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I have a combo box that I create on a dialog window by adding strings to it from a file. Once a selection is made the box shows that selection as long as I keep the window open. But after I close it and return the box is blank until it is selected again.
Is there anyway to init this to display a certain item? I have the index that I wand to set it too..
Thanks for any help
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From MSDN :
CComboBox::SetCurSel
int SetCurSel( int nSelect );
Remarks
Selects a string in the list box of a combo box. If necessary, the list box scrolls the string into view (if the list box is visible). The text in the edit control of the combo box is changed to reflect the new selection. Any previous selection in the list box is removed.
~RaGE();
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Check out CComboBox::SetCurSel / CB_SETCURSEL.
You have to be careful if the combobox is sorted, but CB_ADDSTRING gives you the "post sorting" number.
Iain.
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when using addstring, is there a way to haVE it not ssort the list? im trying to get the word 'none' to come up as default, but another choice in the listbof is 'channel1' so it comes up default. if it wasnt sorted, it would take the first string i put in and use that one. 
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Just remove the LBS_SORT style.
In the resource editor, select the combo box. Bring up its property box. On the 2nd or third tab
there is a check box for "sort". Clear the check. Compile. Enjoy!
Iain.
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ok that works great. now, if anyone sees this, is there a way to get a number returned by SetCurSel()? i need to output which value in my listbox is selected. setcursel(0) forces the first string to be selected. so, if the user changes the selected variable, a number has to be stored somewhere because the program remembers it. so....where is that number at?
*.*
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This is pretty basic stuff... You should find all this information in the MSDN libraries, or
any half-decent MFC/Win32 book.
Anyway, as I'm in a nice mood... 
Lookup:
CComboBox::GetCurSel ().
DDX_CBIndex (...).
Just about any example in the Combo Box section here on CodeProject.
Iain.
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I need to build a program that will allow me to enter a part number(s) and then bring up the corresponding information. I want to use the MFC templates. I also want to enable the program user to edit the default part number(s) if they're updated or changed later on. I want to have part numbers for 4 different machines, so I'm thinking I should write one base class with public variables and then d erive 4 new classes from it. Is this the way to do this? I'd appreciate any tips here.
What's the best way to structure the part numbers (hundreds of part numbers, eg. 8567-345-34-3453) into a program?
Do I need a database?
Thanks, Dave
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DaveE9th wrote:
Do I need a database?
That's a good place to start  . This is a perfect situation for using a database.
Ryan
Being little and getting pushed around by big guys all my life I guess I compensate by pushing electrons and holes around. What a bully I am, but I do enjoy making subatomic particles hop at my bidding - Roger Wright (2nd April 2003, The Lounge)
Punctuality is only a virtue for those who aren't smart enough to think of good excuses for being late - John Nichol "Point Of Impact"
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Hi,
I have a x.bmp file. Now i want the data extract some part of the data and store it in an another BMP file. How can i do that?
Regards
Asha
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I want to know if an IP address is in use on LAN.
Usually ping works,which can tell me whether the remote machine is alive or dead.
But it does not always do the job for the reason of firewalls or something else..
even if I 've got a result like this:
C:\>ping 192.168.28.168
Pinging 192.168.28.168 with 32 bytes of data:
Request timed out.
Request timed out.
Request timed out.
Request timed out.
Ping statistics for 192.168.28.168:
Packets: Sent = 4, Received = 0, Lost = 4 (100% loss),
Approximate round trip times in milli-seconds:
Minimum = 0ms, Maximum = 0ms, Average = 0ms
When I change my IP address to 192.168.28.168, Windows informs me that "The IP address 192.168.28.168 is already in use."
How can I know the IP is in use before I changed my IP to that and Windows popups the dialog?
What is the mechanism of Windows examing if an IP is in use?
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Hi, everybody
I have designed a dialog box using resource manager and a MSFlexGrid type pointer variable defined in its class. The OnInitDialog function looks like this:
class CViewRecordsDlg : public CDialog
{
private:
CMSFlexGrid * m_pFlxGrid;
}
BOOL CViewRecordsDlg::OnInitDialog()
{
CDialog::OnInitDialog();
// TODO: Add extra initialization here
m_pFlxGrid = (CMSFlexGrid *) new CMSFlexGrid;
ASSERT (m_pFlxGrid != NULL);
RECT rect;
GetClientRect(&rect);
m_pFlxGrid->Create(_T("CMSFlexGrid"), _T("CMSFlexGrid"), CEditView::dwStyleDefault, rect, this, IDC_MSFLEXGRID, NULL);
/*
...
Some grid Initilization here
...
*/
m_pFlxGrid->UpdateWindow();
m_pFlxGrid->ShowWindow(SW_SHOW);
return TRUE;
}
This code runs on my computer and shows grid correctly (even without calling UpdateWindow and ShowWindow methods). But on another computer grid doesn't appear (it is shown only blanked dialog box without any error message ). I am sure the FlexGrid control is registered in computers. The same code with placing FlexGrid control on dialog box using resource manager and defining a variable on it using Class Wizard works without problem on all computers.
Would you please advice me how I can solve this problem?
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Did you try putting the grid on the dialog using the resource editor?
// Afterall, I realized that even my comment lines have bugs
When one cannot invent, one must at least improve (in bed).-My latest fortune cookie
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Hi,
How can i convert 2.343434343 to 2.34 without using any spintf() atoi() command?
Reagrds
Neha
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Round up, if required
2.343434343 + 0.005
Multiply by 100.0 and cast to an int
cast to a float and divide by 100.0
Not sure if this will introduce rounding errors though, you may need to cast to a double.
If I have seen further it is by standing on the shoulders of Giants. - Isaac Newton 1676
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Any other simple ways??????
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this is already the most simple one.
However, instead of casting to int, I would call trunc()
"Der Geist des Kriegers ist erwacht / Ich hab die Macht" StS
sighist | Agile Programming | doxygen
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peterchen wrote:
I would call trunc()
Don't you mean modf()?
If I have seen further it is by standing on the shoulders of Giants. - Isaac Newton 1676
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double result = floor((x+0.005)*100.0)/100.0; This should do the job, including rounding. If you don't need rounding, remove the +0.005 bit.
Ryan
Being little and getting pushed around by big guys all my life I guess I compensate by pushing electrons and holes around. What a bully I am, but I do enjoy making subatomic particles hop at my bidding - Roger Wright (2nd April 2003, The Lounge)
Punctuality is only a virtue for those who aren't smart enough to think of good excuses for being late - John Nichol "Point Of Impact"
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Ryan Binns wrote:
double result = floor((x+0.005)*100.0)/100.0;
This won't work if x is negative. Usually when I am need to such a thing, I need to do it more than once so I just call one of my own functions to do this : eg
double RoundDecPlace( double dNumberIn, int nDecPlace )<br />
{<br />
double dMultiplier = 10 ^ nDecPlace;<br />
double dDiff = 0.5 / dMultiplier;<br />
double dSign = ( dNumberIn >= 0.0 ) ? +1.0 : -1.0;<br />
<br />
return dSign * floor( ( dSign * dNumberIn + dDiff ) * dMultiplier ) / dMultiplier;<br />
}<br />
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Anonymous wrote:
This won't work if x is negative.
Good point. Your solution won't work as written because 10 ^ nDecPlace is actually 10 XOR nDecPlace, not 10-to-the-power-of-nDecPlace. You'd have to use pow(10, nDecPlace). Other than that, your solution is good 
Ryan
Being little and getting pushed around by big guys all my life I guess I compensate by pushing electrons and holes around. What a bully I am, but I do enjoy making subatomic particles hop at my bidding - Roger Wright (2nd April 2003, The Lounge)
Punctuality is only a virtue for those who aren't smart enough to think of good excuses for being late - John Nichol "Point Of Impact"
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Ryan Binns wrote:
Your solution won't work as written because 10 ^ nDecPlace is actually 10 XOR nDecPlace, not 10-to-the-power-of-nDecPlace. You'd have to use pow(10, nDecPlace).
Yes, you are correct. I had a brain dump when I entered the text. Thanks.
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Why not just write a simple, generic rounding routine that will round to any decimal place (to the right OR left of the decimal point). EX:
double Round(double dVal, short iPlaces)
{
double dRetval;
double dMod = 0.0000001;
if (dVal < 0)
dMod = -0.0000001;
dRetval = dVal;
dRetval += (5/pow(10,iPlaces+1));
dRetval *= pow(10,iPlaces);
dRetval = floor(dRetval+dMod);
dRetval /= pow(10,iPlaces);
return (dRetval);
}
onwards and upwards...
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If the text file have UNIX format (i.e. \n instead of \r\n) then CStdioFile::GetPosition() always returns maximum value for 64 bit int, i.e. 2**64 AFTER a call to CStdioFile::ReadString().
If there was not any previous call to ReadString then all works fine.
In the original docs the no any clear information about this.
What you think about this?
<br />
CStdioFile file("C:\\file.ext", CFile::modeRead);<br />
file.ReadString(szBuf, 255);<br />
ULONGLONG dwPos = file.GetPosition();<br />
TRACE("dwPos=%I64u\n", dwPos);
file.Close();<br />
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