \V[0-9]" wird analysiert - unbekannte escape-zeichenfolge \V.'

3 solutions

Solution 1

Solution 2

Solution 3

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