How the second one works and the first one not on the given set of inputs?

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First code:

int a;
	long b;
	char c;
	float d;
	double e;

	scanf("%d", &a);
	scanf("%ld", &b);
	scanf("%c", &c);
	scanf("%f", &d);
	scanf("%lf", &e);

	printf("%d\n", a);

	printf("%ld\n", b);

	printf("%c\n", c);

	printf("%f\n", d);

	printf("%lf\n", e);

Second Code:

int a; 
    long b; 
    char c; 
    float d; 
    double e;
    scanf("%d %ld %c %f %lf",&a,&b,&c,&d,&e);

    printf("%d", a);
    cout<<endl;
    printf("%ld",b);
    cout<<endl;
    printf("%c ", c);
    cout<<endl;
    printf("%f ", d);
    cout<<endl;
    printf("%lf", e);

What I have tried:

first one is not working and second one is giving correct outputs on these set of input values:

3 12345678912345 a 334.23 14049.30493

Posted 22-Jun-19 23:06pm

Member NFOC

Updated 23-Jun-19 1:42am

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OriginalGriff · Answer 1 · 2019-06-22T23:20:00

Because your second version explicitly includes the spaces which separate your values, your first doesn't, so it gets out of sync.
Try this:

C++

int a;
long b;
char c;
float d;
double e;

scanf("%d ", &a);
scanf("%ld ", &b);
scanf("%c ", &c);
scanf("%f ", &d);
scanf("%lf", &e);

printf("%d\n", a);
printf("%ld\n", b);
printf("%c\n", c);
printf("%f\n", d);
printf("%lf\n", e);

CPallini · Answer 2 · 2019-06-23T01:43:00

Then use the third (C++) one:

C++

#include <iostream>
using namespace std;

int main()
{
  int a;
  long b;
  char c;
  float d;
  double e;

  cin >> a >> b >> c >> d >> e;
  if ( cin.good())
    cout << a << " " << b << " " << c << " " << d << " " << e << endl;
  else
    cout << "no luck" << endl;
}

How the second one works and the first one not on the given set of inputs?

2 solutions

Solution 1

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