Javascript regular expression

Question

0.00/5 (No votes)

See more:

Hi,

I want to match below pattern,

2014%
%2014%
2014%
%2014%;%2014%

What I have tried:

JavaScript

(^%[0-9]{4};?$)+|(^[0-9]{4}%;?$)+|(^%[0-9]{4}%;?$)+

i tried above code.
its working for first 3 but not repeated pattern (%2014%;%2014%)

Can any one please help on that..

Posted 2-Jan-17 19:20pm

Updated 2-Jan-17 21:38pm

v2

1 solution

Add a Solution

Treat my content as plain text, not as HTML

…

Sign in to your account

Download, Vote, Comment, Publish.

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Peter Leow · Answer 1 · 2017-01-02T21:38:00

Try this:

^%\d{4}%$|^\d{4}%$|^%\d{4}$|^(%\d{4}%);\1$

Posted 2-Jan-17 21:38pm