Re: How to randomly generate a number or characters in an Authorization Class file - C# Discussion Boards

Incomprehensible errors. Any anybody help me make sense of this?

18-Jul-18 14:02

Your project is "confused"; you need to clean it up ... literally.

C:\Users\Desktop\C prog\Spring 2018 New List View Macro Box Tester - Copy (4) - Copy\Spring 2018 New List View Macro Box Tester\Form1.resx 133

"(I) am amazed to see myself here rather than there ... now rather than then".
― Blaise Pascal

Member 1207484918-Jul-18 6:49

Member 12074849

18-Jul-18 6:49

I had been working on a program for quite some time. For some reason, though the code was running, the design mode got screwed up. There are several errors.

1. One of my custom controls no longer seems to have design mode available at all. It now just looks like C# code and not a custom control and when I double-click on it in the solution explorer no design mode comes up.

2. Another user control (that makes use of the previous control mentioned) cannot be changed on the main form at all. When I try to edit or even delete it I get this error:

"An error occurred while processing this command: Type 'Spring_2018_New_List_View_Macro_Box_Tester.lineItemData' in Assembly 'Spring 2018 New List View Macro Box Tester, Version 1.0.0.0, Culture = neutral, PublicKeyToken=Null' is not marked as serializable."

And under output I get "The program '[16676] Spring 2018 New List View Macro Box Tester.exe: Program Trace' has exited with code 0 (0x0).
The program '[16676] Spring 2018 New List View Macro Box Tester.exe' has exited with code 0 (0x0).

Thanks,
FC

Re: Incomprehensible errors. Any anybody help me make sense of this?

Gerry Schmitz18-Jul-18 13:24

How to randomly generate a number or characters in an Authorization Class file

18-Jul-18 13:24

The "project properties" of a file can get fouled; causing the "Designer" to have issues.

Sometimes you can just "add" the "item" back as an existing item.

Sometimes you have to create a "new" control and paste your existing code back in.

I've had 3rd party projects that refused to honor my "text formatting rules" until I "rebuilt" some files.

A project file "fix" may help; but can also make the entire project (file) unusable if done wrong.

"(I) am amazed to see myself here rather than there ... now rather than then".
― Blaise Pascal

Bootzilla3317-Jul-18 4:49

Bootzilla33

17-Jul-18 4:49

I need help creating a class file that randomly generates a number of 10 characters, 0-9, A-Z. By generating a PIN it will create an authorization workflow to allow the user to authenticate the app. This number will be directed to a config file instead of a URL. The user goes thru a auth process and instead of calling back a URL there will be a page to randonly generate a pin. The randomly generated PIN will be stored in a database table.

For the database columns would get set properties be the best approach for each column in that table? Would this be the best approach for REST API? I am not very familiar with API's. Something like this

public class AuthorizationPIN
    {
        public int Id { get; set; }
        public string AccessCode { get; set; }
        public string PIN { get; set; }

    }

Re: How to randomly generate a number or characters in an Authorization Class file

Gerry Schmitz18-Jul-18 9:38

Re: How to randomly generate a number or characters in an Authorization Class file

18-Jul-18 9:38

You show one small component (of a larger process) and ask for "opinions".

At this point, it is neither right nor wrong.

"(I) am amazed to see myself here rather than there ... now rather than then".
― Blaise Pascal

Bootzilla3318-Jul-18 10:38

Bootzilla33

18-Jul-18 10:38

Another smarmy smartass. Wow you are you f***ing dumb. I don't have any other code besides what I posted. I don't know where to begin with code to generate a PIN number that's why I asked!

F*** off a**hole seriously. I don't want to hear it from the moderators. There is no excuse for responding to me the way this guy responded to me. None!

Re: How to randomly generate a number or characters in an Authorization Class file

Gerry Schmitz18-Jul-18 13:06

Re: How to randomly generate a number or characters in an Authorization Class file

18-Jul-18 13:06

LOL.

How do I generate a random int number in C#? - Stack Overflow

And then you use a "substitution" cipher.

(And keep your foul mouth out of my personal email box).

"(I) am amazed to see myself here rather than there ... now rather than then".
― Blaise Pascal

modified 18-Jul-18 19:15pm.

Mycroft Holmes18-Jul-18 14:10

Mycroft Holmes

18-Jul-18 14:10

And with a response like that you are hoping for support from a bunch of volunteers. If you don't like the response he gives you then ignore him as you will probably be ignored in the future.

Never underestimate the power of human stupidity
RAH

The animation of my character runs on the spot

Member 1391486817-Jul-18 1:24

Member 13914868

17-Jul-18 1:24

Hello,
I have a probleme with the animation of my caracter. The animation run when my caracter stay put. I use Unity3D

<br />
using System.Collections;<br />
using System.Collections.Generic;<br />
using UnityEngine;<br />
<br />
public class PlayerMove : MonoBehaviour {<br />
<br />
    private Animator anim;<br />
    private CharacterController charController;<br />
    private CollisionFlags collisionFlags = CollisionFlags.None;<br />
<br />
    private float moveSpeed = 5f;<br />
    private bool canMove;<br />
    private bool finished_Movement = true;<br />
<br />
    private Vector3 target_Pos = Vector3.zero;<br />
    private Vector3 player_Move = Vector3.zero;<br />
    <br />
    private float player_ToPointDistance;<br />
<br />
    private float gravity = 9.8f;<br />
    private float height;<br />
<br />
    // Use this for initialization<br />
    void Awake () {<br />
        anim = GetComponent<Animator> ();<br />
        charController = GetComponent<CharacterController> ();<br />
    }<br />
    <br />
    // Update is called once per frame<br />
    void Update () {<br />
        MoveThePlayer ();<br />
        charController.Move (player_Move);<br />
<br />
    }<br />
<br />
    void MoveThePlayer() {<br />
        if (Input.GetMouseButtonDown (0)) {<br />
            Ray ray = Camera.main.ScreenPointToRay (Input.mousePosition);<br />
            RaycastHit hit;<br />
<br />
            if (Physics.Raycast (ray, out hit)) {<br />
                if(hit.collider is TerrainCollider) {<br />
<br />
                    player_ToPointDistance = Vector3.Distance (transform.position, hit.point);<br />
<br />
                    if (player_ToPointDistance >= 1.0f) {<br />
                        canMove = true;<br />
                        target_Pos = hit.point;<br />
                    }<br />
                }<br />
<br />
            }<br />
<br />
            <br />
        <br />
        }<br />
<br />
        if (canMove ) {<br />
                anim.SetFloat ("Walk", 1.0f);<br />
<br />
                Vector3 target_Temp = new Vector3 (target_Pos.x, transform.position.y, target_Pos.z);<br />
<br />
                transform.rotation = Quaternion.Slerp (transform.rotation,<br />
                    Quaternion.LookRotation (target_Temp - transform.position),<br />
                    15.0f * Time.deltaTime);<br />
<br />
                player_Move = transform.forward * moveSpeed * Time.deltaTime;<br />
<br />
                if(Vector3.Distance (transform.position, target_Pos) <= 0.5f) {<br />
                    canMove = false;<br />
                }<br />
                <br />
            } else {<br />
                player_Move.Set (0f, 0f, 0f);<br />
                anim.SetFloat ("walk", 0f);<br />
            }<br />
<br />
    }<br />
<br />
}<br />
<br />

If someone can help me I would be grateful

Re: The animation of my character runs on the spot

Gerry Schmitz17-Jul-18 7:37

17-Jul-18 7:37

Too many "if's".

Just "move" in the Update to test that you can actually "move"; then add the "if's".

"(I) am amazed to see myself here rather than there ... now rather than then".
― Blaise Pascal

string replace

Ali Doran16-Jul-18 9:39

16-Jul-18 9:39

hello

i want to edit a file by c# string by this code

                string text = File.ReadAllText(@"c:\a.txt", Encoding.UTF8);
                string text1 = text.Replace("xx", XX");
                File.WriteAllText(@"d:\a.txt", text1);

i want to search in string and when find example replace exam\ple and 4 word after exam\ple with exam\plexxxx

problem is i dont know what is the 4 word and i want replace.

i want any like * in windows seach.

in windows search * can support all character.

Dave Kreskowiak16-Jul-18 10:42

Dave Kreskowiak

16-Jul-18 10:42

There is no wildcard support in the Replace method. You're going to have to write your own code to do search and replace with support for wildcards.

Asking questions is a skill
CodeProject Forum Guidelines
Google: C# How to debug code
Seriously, go read these articles.

Dave Kreskowiak

Peter_in_278016-Jul-18 11:40

Peter_in_2780

16-Jul-18 11:40

Sounds to me like a case for Regular expressions[^] Google will have lots of help.

Software rusts. Simon Stephenson, ca 1994. So does this signature. me, 2012

Gerry Schmitz16-Jul-18 11:46

16-Jul-18 11:46

Get the ".IndexOf" your "keyword".

Then "string.Split" the rest into tokens / words; delimited by space, coma, etc.

The first 4 tokens are your "any character words".

Replace that part of the string between the "keyword" and the last word.

"(I) am amazed to see myself here rather than there ... now rather than then".
― Blaise Pascal

jschell16-Jul-18 15:49

jschell

16-Jul-18 15:49

Looks like homework to me. And I suspect (and hope) the teacher has been teaching you something and that something is how you are supposed to be doing this.

Ali Doran16-Jul-18 17:09

16-Jul-18 17:09

i want to to write a program to correct program by edit one of bad file

OriginalGriff16-Jul-18 19:36

16-Jul-18 19:36

That's different: in that case you definitely need a different approach. Reading and treating an executable file as text will corrupt the file; what you end up with is not going to be a valid executable, because the "translation" from the on-disk binary to text loses information, and the when you write it that cannot be recovered.

You would need to read the file as binary, handle it as binary, and write it back as binary as well.

But you also don't want to use the root folder of any drive: the access is restricted and likely to become more restricted in future.

Why do you think a program has a "bad file" that a simple text replace will fix?

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Ali Doran16-Jul-18 22:38

16-Jul-18 22:38

my file is text file and not executable
this text file edit by program every run it but i want change one number after "id-number="
i dont know id-number in file but i want to change by my id number.

OriginalGriff16-Jul-18 23:07

16-Jul-18 23:07

If you don't know the number you are replacing, then you need to look closely at the file, and check that the sequence "id-number=" only appears where you want to change it - that looks like a XML or config file and it's not guaranteed to have just a single occurrence.

But changing that is a text file is trivial: a basic regex will do it:

public static Regex regex = new Regex(
      "(?<=id-number=)\\d+",
    RegexOptions.IgnoreCase
    | RegexOptions.CultureInvariant
    | RegexOptions.IgnorePatternWhitespace
    | RegexOptions.Compiled
    );
public static string regexReplace = "98765";
...
    string result = regex.Replace(InputText,regexReplace);

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Ali Doran16-Jul-18 23:34

16-Jul-18 23:34

i do it by replace method but i have a problem
look to this please
i have : id number="5421" note:5421 is different by any run program
and i want to replace by : id number="2223"
i can replace "idnumber=" by "idnumber="2223"" but 3 number of old idnumber add to my file and my file corrupt.
this file is xml and i comment it this number but program detect Extra numbers and not run.
i want a command to can select by this method

string text1 = text.Replace("hostport=\"****\"", "hostport=\"2262\"");
and * mean is all character support.
thank you for replay

OriginalGriff16-Jul-18 23:39

16-Jul-18 23:39

You can't use String.Replace - it doesn't support wildcards at all, that's why Regular Expressions exist. Look at what I gave you and get a copy of Expresso[^] - it's free, and it examines and generates Regular expressions.

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Ali Doran17-Jul-18 5:03

17-Jul-18 5:03

thank you
regex support and my problem solved

OriginalGriff17-Jul-18 5:10