Getting the nodes in a TreeView control.

Question

3.00/5 (2 votes)

See more:

I've got a treeview on a form and it contains a few hundred nodes, many indented. Think of the explorer view for example. This statement:

int i = ExampleTreeView.GetNodeCount(true);

returns the count of all the nodes in my example treeview. I've tried searching for a one-liner but if the treeview can tell you how many nodes there are, is there a method that will return a "flattened" list-cum-array of those nodes, also as one-liner statement?

I've seen lots of examples that use recursion to build a flattened list of nodes but maybe there's something in the framework that'll do it for me? I'd like to think the framework might have something but if I have to do it with recursion, then so be it.

Does anyone know of something builtin to the framework that'll do that for me?

Posted 12-Jul-11 22:57pm

Septimus Hedgehog

Add a Solution

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

OriginalGriff · Answer 1 · 2011-07-12T23:09:00

There is nothing in the framework that will convert a hierarchical tree of nodes into a flat list: it could not be sure that it would be possible to distingiush dfferent elements:

Root
  branch1
    leaf1
    leaf2
  branch2
    leaf1
    leaf2

A default flat view would have only four elements, two called "leaf1" and two called "leaf2".

You will have to recursively parse the tree.