C / C++ / MFC

int Bad (int someval){
	int i;
	if (someval > 0){
		i = 1;
	}
	if (i == 0) return (1);
	return (0);
}

Bram van Kampen wrote:

Being Able to Run VS98 on a Win7 Platform, is another question It works with Problems and Limitations (No Help Files, The Class Browser does not work, etc)...

Voltage readings are obtained from an electrical substation once every hour for six hours (so there are six
readings).  Write a C program to perform the following checks on the substation:
a)	display all voltages that differ from the average by more than 10% of the average.
b)	display all pairs of consecutive hours where the change from the voltage at one hour
	to the next is greater than 15% of the average.


Example 1

Enter 6 voltages: 210.1 223.2 189.6 206.2 235.1 215.0
The average is 213.2 volts.
10% = 21.3 volts.
15% = 32.0 volts.

The following problems occurred:
1. Voltage at hour 3 was 189.6 volts (difference of 23.6 volts).
2. Voltage at hour 5 was 235.1 volts (difference of 21.9 volts).
3. Voltage change from hour 2 to hour 3 was 33.6 volts.


Example 2

Enter 6 voltages: 233.1 201.0 221.5 240.2 222.7 208.1
The average is 221.1 volts.
10% = 22.1 volts.
15% = 33.2 volts.

No problems were encountered.

#include <stdio.h>
#include <math.h>
#include <string.h>

int i;
float volt[6];
float avg, avg10, avg15, total, a, b;

    int main () {

  total= 0 ;
  avg = 0;
  printf("Enter 6 Volts of Machine\n");

   for ( i=0; i<6; i++) {
   printf("Type %d. volt", i+1);
    scanf("%f",&volt[i]);

  total = total + volt[i];
}
avg = total/6;
avg10 = (avg * 10) / 100;
avg15 = (avg * 15) / 100;
printf("------------------------------------------\n");
printf("The machine Avarage Voltage is %.2f\n", avg);
printf("The Machine  Avarage is%.2f\n", avg10);
printf("The Machine 15 Avarage is%.2f\n\n\n", avg15);


     for (i=0;i<6;i++) {
      a = fabs(volt[i] - avg);
    
      if( a > avg10 ) {
     printf("\nVoltage at hour %d was %.2f volts (diffrence of %.2f volts)\n\n", i+1, volt[i], a);
       }
   }


     for (i=0; i<5; i++) {

       b = fabs(volt[i+1] - volt[i]);
       if( b > avg15) {
     printf("\nVoltage change from hour %d to hour %d was %.2f\n\n", i+1, i+2, b);
       }
   }

}