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tpndtbk wrote:
If I use fstream class, I can open only the file already exits.
If I want to create a new file. What can I do?
use ios::in in Second Parameter of fstream object initialization
-----------------------------
"I Think this Will Help"
-----------------------------
Alok Gupta
visit me at http://www.thisisalok.tk
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HI,
I did like following:
fstream *fout;
fout = new fstream("data.dat", ios::in | ios::out | ios::binary);
fout->write((const char*)name, sizeof(Names));
//Names is a struct and name is a variable of Names type
fout->close();
-----------
So what is wrong in these codes?
I run this code, no errors but the file is not created!
Thank you
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I tried your code (except I did not use a pointer) and it worked as expected. Perhaps it is a permission-related issue.
"Opinions are neither right nor wrong. I cannot change your opinion. I can, however, change what influences your opinion." - David Crow
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As with David's comment above, but also be aware of the location that your file is being created.
tpndtbk wrote:
fout = new fstream("data.dat", ios::in | ios::out | ios::binary);
You supplied only the filename, not a definite path, which means that the file will be created in the current directory. This, in most cases, may very well be in your ..\debug\ subfolder.
I Dream of Absolute Zero
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HI,
THank you.
My program runs without any error but there's no file created. I think I have problem with writing permission. But I don't know how to solve it.
Can anyone help me out?
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And there's a strange thing that:
If I write:
fstream *fout;
fout = new fstream("data.dat", ios::in | ios::out | ios::binary);
if (!fout->is_open())
{
cout << " can't open the file" << endl;
return 1;
}
fout->write((const char*)name, sizeof(Names));
---> the result is "can't open the file";
But if I don't check if the file is open.
fstream *fout;
fout = new fstream("data.dat", ios::in | ios::out | ios::binary);
fout->write((const char*)name, sizeof(Names));
--> there's no error but there's no file created. I think if the file doesn't exist, the instruction "fout->write((const char*)name, sizeof(Names));" should cause an error. Right?
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Hi,
I'm trying to set up BlueTooth comunication between 2 devices,by using Virtual COM Port,with the RegisterDevice() function.
The problem is that the last parameter required the BD_ADDR(BlueTooth address) of the device i want to connect to.
How can i get the asddress????
Regards,
Eli
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BTH_ADDR which is a MAC address,
not BD_ADDR that is an IP address
but i don't remember how 
TOXCCT >>> GEII power
[toxcct][VisualCalc]
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First,thanx for your prompt reply.
According to MSDN:
When the client or server starts, it creates a COM port to associate
with the Bluetooth stack in the following manner:
HANDLE h = RegisterDevice (L"COM", index, L"btd.dll", (DWORD)&pp);
For the client, the Bluetooth server address (pp) is passed into the
pp.device member in the PORTEMUPortParams structure(and pp.device type is
BD_ADDR).
Anyone???
Regards,
Eli.
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Hey,
I lost the Intgration of VSS with my MSDEV. In the "projects" menu, there is no "Source control" option. There is no such tab in "Options" too.
How can i reintegrate MSDEV with VSS?
Thanks in ADvance
shijuck
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How I re-register ssscc.dll ?
I dont have the previous experience in it.
please help me.
shijuck
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Hi
Does anyone know how I can find out what exception has actualy
been thrown when I catch it with catch (...) block.
/Per
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all the other exceptions that has not been catched with previous catch block. you can imagine its behavior like the default statement of a switch...
TOXCCT >>> GEII power
[toxcct][VisualCalc]
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I woul'd like to catch the exception, but I don't know what type it is. Can I figure that out in some way?
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I don't think so either. In cases where you specify the exception type, you can do something like catch(CexType& ex)
and that gives you an object you can interrogate, perhaps using RTTI, but in the ellipsis case, there's nothing to help you.
Steve S
Developer for hire
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Most frameworks provide a base class that all exceptions should be derived from for this reason. For example MFC has a CException class.
In all but the most exceptional (pun intended) circumstances exceptions should derive from std::exception, the exception base class for the C++ Standard library. Rather than catch(...), use catch(std::exception& )
If you can keep you head when all about you
Are losing theirs and blaming it on you;
If you can dream - and not make dreams your master;
If you can think - and not make thoughts your aim;
Yours is the Earth and everything that's in it.
Rudyard Kipling
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I am using a dll that is returning a byte buffer and bitmapinfoheader
my front end is mfc appliction dialog box and now i want to draw that image byte buffer (that is accompanied by bitmapinfoheader)to my dialog box also the image is very large so i wan to scale it inorder to draw.
can any body help me
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I know it's a little old, but this function works and is pretty easy to use.
DrawDibDraw()
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use BitBlt().....
that might help.....
happy programmin.....
cheerz.....
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Look the scale is almost irrelivante (does not matter).
Never mind (I am not in the mode)! If you have the bitmapinfoheader, then you should know what (should) follow.
I started to go into all the ways this could be handled, but blank that, either you are recieving a bitmap (or DIB) or not (or some other [none-Window} reconized protocal, or you are not).
INTP
"The more help VB provides VB programmers, the more miserable your life as a C++ programmer becomes."
Andrew W. Troelsen
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Hi everyone, i have a wrapper calss of std::list<T> that compiles well under VC6.0 but under VC7.1 gegerates syntax error. the listings of the file are as follows:
.h file looks like this
template <class T> class myList
{
public:
list<T>::reference front();
protected:
list<T> m_lItems;
};
and .cpp file looks like this
template <class T> list<T>::reference myList<T>::back()
{
list<T>::reference r = m_lItems.back();
return r;
}
any help why this code is being compiled in VC6 but not in VC7.1.
the error it generated is 
error C2143: syntax error : missing ';' before '<
Tariq
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template class myList
{
public:
list::reference front();
protected:
list m_lItems;
};
and .cpp file looks like this
template list::reference myList::back()
{
list::reference r = m_lItems.back();
return r;
}
---------------------------------------------------------
Questions:
1) Where is the list?
You do not difine it (declare it) or what ever...
---------------------------------------------------------
Answer:
1) It is not there!
---------------------------------------------------------
How to declare a list class from a given template:
#include <list>typedef list<byte> CByteList;
INTP
"The more help VB provides VB programmers, the more miserable your life as a C++ programmer becomes."
Andrew W. Troelsen
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