XML / XSL

ZoogieZork9-Jan-04 2:06

ZoogieZork

9-Jan-04 2:06

Works fine here. Have you set the JAVA_HOME and CATALINA_HOME environment variables? (The first should be set to your Java SDK path, e.g., C:\j2sdk-1.4.2, and the second to your Tomcat path, e.g., C:\tomcat).

Also, the current version of the Java SDK (previously known as the "JDK") is 1.4.2. Get it here:
http://java.sun.com/j2se/1.4.2/download.html[^]

- Mike

The_Server9-Jan-04 2:18

The_Server

9-Jan-04 2:18

10x...

I guess the JAVA_HOME environment variable was missing.

cause after I added it, the Tomcat server start.
...

Now,
Only to create a database.
And create a .jsp file that will connect to that database
and generate an HTML.

Tips about how to and/or where to start from...
Will be mostly appricated.

=-=-=-=-=-=-=
The-Server Rose | [Rose]

ZoogieZork9-Jan-04 17:28

ZoogieZork

9-Jan-04 17:28

You really should focus on one thing at a time. First, play around with JSP to get an idea of how it works and get a feel for writing dynamic pages with JSP. There are plenty of tutorials for this, just check Google. Here's one that I ran across:
http://www.jsptut.com/[^]

Next, get familiar with a database system. MySQL is a popular choice for getting started, since it's free and has a Win32 version:
http://www.mysql.com/downloads/mysql-4.0.html[^]
There's also PostgreSQL, which is more powerful but trickier to get started with.

Finally, you can put them together. The standard way to interface with a database in Java is through JDBC. Simple tutorial:
http://java.sun.com/docs/books/tutorial/jdbc/[^]

- Mike

RSS Feed not displaying properly

The_Server10-Jan-04 21:46

The_Server

10-Jan-04 21:46

One more question,
A litle less, but still importent:

I have linux mandrake.
and I need to install the JDK
so I downloaded the file: JDK_file.rpm.bin
And executed it from the using the linux command: . JDK_file.rpm.bin
After the extrection...
I typed: ls. and saw the list of files.
2 files were there:
JDK_file.rpm.bin
and
install.something.1157

How do I run the .something file??

=-=-=-=-=-=-=
The-Server Rose | [Rose]

AAntix7-Jan-04 8:02

AAntix

7-Jan-04 8:02

I have a problem :

I have been developing an RSS feed in PHP. I have used the following RSS validator, and it states that it is valid RSS output :
http://feedvalidator.org/check?url=http%3A%2F%2Fqtextender.com%2Fforum%2Findex.php%3Fact%3Dmodule%26module%3Drecent%26limit%3D10%26admin_forums%3D%287%2C9%29

That is for the following url :
http://qtextender.com/forum/index.php?act=module&module=recent&limit=10&admin_forums=(7,9)

The problem is, when I enter the above url, it doesn't display at all within Internet Explorer. Why doesn't it display like The Codeproject's RSS feed?
http://www.codeproject.com/webservices/articlerss.aspx?cat=2

Do I need to output any specific headers?

Here's a link[^]
(the tages gets screwed up when trying to display in this forum) to the code.

Any help would be appreciated.

Jim
QTExtender - The OFFICIAL addon for QuoteTracker.

XSLT of data extracted via XPath?

AndrewCherry3-Jan-04 17:01

AndrewCherry

3-Jan-04 17:01

I know this really shouldn't be defeating me, but... I have a page where i'm using XSLT to transform a simple XML document (forum postings). This works fine, but if I want to display just one topic, i'm finding myself stuck. Using c# I can create an XmlNodeList containing the XML that I want, by performing a SelectNodes on an XmlDocument. This gives me the right data back, my XPath expression is fine. But! How do I then apply an XSL transform to that resulting nodelist? XSLT on seems to like XMLDocs, etc. Can I convert a NodeList to a Doc? I'm really stuck!

Am I going about this the wrong way? Any help, or hints, anything, would be very gratefully received!

Re: XSLT of data extracted via XPath?

avnrao4-Jan-04 23:37

avnrao

4-Jan-04 23:37

You can use for-each statement in xslt and loop thru in xslt. But anyway you have to pass XMLDocument, not XMLNodeList. Pass the XPath as a parameter to XSLT or you can hardcode in xslt if it doesnt change.

You can check MSND for how to use for-each statement and Passing parameters to XSLT.

xml transform

samo7a2-Jan-04 11:10

samo7a

2-Jan-04 11:10

hi to u

, my project that i need asp.net program that take two file ,file of xml the other of dtd file , and take tha data from it and put it in database as access for example plz if u can help me plz u or ur freind plzzzzzzzzzzzz

samah

plz

Re: xml transform

Heath Stewart2-Jan-04 11:51

Serializing web server controls

2-Jan-04 11:51

Since you're using ASP.NET, just take advantage of the easy-to-use Xml web control. Give it an XML document, XSLT document, and render it (ASP.NET will do this when sending the response to a client browser). If you need this in a database, you can render it yourself and save the resulting document to a database.

You could also do this manually using the System.Xml.XmlDocument and System.Xml.Xsl.XslTransform classes. They do contain example source code.

-----BEGIN GEEK CODE BLOCK-----
Version: 3.21
GCS/G/MU d- s: a- C++++ UL@ P++(+++) L+(--) E--- W+++ N++ o+ K? w++++ O- M(+) V? PS-- PE Y++ PGP++ t++@ 5 X+++ R+@ tv+ b(-)>b++ DI++++ D+ G e++>+++ h---* r+++ y+++
-----END GEEK CODE BLOCK-----

Rafik2-Jan-04 10:33

Rafik

2-Jan-04 10:33

I have a web user control that contains some web server controls (Label, Texrbox, ddl,....) and I need to save the settings of those user control in an XML file using XML serialization. When I try to serialize any web server control I get the following error message:

"Can't serialize web control because there is no default constructor"

Please Help.

Re: Serializing web server controls

Heath Stewart2-Jan-04 11:49

Serializing Arrays in .NET

2-Jan-04 11:49

Classes need default constructors (constructors with no parameters) in order to serialized using the XmlSerializer. You'd have to extend these and implement a default constructor in the class itself.

mohn331031-Dec-03 15:07

mohn3310

31-Dec-03 15:07

Hi,

I'm serializing an array of objects using XML Serialization. Using attributes you can customize what the xml element names will be. If you serialize an array, the root name is prefixed with "ArrayOf". How do you change that? I tried using the [XmlArray( Elementname = "SomethingElse") ] attribute on the array, but it didn't seem to work.

I've seen examples where they use the "XmlRoot" attribute on the class name. But I'm serializing JUST the array, NOT a class. So I can't use that.

Basically here's what I have...

I have

MyType[] myArray;

and I want to serialize that...

XmlSerializer xs = new XmlSerialize( typeof( MyType[] ) );
xs.Serialize( fileStream, myArray );

I get...

<arrayofmytype>
<mytype>...
<mytype>...

Is there anyway to change <arrayofmytype> to something else?

Thanks.

mohn331031-Dec-03 15:09

mohn3310

31-Dec-03 15:09

The XML didn't show up

I get...

<?xml version="1.0" encoding="utf-16"?>
<ArrayOfMyType>
<MyType>...</MyType>
<MyType>...</MyType>
<MyType>...</MyType>
</ArrayOfMyType>

Heath Stewart2-Jan-04 11:44

2-Jan-04 11:44

Unfortunately, this doesn't seem possible using the System.Xml.Serialization attributes. On this and another site a long time ago, several other people and I discussed this and came up with nothing. You can control the XML serialization if you implement the undocumented IXmlSerializable interface, however, but you'll have to implement this in a class that contains the array since you can't actually implement an array class yourself (although you could implement and use a collection or list instead).

mohn33102-Jan-04 14:16

mohn3310

2-Jan-04 14:16

Thanks for your reply.

Could you point me to the discussion?

Heath Stewart2-Jan-04 19:44

extract data from xml document

2-Jan-04 19:44

You can search for the discussion in google, since both DevHood and CodeProject are well-indexed.

I will point you to two articles that were the results of those discussions:

Both of these end up in wrapping a list or array in a class to be serialized, but then that gives you control over what exactly is serialized. Otherwise, make a collection or a list class as I mentioned before, and implement IXmlSerializable, which is pretty easy to implement, though undocumented.

samo7a30-Dec-03 11:06

samo7a

30-Dec-03 11:06

i have software project about ( how to extract data from XML document ) and read ur page and plz i would be grateful if u could send me some help in this subject

plz help me
samo7a

Re: extract data from xml document

Nick Parker2-Jan-04 6:55

Nick Parker

2-Jan-04 6:55

Please be more specific, if you have a particular question with a defined scope there are many who are willing to help.

- Nick Parker
My Blog

Problem with transformation result

tamekyle30-Dec-03 9:09

tamekyle

30-Dec-03 9:09

I am trying to dynamically create web sites using xml/xsl transformations, but am having trouble with the formatting of the output html.

My code looks like this:

Dim xslDoc As XslTransform = New XslTransform()<br />
        <br />
xslDoc.Load(sXslDoc)<br />
xslDoc.Transform(sXmlDoc, sNewHtmlFile)

The problem is the my HTML output is formatted with indentation and carriage returns for every new tag, like an XML document:

<tr><br />
  <td width="209px" height="49px" bgcolor="#FFFBE6"><br />
    <img border="0" src="images/logo.gif"><br />
  </td><br />
  <td width="66px" height="49px"><br />
    <img src="images/banner03.gif" width="66px" height="49px" alt=""><br />
  </td><br />
</tr>

And I want it to look like this:

<tr><br />
  <td width="209px" height="49px" bgcolor="#FFFBE6"><img border="0" src="images/logo.gif"></td><br />
  <td width="66px" height="49px"><img src="images/banner03.gif" width="66px" height="49px" alt=""></td><br />
</tr>

Without puting carriage returns before every new tag, because it seems to be screwing up how it displays in the browser. I have a lot of cells with images in them and it looks like the carriage returns are putting spaces or something after the images and everything gets thrown off, and my pages look like crap!!

Any ideas? Confused | :confused:

Re: Problem with transformation result

Heath Stewart31-Dec-03 11:23