C / C++ / MFC

void main ()
{
 int number
 
 cout<<"CHARACTER \t\ How many times it appeared"<<endl;

 for (number='01'; number<='49'; number++)
 {
  cout<<number<<" - \t"<<countNumber(numbercount)<<" times"<<endl;
  cout<<number<<" paired with \t"<<number<<" "<<ountNumber(numbercount)<<" times"<<endl;
 }

 
 system ("PAUSE");
 return 0;
}

int countNumbers (int number)
{
 ifstrem.stream; //to open the file
 int numbercount;
 int count=0; //counter to count occurences

 stream.open ("countNumbers.txt"); //this opens the file
 stream.get (numbercount);

 while (!stream.fail())
 {
  if (numbercount==number)
    count++
    stream.get(numbercount);
 }

stream.close ();

return numbercount;
}

Good afternoon

I am new in c++. I am trying to write a code that uses an array of 2 exponent 32, A small example is the code below.


#include <iostream>
# include <stdio.h>
# include <fstream>
# include <string.h>
# include <iostream>
#include <math.h>  
# include <stdlib.h>  
#include <cstdio>
#include <cmath>
#include <cstring>
#include <limits>
#define two_power(n) (1u << (n))
using namespace std;  


typedef unsigned long  word32; 

int main()
{
	word32 delta, alfa;
	static word32 array[4294967295][4294967295] ={0};
	for (delta = 0; delta < 4294967296; delta++)
	{
		for (alfa = 0; alfa < 4294967296; alfa++)
		{
			array[delta][alfa] = alfa + delta;
		}
	}
	cout << array[4294967295][4294967295];
	return 0;
}



I there any method I can use to instead of using array because arrays have limitation in size. 2^32 = 4294967296. You can send me an email if you have an answer

kdmuthavhine@gmail.com