Validating a pattern using c

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i want to validate a string pattern using c

pattern 123-456-789 i.e position 3 & 7 should be dash and others should be numeric value

i am validating it as below as below

C++

for( int iny = 0; iny < ilength ; iny++ )
    {

        if(isdigit((pszSeqCodeObjName[iny]) && ((iny != 3  || iny != 7))
        {
            validation= true;
        }
       else 
        {
           if(pszSeqCodeObjName[3] == '-'|| pszSeqCodeObjName[7] =='-')
            {
                 validation= true;
            }
            else
            {
              validation= false;

            }

suggest if any better logic can be done

quick response highly Appreciated !!.

Posted 9-Mar-16 7:34am

ramina sen

Updated 9-Mar-16 10:23am

Patrice T

v2

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jeron1 9-Mar-16 13:54pm

What happens if you put a '3' in position 3?

2 solutions

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OriginalGriff · Answer 1 · 2016-03-09T08:10:00

Solution 1

I would simplify it a little:

C++

bool valid = true;
for (int i = 0; i < iLength && valid; i++)
    {
    if (i == 3 || i == 7)
        {
        valid = pszSeqCodeObjName[i] == '-';
        }
    else
        {
        valid = isdigit(pszSeqCodeObjName[i]);
        }
    }

Posted 9-Mar-16 8:10am

OriginalGriff

bling · Answer 2 · 2016-03-09T10:23:00

C++

static bool match(const char *text, const char *pattern)
{
    while (*text && *pattern)
    {
        switch (*pattern)
        {
            case '#':
                if ( !isdigit(*text) )
                    return false;
            default:
                if (*pattern != *text)
                    return false;
        }
        text++;
        pattern++;
    }
    return *text == 0 && *pattern == 0;
}

int main(int, char **)
{
    const char text[] = "123-45-6789";
    const char pattern[] = "###-##-####";
    printf("%s applied to %s returns %d.\n", pattern, text, match(text, pattern));
    return 0;
}