How to passing values from to another without reinitialize form C#

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how to passing values from to another without reinitialize form c#

this is what iam trying to do

C#

frm_employees emp_form = new frm_employees();
            emp_form.txt_empid.Text = txt_emp_code.Text;
            emp_form.Show();

this code reinitialize the form again i don't need this,so could you please help me with this.

thanks in advance

this image can make it clear
http://i.imgur.com/cFZL66t.jpg[^]

What I have tried:

C#

frm_employees emp_form = new frm_employees();
            emp_form.txt_empid.Text = txt_emp_code.Text;
            emp_form.Show();

Posted 16-Jul-16 4:21am

Eng Abdull A-ziz

Updated 16-Jul-16 19:54pm

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2 solutions

Solution 1

Your are trying to have a "child" form which passes data back to it's "parent"?
That's pretty simple - all you need is an event (and maybe a property).
See here: Transferring information between two forms, Part 2: Child to Parent[^]

Posted 16-Jul-16 4:29am

OriginalGriff

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Karthik_Mahalingam · Accepted Answer · 2016-07-16T19:54:00

refer this example

Child Form

C#

public partial class FormChildEmployee : Form
    {
        public frm_employees ParentFormObject { get; set; }  // create a property for parent form

        public FormChildEmployee()
        {
            InitializeComponent();
        }
         
        private void btnSelect_Click(object sender, EventArgs e)
        {
            ParentFormObject.txt_empid.Text = txt_emp_code.Text; // assign the child's textbox value to the parent form Textbox without creating new instance
        }
    }

in Parent Form

C#

// opening the child pop up on button click in parent form
private void btnOpenPopUpChild_Click(object sender, EventArgs e)
       {
           FormChildEmployee objChild = new FormChildEmployee();
           objChild.ParentFormObject = this; // initialise this object( parent form ) to the property created.
           objChild.Show();
       }

Note: make the Parent Form textbox (txt_empid) as Public modifier in the design view.