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char c[]; /* compiles just fine */
char[] d; /* error */
// so followig the same 
Tis the style of this language, inasmuch to continue that style far more logical to write */
char *e;

Quote:

In C "char *" is not a type

char* c" /* is wrong, "char*" is NOT the type because there is no such thing, it's wrong, plain wrong! */
char *c  /* is the proper form */

char *c

char* c

0x01AA wrote:

Please refracte

Quote:

But at my age I may not have enough time to get it all done

*char e;

Lopatir wrote:

The article you read was written by someone that either referred to a different programming language, or doesn't understand the C/C++ language definitions; char* is not a type in C/C++.

void f(char* cptr, void* vptr)
...
int* p1 = 
...
char* cptr;
int* iptr;
void* vptr;

char* a , b, c[12], *d[5]; // ugly and prone to misinterpretation

char* a; // no ambiguities here!
char  b;
char  c[12];
char* d[5];

Chris Maunder wrote:

the variable is the type, and the type stays the type. The * goes with the variable because you're modifying defining how the variable will be using accessing the type value. You're not, as it were, modifying the type.

char* c;

char* c;

char * c;

char *c;

Member 10753505 wrote:

arrays

int x[2];
0[x] = 1[x];