Three more errors pop up, how can it be fix

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hi
I have since corrected the error that you guys have pointed out to me but now I have three more errors and i have no idea how to fix it. been searching the net for something similiar but to no avail. here are the errors. it is the same codes.

error no1.

PHP

Notice: Undefined variable: query in C:\wamp64\www\luana_itec244\php\dashboard.php on line 70

error no 2:

PHP

Warning: mysqli_query(): Empty query in C:\wamp64\www\luana_itec244\php\dashboard.php on line 70

error no. 3:

PHP

Warning: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given in C:\wamp64\www\luana_itec244\php\dashboard.php on line 71

this project has to be handed in tomorrow so you know, it is a whole night for me. any help would be greatly appreciated. here i what I have. can someone tell me how do i get to insert and display images in my database, have tried everything, am now ran out of ideas

What I have tried:

PHP

<pre><?php

		
		$db_host='localhost';
		$db_username='root';
		$db_password="";
		$con=mysqli_connect($db_host,$db_username, $db_password) or die (mysqli_connect_error());
		
		mysqli_select_db($con, 'food') or die (mysqli_error($con));
		if(isset($_POST['submit']) && isset($_GET['img_id']))
		{
			$sql= "SELECT * FROM tbl_images  WHERE img_id={$img_id}";
			$result=mysqli_query($con, $sql) or die("Error:" .mysql_error($con));
			$rowcount=mysqli_num_rows($result);
		}
		
			
?>
<html>
<body>	
		<form  method="post" enctype="multipart/form-data" >
			<br/>
				<input type="file" name="image">
				<br/><br/>
				<input type="submit" name="submit" value="upload">
		</form>
			
		
<?php		
		if(isset($_POST['submit'])&& isset($_FILES['file']))
		{
			if(getimagesize($_FILES['image']['tmp_name'])== false)
			{
				echo "Please select an image";
			}
			else
			{
				
				$name=addslashes($_FILES['image']['name']);
				$image=base64_encode(file_get_contents(addslashes($_FILES['image']['tmp_name'])));				
				saveimage($name, $image);
			}			
		}
	
	function saveimage($name,$image)//this function is saving the images to the db
	{
			$con = mysqli_connect($db_host, $db_username, $db_password,"tbl_images");			
			$sql="INSERT INTO tbl_images(name,image) value('$name, '$image')";
			$query=mysqli_query($con, $sql);
			
			if($query)
			{
				echo "Success";
			}
			else
			{
				echo "not Upload";
			}
		
	}
	displayimage();	
	function displayimage()//this function will be used to display the images from the db
	{
		$db_host='localhost';
		$db_username='root';
		$db_password="";
		
		$con = mysqli_connect($db_host, $db_username, $db_password);			
		$sql="SELECT * FROM tbl_images";		
		$query=mysqli_query($con, $query);
		$num=mysqli_num_rows($query);					
		for($i=0; $i<$num; $i++)
		{
			$result=mysqli_fetch_array($query);
			$img=$result['image'];
			echo'<img src="data:image;base64, '.$img. '">';
		}
		mysqli_close($con);
	}
			
?>		
		
</body>
</html>

Posted 26-May-18 16:20pm

divinity02

Updated 26-May-18 18:00pm

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Patrice T · Answer 1 · 2018-05-26T18:01:00

Quote:
error no1: Notice: Undefined variable: query in C:\wamp64\www\luana_itec244\php\dashboard.php on line 70
error no 2 : Warning: mysqli_query(): Empty query in C:\wamp64\www\luana_itec244\php\dashboard.php on line 70

Messages are pretty clear
Just look at the code

PHP

$sql="SELECT * FROM tbl_images";
$query=mysqli_query($con, $query); // line 70 here

What is the name of the variable containing the query ?
Try

PHP

$sql="SELECT * FROM tbl_images";
$query=mysqli_query($con, $sql); // line 70 here