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Download and install the DirectX SDK.
Take a look at the PlayCap sample application which installed to C:/DXSDK/Sample/C++/DirectShow/Capture/Playcap for a default installation. It describes how to get a capture graph up and going. Modify the graph to include a ?sample?grabber filter (the name depends on the version of the SDK). Modify the application to grab and parse jpegs.
There is a fair bit of work involved in doing this, but enough people on Codeproject know how to use DirectShow so you should get plenty of help
If you can keep you head when all about you
Are losing theirs and blaming it on you;
If you can dream - and not make dreams your master;
If you can think - and not make thoughts you aim;
Yours is the Earth and everything that's in it.
Rudyard Kipling
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Well, I've been working for a few weeks with directshow, and working whith the capture graph isn't really a problem anymore.
its the parsing of these Jpegs that troubles me. I Have no idea how to make a stream out of these and using them with in Directshow.
I use Wininet to download one jpeg and save it to a file at a time, and I can show this with using RenderFile(c:\\"example.jpg") or something. I just don't know how to stream these jpegs. (the camera has a webserver where a jpeg image is refreshed constantly).
thanks for the reply btw
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I'm speculating - your application doesn't seem to be as similar to what I was using DirectShow for as I first thought. Have you looked at the PushSource Filter? It pushes bitmaps from files, but I'm sure it could be modified to either push jpegs or to convert jpegs in bitmaps and then push them into a graph.
If you can keep you head when all about you
Are losing theirs and blaming it on you;
If you can dream - and not make dreams your master;
If you can think - and not make thoughts you aim;
Yours is the Earth and everything that's in it.
Rudyard Kipling
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I think I'll try working with this filter, I'll let you know if i accomplish something
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Hi,
I am using a CView to display a GDI+ image. My problem is when I change the image displayed i want to erase the background first. Invalidate(true) appears to have no effect, does anyone know why this is the case? Any clues at all would be appreciated!
Cheers
Rich
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doh!, please ignore this my logic was a bit screwed up. Wasn't clearing one of my GDI+ Graphics objects.
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How create a .lib from a .cpp & its .h ?
And that's in order to use some functions which are defined in.
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if you are using Visual Studio, just try something bellow:
1. Select File -> New -> Projects -> Win32 Static Library
2. Specify Project Name and Location
3. Add all your files into project with command: Project -> Add to project -> Files
4. Make any setting that you need and build
In order to re-use library function:
1. Include headers which declare functions into file where you plan to use that functions
2. In project setting, at Link tab -> Object/ Library modules, type the path points to your lib file
3. Build
There is an easier way to re-use library function from lib file if you add that library project to your current project and set the dependency between them correctly (Project -> Dependencies)
Have fun.
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Thank's it works well 
And very easy to run...
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Hi everybdoy!
I developed a program under Mfc and VisualC++, SP5. After installing the program and all the components (i. e. controls) under Win98 (not SE), I get a black screen. When I click around and hit a control, it appears back, the rest stays black.
Under Win2000 it works fine without any problems.
Now I need your help:
Where could the problem be located?
How can I resolve this problem?
Thank you very much for your help
Brennivin
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what do you mean by black screen? does the program or the os not react anymore?
Don't try it, just do it! 
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No, there is just no picture! If you finish the program, it appears back and you can work on without any problems. And if you click left on a control, you see just this control, the rest is black.
Greets
Brennivin
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Hi Friends,
Can anyone tell me what is the alternative of CreateRemoteThread in Win98 . How can i create a thread in Remote Process in Win98 operating system.
Thanx in advance !
Kuldeep
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there are a couple of articles here at cp that show a ballon help one is CPPTooltip and another is by shog.
calculate the coordinates of ur tray icon (easier said than done )
and show the ballon help
i can't even remember what my point is now, but anyway, i'm correct
Barring unforeseen acts of God and Adminstrators, my server will be up tomorrow. I'm more worried about the Adminstrators.
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Michael Dunn wrote:
On XP, use the IUserNotification interface provided by the shell. On earlier OSes, you'll need to handle adding/removing the icon yourself.
Thanx for the advice, but my software is targeted for varity of OS's so i cant use it even if i want to.
But i figured out that NIF_INFO in NOTIFYICONDATA by using Shell_NotifyIcon does the samething.
But i havent test it yet but seems like that what i am looking for.
I'll write a suicide note on a hundred dollar bill - Dire Straits
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I have the following snippet of code:
for(int i=nIndex; i>=0; i--){
if(csBuff[i]==chDelim || csBuff[i]==LF) break;
}
I thought it would decrement i until a deliminator was found or until i == 0 in which case it would not execute anything inside the loop, nor would it decrement i anymore either...
to my surprise i is -1 and it's driving me nutts...
someone tell me this is normal or indicate the bug in my code....
Should I just test after the loop and make sure -1 becomes ZERO...like I thought it would and all post code assumes as well...?
Thanks
Cheer s
How do I print my voice mail?
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Hockey wrote:
I thought it would decrement i ... until i == 0
No, the loop runs as long as the condition i>=0 is true. When i is 0, the test becomes 0>=0 which is true, so the loop runs. If you want to stop when i is 0, the test should be i>0
--Mike--
Personal stuff:: Ericahist | Homepage
Shareware stuff:: 1ClickPicGrabber | RightClick-Encrypt
CP stuff:: CP SearchBar v2.0.2 | C++ Forum FAQ
----
There is a saying in statistics that a million monkeys pounding on typewriters would eventually create a work of Shakespeare. Thanks to the Internet, we now know that this is not true.
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I understand true would cause the loop to iterate again, but I still can't get the code working...
I'm trying to extract a word given an offset into a buffer using space as delimiters, this is what I have so far and it doesn't work...and I have no idea why...
for(int i=nIndex; i>0; i++){
if(csBuff[i]==chDelim || csBuff[i]==LF) break;
}
for(int j=i; j<csBuff.GetLength(); j++){
if(csBuff[j]==chDelim || csBuff[i]==CR) break;
csWord += csBuff[j];
}
Any idea?
Thank again
How do I print my voice mail?
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Hockey wrote:
for(int i=nIndex; i>0; i++){
Are you sure that i++ is intentional? That, coupled with the i>0 condition, means that this is potentially a "forever" loop. The only thing that would cause the loop to exit, besides i becoming negative after about 231, would be if either of the conditions in the if statement were true.
"The pointy end goes in the other man." - Antonio Banderas (Zorro, 1998)
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May be he typeoed coz his original post has i--;
I'll write a suicide note on a hundred dollar bill - Dire Straits
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Yes, that notion was considered.
"The pointy end goes in the other man." - Antonio Banderas (Zorro, 1998)
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It is normal.
Remember that the syntax of for statement is defined as:
for(init_statement ; condition ; expression) exp_2;
The expression (in the case, i--) will continue to work (decrement) till the condition becomes false, then the execution leaves the for loop. In the case, i>=0 is still true while i is zero at that time, thus the expression (i--) will be executed once more to expect the condition to become false.
If you hope it exit the for loop at the time i = 0, you may write this way:
for(int i = nIndex; ; i--)
{
if(csBuff[i] == chDelim || csBuff[i] == LF)
break;
if(0 == i)
break;
}
Maxwell Chen
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How do i show a balloon window with my trayicon to show some events accoring.
The balloon window similar to what you get when a new hardware is detected by windows.
Regards.
I'll write a suicide note on a hundred dollar bill - Dire Straits
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