Re: IEndPoint Object - C# Discussion Boards

23-Jun-04 0:31

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IEndPoint Object

dabuskol22-Jun-04 23:49

dabuskol

22-Jun-04 23:49

Guys,

I'm connecting to different servers using IP/PORT. So far I'm connected to 70 ip/port at the same time using the statement below. My problem is that if i'm using a port which has a value greater than 70000 it gives me an error "index out of bound"

string stripd = "10.32.54.23";<br />
string strport = "70252";<br />
<br />
IPAddress ip = IPAddress.Parse (stripd);<br />
Int32 iPortNo = Convert.ToInt32 ( strport);<br />
//create the end point <br />
IPEndPoint ipEnd = new IPEndPoint(ip.Address, iPortNo);<br />
//connect to the remote host...<br />
socketList[arrcnt].Connect (ipEnd);

I think int32 is not enough for the value=70252 but I tried to change it to int64 but the IEndPoint object doesn't accept long datatype.

Kindly help me, I'm got getting any data for that particular PORT.

Thank you very much in advance
/Dabuskol

Colin Angus Mackay23-Jun-04 0:33

23-Jun-04 0:33

THE TCP/IP specification defines the port as a 16 bit integer. That gives a range of 0 to 65535. You cannot define a port outside that range.

dabuskol23-Jun-04 0:59

dabuskol

23-Jun-04 0:59

What can I do then I have 5 ports with greater than 70000. Do we have any other object that I can use for this scenario?

Thanks for the help
/Dabuskol

Colin Angus Mackay23-Jun-04 1:19

23-Jun-04 1:19

I don't know how you have any ports greater than 65535 as TCP [The underlying protocol] does not support it. It has nothing to do with the .NET Framework.

dabuskol23-Jun-04 1:26

dabuskol

23-Jun-04 1:26

Ok. I will check with our administrators why he is sending me these ports. Sorry, I'm new to IP/PORT thing

I thought it's .net problem
/dabsukol

Highlight a line that contains a string

Heath Stewart23-Jun-04 4:24

Heath Stewart

23-Jun-04 4:24

dabuskol wrote:
I think int32 is not enough for the value=70252

Your question was already answer correctly (TCP doesn't support ports about 65535), but an Int32 - if you read the documentation and if you know anything about bits - is plenty large enough to hold the value 70252.

An Int32 is a signed 32-bit integer that can hold 2^32 bits of data. Because it's signed, it can have a negative value. This value can range from -2,147,483,648 to 2,147,483,647. 70252 easily falls within that range.

As Colin said, this problem has nothing to do with .NET.

Microsoft MVP, Visual C#
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clatten22-Jun-04 23:49

clatten

22-Jun-04 23:49

Since I received good answers on my previous question I'll go for a new.

I have a richtextbox and like to highlight lines that contain a specific string.
I'v found the .Find method which lets me search for a string and then with the selection methods I can highlight by changing font and foreground colour etc.
But the problem is that only the search string becomes selected and not the whole line. Also only the first occurrence is selected but I guess that's solvable.

Is there some way to achieve this with .Find or is there any other way I can/should go?

Re: Highlight a line that contains a string

LongRange.Shooter23-Jun-04 3:20

LongRange.Shooter

23-Jun-04 3:20

Looking at the richtext control in a prototype project I built, it indicates that display.Find() returns an index of the found line of text.

So it may be possible to make use of the display.GetLineFromCharIndex() using the result form Find();

So your final code would be this:

RichTextBox display = new RichTextBox();
 ...
public void SetLine(string textToSelect)
{
     int locate = display.Find(textToSelect);
     int linePos= display.GetLineFromCharIndex(locate);
     this.SetSelectedStyle();
     display.SelectedText = display.Lines[linePos];
}

The approach I took to determine this was to create a blank project.
Add a richtext control.
Create a dummy method in the project so that I can see exposed properties and methods.
Start looking at 'WHAT' for the return type and description of Find();
See what is exposed that deals with lines based on character position.
See what collection might be used for the output of that.

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Re: Highlight a line that contains a string

clatten23-Jun-04 11:44

clatten

23-Jun-04 11:44

OK, I tried that and it worked somehow but there's still a problem.

Given the code below I search for the string "string" and then select the line that contains the string "This is the string I search for". The result will be that string is replaced and highlighted and thus giving:

"This is the This is the string I search for I search for".

I have tried several solutions avoiding this, but I assume I need to use SelectedText.Replace or set Select to start from the beginning of the line
But I can't find out a way to calculate where the line starts and ends.

Anyone that can hint how to proceed?

private void WinForm_Load(object sender, System.EventArgs e)
{
richTextBox1.Text = "Hello world\n";
richTextBox1.AppendText("This is the string I search for\n");
richTextBox1.AppendText("The last row\n");
}

}

private void button1_Click(object sender, System.EventArgs e)
{
int locate = richTextBox1.Find("string");

int line = richTextBox1.GetLineFromCharIndex(locate);
richTextBox1.SelectionColor = Color.Red;
richTextBox1.SelectedText = richTextBox1.Lines[line];
string q = richTextBox1.Lines[line];;
richTextBox1.SelectionProtected = true;
int len = richTextBox1.Lines[line].Length;
string txt = richTextBox1.Lines[line];
richTextBox1.SelectionCharOffset = 5;
richTextBox1.AppendText("Line no: " + line + ", Locate: " + locate + ", Len: " + len + "\n");
richTextBox1.AppendText(txt + "\n");
richTextBox1.AppendText("q: " + q);
}

Re: Highlight a line that contains a string

clatten23-Jun-04 21:57

clatten

23-Jun-04 21:57

Dunno what I was thinking about yesterday since it was pretty obvious.

private void onLoad(object sender, System.EventArgs e)
{
richTextBox1.Text = "Hello World\n";
richTextBox1.AppendText("This is the string I search for\n");
richTextBox1.AppendText("Another Hello World Again\n");
}

private void button1_Click(object sender, System.EventArgs e)
{
int loc = richTextBox1.Find("string");
int linePos= richTextBox1.GetLineFromCharIndex(loc);
int lineLen = richTextBox1.Lines[linePos].Length;
int lineStart = richTextBox1.Lines[linePos].IndexOf("string");
richTextBox1.Select(lineStart,lineLen);
richTextBox1.SelectionColor = Color.Blue;
richTextBox1.SelectedText = richTextBox1.Lines[linePos];
richTextBox1.AppendText("strPos: " + loc + ", Len: " + lineLen + ", linestart: " + lineStart);
}

Required permissions cannot be acquired

Daniel Zaharia22-Jun-04 23:25

22-Jun-04 23:25

I want to access a class (TestClass) that is in a given assembly(Test.dll) on my machine.
I use activator :

ObjectHandle objH=null;
objH=Activator.CreateInstanceFrom(@"\\Daniel\SharedDocs\Test.dll","TestClass");
TestClass tc=(TestClass)objH.Unwrap();
MessageBox.Show(tc.GetCompName());

But I get this error : "Required permissions cannot be acquired."

What should I do?
Thanks,
Daniel.

Jochen Kalmbach [MVP VC++]

Jochen Kalmbach [MVP VC++]23-Jun-04 0:44

23-Jun-04 0:44

You should not load the DLL from a network path... instead use a local copy. Or change the default security settings in "Control Panel".

Daniel Zaharia23-Jun-04 1:37

23-Jun-04 1:37

The exception type is : System.Security.Policy.PolicyException
I think it has somthing to do with SecurityPermission and ReflectionPermission...

Jochen Kalmbach [MVP VC++]

Jochen Kalmbach [MVP VC++]23-Jun-04 1:57

23-Jun-04 1:57

Daniel Zaharia wrote:
The exception type is : System.Security.Policy.PolicyException
I think it has somthing to do with SecurityPermission and ReflectionPermission...

No, it has something to do with the Policy!!!

So either change your policy to allow executiong ffrom network shares or change the way you load your assembly!

Heath Stewart23-Jun-04 4:19

Heath Stewart

23-Jun-04 4:19

You need to add a code group with a URL or Site membership condition with the necessary privileges (or simply FullTrust permissions) for the directory (or any parent directory) to allow execution from that directory.

For example, using a URL membership condition, use file://MYSERVER/SHARE/* or something like that. Be sure to add the asterisk at the end as a wildcard unless you only want to apply the policy to only one assembly (which, of course, you should include the assembly name).

You should read Understanding .NET Code Access Security[^] here on CodeProject for more information. It's a good read and a comprehensive resource of what you can find scattered throughout the .NET Framework SDK.

Microsoft MVP, Visual C#
My Articles

Daniel Zaharia23-Jun-04 4:37

23-Jun-04 4:37

Thanks!
Daniel.

Daniel Zaharia23-Jun-04 2:06

Re: Registration page woes

23-Jun-04 2:06

I get the same error even if i try to load the assembly from the same directory with the executing assembly.

objH=Activator.CreateInstanceFrom("Test.dll","TestClass");

Registration page woes

diptea22-Jun-04 23:18

diptea

22-Jun-04 23:18

Can some1 pls tell me what's wrong with my coding? thank u.

<%@ Page Language="C#" Debug="True" %>

int AddUser(string fname, string sname, string username, string password)
{
string connectionString = "server=\'\'; user id=\'\'; password=\'\'; databas" +
"e=\'\'";
System.Data.IDbConnection dbConnection = new System.Data.SqlClient.SqlConnection(connectionString);

string queryString = "INSERT INTO [Members] ([fname], [sname], [username], [password]) VALUES (@fname, " +
"@sname, @username, @password)";
System.Data.IDbCommand dbCommand = new System.Data.SqlClient.SqlCommand();
dbCommand.CommandText = queryString;
dbCommand.Connection = dbConnection;

System.Data.IDataParameter dbParam_fname = new System.Data.SqlClient.SqlParameter();
dbParam_fname.ParameterName = "@fname";
dbParam_fname.Value = fname;
dbParam_fname.DbType = System.Data.DbType.String;
dbCommand.Parameters.Add(dbParam_fname);
System.Data.IDataParameter dbParam_sname = new System.Data.SqlClient.SqlParameter();
dbParam_sname.ParameterName = "@sname";
dbParam_sname.Value = sname;
dbParam_sname.DbType = System.Data.DbType.String;
dbCommand.Parameters.Add(dbParam_sname);
System.Data.IDataParameter dbParam_username = new System.Data.SqlClient.SqlParameter();
dbParam_username.ParameterName = "@username";
dbParam_username.Value = username;
dbParam_username.DbType = System.Data.DbType.String;
dbCommand.Parameters.Add(dbParam_username);
System.Data.IDataParameter dbParam_password = new System.Data.SqlClient.SqlParameter();
dbParam_password.ParameterName = "@password";
dbParam_password.Value = password;
dbParam_password.DbType = System.Data.DbType.String;
dbCommand.Parameters.Add(dbParam_password);

int rowsAffected = 0;
dbConnection.Open();
try {
rowsAffected = dbCommand.ExecuteNonQuery();
}
finally {
dbConnection.Close();
}

return rowsAffected;
}

void Button1_Click(object sender, EventArgs e)
{
if AddUser(txtUserName.Text, txtUserPassword.Text) > 0
Message.Text = "Success";
else
Message.Text = "Failure";

}

<asp:label id="Label1" runat="server">User Name
<asp:textbox id="txtUserName" runat="server">

<asp:label id="Label2" runat="server">Password
<asp:textbox id="txtUserPassword" runat="server" textmode="Password">

<asp:label id="Message" runat="server">

<asp:button id="Button1" onclick="Button1_Click" runat="server" text="Register">

Colin Angus Mackay22-Jun-04 23:39