problem with type casting

If you are dividing int values, you must cast them to doubles if the receiving variable is a double.

For example, this will result in "0":

int x = 1;
int y = 2;
double z = x / y;

Where this will result in the expected 0.5:

int x = 1;
int y = 2;
double z = (double)x / (double)y;