The Weird and The Wonderful

Rick York wrote:

t is so entwined with the rest of my framework it would be difficult to extract and isolate. I have stuff like multiple trace contexts, editable colors on a per-thread basis, and other stuff

M.D.V.

If something has a solution... Why do we have to worry about?. If it has no solution... For what reason do we have to worry about?
Help me to understand what I'm saying, and I'll explain it better to you
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Ranges and Progressions - Kotlin Programming Language[^]:

if (i in 1..4) {  // equivalent of 1 <= i && i <= 4

To iterate a number range which does not include its end element, use the until[^] function

Richard Deeming wrote:

Updating your example[^] to use until produces the expected result.

// like 0..0 in Kotlin
// prints x 0
for (int x=0;x<=0;x++){
   Console.WriteLine($"x {x}");
}

// like 0 until 0 in Kotlin
// no output
for (int x=0;x<0;x++){
   Console.WriteLine($"x {x}");
}

foreach(var item in 1..100)
{
  Console.WriteLine(item);
}

TheGreatAndPowerfulOz wrote:

foreach (var in list) { ... }

List<int> allInts = new List<int>();
Console.WriteLine($"There are  {allInts.Count} items in the list");
foreach (var x in allInts){
	Console.WriteLine(x);
}
//output : There are  0 items in the list

TheGreatAndPowerfulOz wrote:

foreach(var item in 1..100)

int[] numbers = Enumerable.Range(0, 20).ToArray();
foreach (int i in numbers[1..10])
{
    Console.WriteLine(i);
}

/*
Output:
1
2
3
4
5
6
7
8
9
*/

What's new in C# 8.0 - C# Guide | Microsoft Docs[^]:

The start of the range is inclusive, but the end of the range is exclusive, meaning the start is included in the range but the end isn't included in the range.

foreach(var item in Enumerable.Range(1, 10))
{
  Console.WriteLine(item);
}

TheGreatAndPowerfulOz wrote:

Since a range is a set, and you're asking to iterate the set, then it's working exactly as I would have expected.

TheGreatAndPowerfulOz wrote:

But the set from 0 to 0 is not empty, there is one item in it: 0.

for (i in 0..allItems.count){
    allItems.getItem(i);
}

for (i in 0..allItems.count - 1){
    allItems.getItem(i);
}

raddevus wrote:

thinking about iterating over a set of item

for value in 1 to 3
    print value
done

TheGreatAndPowerfulOz wrote:

But the set from 0 to 0 is not empty, there is one item in it: 0.

fn main() {
    for i in 0..=0 {
        print!("0..=0: {}\n", i);
    }
    for i in 0..0 {
        print!("0..0: {}\n", i);
    }
}

0..=0: 0