Formula to calculate the number of days

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hi,

I have in A1 = '20-05-2012' B1 = 'NO' and I want in C1 a formula to calculate the number of days between to dates, so:

C#

string today = DateTime.Now;

if(B1='NO')
{
   //Here I want that C1 = '3'
   //and tomorow will C1 = '4' 
   //because the number of days between 20-05-2012 and 23-05-2012 = 3
   //and tomorrow the number of days between 20-05-2012 and 24-05-2012 = 4
}

How I do this in excel?
I hope you understand my question...

Regards,
KZ

Posted 23-May-12 6:35am

Killzone DeathMan

Updated 23-May-12 6:36am

v2

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3 solutions

Solution 2

If you want highly efficient algorithms, then you want look at:
http://alcor.concordia.ca/~gpkatch/gdate-algorithm.html[^]

Posted 23-May-12 9:23am

Clifford Nelson

Solution 3

I already solve it my friend:

=IF(E4="NO";(D4-TODAY())*-1;"OK")

this gives me the number of days between two dates:

D4="23-05-2012"

(D4-TODAY())*-1

But thanks!

KZ

Posted 23-May-12 22:17pm

Killzone DeathMan

Comments

Richard MacCutchan 24-May-12 4:31am

Why do you need to multiply by -1? What is wrong with TODAY()-D4?

Killzone DeathMan 24-May-12 4:37am

Because ('23-05-2012') - ('24-05-2012') = -1
and (-1)*(-1) = 1
I don't know why the result is -1, but multiply by -1 it works :)

Richard MacCutchan 24-May-12 4:42am

Like I said, why not just use TODAY()-D4?

Killzone DeathMan 24-May-12 4:49am

Because...because... come on my friend, it looks more mathematically...
But 'TODAY()-D4' and '(D4-TODAY())*-1' are the same! :)

Richard MacCutchan 24-May-12 4:54am

They are indeed the same in terms of the result, but why make a formula more complicated than it needs to be? Imaging some intern 5 years from now looking at that formula and wondering why it needs the 'extra' bit of calculation.

Killzone DeathMan 24-May-12 4:58am

ok ok I understand... I was just joking...

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Maciej Los · Accepted Answer · 2012-05-23T06:46:00

Solution 1

You need DateDiff function.

Take a look here:
http://msdn.microsoft.com/en-us/library/ms127413.aspx[^]
http://social.msdn.microsoft.com/Forums/eu/csharpgeneral/thread/f7094472-b473-4a29-8a90-d32056d05bef[^]

Posted 23-May-12 6:46am

Maciej Los

Updated 23-May-12 6:47am

v2