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You need to specify the font family name, separated from the folder name with a #:
The folder and font family name are delimited by a # character. The folder reference may be absolute, or relative. For example, "Custom Fonts\#My Custom Font".
<TextBlock FontFamily="./resources/#Pericles Light">
"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer
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Ok, so now I have
<TextBlock Grid.Row="2"
Text="1234"
Foreground="Lime"
FontSize="40"
FontFamily="./resources/#DSEG14Modern-Bold"/>
No change
If it's not broken, fix it until it is
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Also tried
<TextBlock Grid.Row="2"
Text="1234"
Foreground="Lime"
FontSize="40"
FontFamily="pack://application:,,,/KClock;Component/Resources/#DSEG14Modern-Bold"/>
No change
If it's not broken, fix it until it is
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Figured it out!
<Grid>
<TextBlock Text="12345"
FontSize="40"
FontFamily="pack://application:,,,/Folder1/#DSEG14Modern-Bold" />
<TextBlock Text="12345"
FontSize="40"
FontFamily="pack://application:,,,/Folder1/#DSEG14 Modern" />
</Grid>
If it's not broken, fix it until it is
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[UPDATE]... Sorry formatting isnt working
OVERVIEW
I'm working on a app where I need to be able produce a "report" which involves saving a piece of a view as a PNG and displaying it in Windows Photo Viewer. So I pass in the name of the topmost element and it creates the PNG and then opens the viewer. All works fine.
Now, I need to be able to exclude specific UI elements from appearing in the report. So I've written an Attached Property called ExcludeFromReport and applied it to multiple elements in my view.
Then in my class, PrintLib, I recurse the tree looking for the DP, and if it's set, I set its Visibility to Collapsed and produce the report. This work great because I can now "turn off" specific elements from appearing in the image.
PROBLEM
However.... when the property is set set to Collapsed it hides it in the UI at runtime also. So I need to find a way to store the value of the property, turn it off, then reset it. I'm an NOT looking for the default value. The default value may or may not be the value at runtime, so it can't be used.
POSSIBLE SOLUTION
Use a dictionary to hold the DP and its value before printing, then after the print routine is done, find it in the dict and reset it to its pre-print state.
CODE
Here's my class. See last method down "SetReportProperties"
public static class PrintLib
{
public static DependencyProperty ExcludeFromReportProperty =
DependencyProperty.RegisterAttached("ExcludeFromReport",
typeof(bool),
typeof(PrintLib),
new PropertyMetadata(false));
<pre>
public static void SetExcludeFromReport(DependencyObject obj, bool value)
{
obj.SetValue(ExcludeFromReportProperty, value);
}
public static bool GetExcludeFromReport(DependencyObject obj)
{
return (bool)obj.GetValue(ExcludeFromReportProperty);
}
public static void ViewImage(string filename)
{
Process process = new Process();
process.StartInfo.FileName = "rundll32.exe";
process.StartInfo.Arguments = @"C:\WINDOWS\System32\shimgvw.dll, ImageView_Fullscreen " + filename;
process.Start();
}
public static void GenerateReportFromControl(FrameworkElement element)
{
PrepareReportElements(element);
Rect rect = VisualTreeHelper.GetDescendantBounds(element);
DrawingVisual dv = new DrawingVisual();
using (DrawingContext ctx = dv.RenderOpen())
{
VisualBrush brush = new VisualBrush(element);
ctx.DrawRectangle(brush, null, new Rect(rect.Size));
}
int width = (int)element.ActualWidth;
int height = (int)element.ActualHeight;
RenderTargetBitmap rtb = new RenderTargetBitmap(width, height, 96, 96, PixelFormats.Pbgra32);
rtb.Render(dv);
PngBitmapEncoder encoder = new PngBitmapEncoder();
encoder.Frames.Add(BitmapFrame.Create(rtb));
string filename = @"C:\temp\ReportImage.jpg";
using (FileStream fs = new FileStream(filename, FileMode.Create, FileAccess.Write, FileShare.None))
{
encoder.Save(fs);
}
ViewImage(filename);
}
private static void PrepareReportElements(FrameworkElement element, int level = 0)
{
SetReportProperties(element);
var childCount = VisualTreeHelper.GetChildrenCount(element);
for (var i = 0; i <= childCount - 1; i++)
{
var visual = (FrameworkElement)VisualTreeHelper.GetChild(element, i);
SetReportProperties(visual);
if (VisualTreeHelper.GetChildrenCount(visual) > 0)
{
PrepareReportElements(visual, i);
}
}
}
private static void SetReportProperties(FrameworkElement element)
{
var excludeFromReportIsSet = element.ReadLocalValue(ExcludeFromReportProperty) != DependencyProperty.UnsetValue;
if (excludeFromReportIsSet)
{
var exclude = (bool)element.GetValue(ExcludeFromReportProperty);
if (exclude)
{
element.Visibility = Visibility.Collapsed;
}
}
}
}
If it's not broken, fix it until it is
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I know this may sound like a bloody silly question by why not build a new view to support the print version flip to that and after printing return to your original view?
Oh wait, why not use a proper reporting tool SSRS or something?
Never underestimate the power of human stupidity
RAH
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1) These views are already in place. Creating a new view to support the requirement means duplicating each and every view that needs to be screen grabbed. Bad idea
2) Again, creating reports means more development.
What I've come up with now is simple... Set a few Attached Properties and voila! the view becomes an image.
If it's not broken, fix it until it is
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How about adding an inherited DP to the root, and using a trigger against the elements you want to hide? That way, WPF will take care of setting and resetting the visibility property on the child elements for you.
public static readonly DependencyProperty IsReportModeProperty = DependencyProperty.RegisterAttached(
"IsReportMode", typeof(Boolean), typeof(PrintLib),
new FrameworkPropertyMetadata(false, FrameworkPropertyMetadataOptions.Inherits));
public static bool GetIsReportMode(UIElement target)
{
return (bool)target.GetValue(IsReportModeProperty);
}
public static bool SetIsReportMode(UIElement target, bool value)
{
target.SetValue(IsReportModeProperty, value);
}
<Style TargetType="{x:Type Label}">
<Style.Triggers>
<Trigger Property="ns:PrintLib.IsReportMode" Value="True">
<Setter Property="Visibility" Value="Collapsed" />
</Trigger>
</Style.Triggers>
</Style>
"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer
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I have a view which populates tab controls as follows:
<TabControl x:Name="MyTabControl" ItemsSource="{Binding ViewModels}" Margin="4"
Background="#DCE8F3"
SelectedIndex="0"
BorderBrush="LightGray"
TabStripPlacement="Top">
<TabControl.Resources>
<DataTemplate DataType="{x:Type vm:SmartCardViewModel}">
<view:SmartCardView/>
</DataTemplate>
<DataTemplate DataType="{x:Type vm:RfidLogFileViewModel}">
<view:LogFileView/>
</DataTemplate>
<DataTemplate DataType="{x:Type vm:VideoLogFileViewModel}">
<view:LogFileView/>
</DataTemplate>
</TabControl.Resources>
<TabControl.ItemTemplate>
<DataTemplate>
<TextBlock Text="{Binding Name}"/>
</DataTemplate>
</TabControl.ItemTemplate>
</TabControl>
The above has been simplified for clarity.
What I want is two instances of the LogFileViewModel and LogFileView pair in the tab, one for video files and one for RFID files. However, the above does not allow me to have the same model class twice, for reasons that are fairly obvious. I have got round this by deriving classes from LogFileViewModel, called VideoLogFileViewModel and RfidLogFileViewModel, which initialise the base class appropriately. The tab control obtains the view model instances from the ViewModels property of the main view model. Hence my workaround makes sure that there are no duplicate view model class instances. However, it is inelegant.
Is there some more elegant way of doing this?
I was wondering is there is some jiggery pokery I can add to the <datatemplate> to allow it to identify a specific instance of LogFileViewModel i.e. to compare a string property with a fixed value.
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As long as you had something in there that identifies whether the template is for RFID or for video, you can use the technique I demonstrate here[^] to switch to the appropriate template. All you need is something to trigger on.
This space for rent
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Thanks Pete
This is probably ignorance on my part but I'm not sure how that would work with my case, since I want two instances of the same template visible at the same time, or more precisely, present at the same time since you can only view one tab at any given time. I need to think about this more!
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You're using two separate ViewModel instances - the appropriate template will be rendered in place based off the ControlTemplate.
This space for rent
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I was developing WPF Desktop App with several features. One of them was recording video into file from webcam(usb). I used AForge.NET Framework for implementing this. Everything was fine till we try to play saved videos in HTML5 media player. Supported video codecs by the player are not supported by AForge. AForge seems not to be a live project anymore. So I tried to recompile by myself the latest source code from AForge with suggested patches (include H.264) I found on the internet. But without any luck. I guess I have to look for any other solution instead of using AForge.
I am really confused I could not find any helpful information on the internet about recording video from C# (WPF). Maybe I am so strictly oriented the way AForge is working that I am not able to find any other types of solution anymore.
After one day spent on the internet I found out:
There is no way supported directly by Microsoft for WPF application to capture video into file (h264). The only useful Microsoft SDK for this kind features is supported just by WindowsPhone or Silverlight platforms. So to implement it I still have to use third party frameworks. There is a Project iSpyConnect similar to AForge and is still living. Maybe I can look for inspiration in there
Can anybody help please, to suggest me any kind of solution? It seems nobody needs to capture webcam video from WPF App since I could find on the internet just articles mostly older than 2013 for this theme 
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The MS Expression Encoder SDK v4 can save to some 18 different presets of H264; it is not limited to Silverlight or streaming; this is because the "pro" version required for expanded H264 functionality is the only version now available and is free (including Encoder 4 itself).
(The samples appear to include elements of what you are looking for).
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Summary:
Designer "Cannot create an instance of [UserControl]" due to not being able to find the style resource file the user-control uses, linked from within the user-control. However, the user-control itself is displayed correctly in designer, and, the user control is displayed properly when the project is built and running.
Details:
I've decided to put some sense into my project structure and moved XAML resource files under /Resources/ directory in my project.
I have a user control that resides in /UserControls/ which looks for a resource file from /Resources/GeneralTheme.xaml which is also used by the parent window. All Source properties look like Source="/Resources/GeneralTheme.xaml"
What didn't work:
*Moving just the UserControl.xaml to the root.
*Using pack://application:,,,/Resources/GeneralTheme.xaml instead of the plain alternative.
What works:
*A completely flat project structure, aka put everything under the root.
But I don't like the latter choice.
Here's how I reference my user control inside the parent window:
<UserControls:SQLFilterSettings DataContext="{Binding Path=Criteria}"/>
Here's how I reference the resource file in the User-Control xaml:
<ResourceDictionary Source="/Resources/UserControlResources.xaml" />
Any help is much appreciated!
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I am (I have to) using an XAML file as a resource from my main window.
In this simplified example, the XAML file looks like this
<Grid xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" Name="themeGrid">
<Image Height="Auto" HorizontalAlignment="Left" Margin="0" Stretch="Fill" VerticalAlignment="Top" Width="Auto">
<Image.Source>
<BitmapImage UriSource="pack://siteoforigin:,,,/Resources/image1.jpg" CacheOption="OnLoad" />
</Image.Source>
</Image>
</Grid>
The file is loaded that way (the XAML file, as well as a 'image1.jpg' file, are in a 'Resources' folder along with the exe file)
Imports System.IO
Class MainWindow
Private Sub MainWindow_Loaded(sender As Object, e As System.Windows.RoutedEventArgs) Handles Me.Loaded
loadInterface()
End Sub
Sub loadInterface()
Dim GridUri As String = System.AppDomain.CurrentDomain.BaseDirectory & "Resources\theme.xaml"
Dim fs As FileStream = New FileStream(GridUri, FileMode.Open, FileAccess.Read)
Dim sri = TryCast(System.Windows.Markup.XamlReader.Load(fs), Grid)
Me.Content = sri
fs.Close()
End Sub
End Class
..and that works nicely
Now I would like to use a label whit a font file taken in the same 'Resources' folder (the font used in this example: http://www.dafont.com/fr/digital-7.font)
<Grid xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" Name="themeGrid">
<Image Height="Auto" HorizontalAlignment="Left" Margin="0" Stretch="Fill" VerticalAlignment="Top" Width="Auto">
<Image.Source>
<BitmapImage UriSource="pack://siteoforigin:,,,/Resources/image1.jpg" CacheOption="OnLoad" />
</Image.Source>
</Image>
<Label FontFamily="pack://siteoforigin:,,,/Resources/#Digital-7" Content="Have a nice day!"/>
</Grid>
...but then the label text isn't displayed with the proper FontFamily!
What should I please do for the text of the label to be displayed using the font in the resources folder?
Thanks very much!!
PS: the font file CAN'T be in resource of the application. Think of this XAML as a theme, any font could be inside and the application couldn't have all those possible fonts in resources!
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You can always include the font as a content item. All you need to do is make sure that the font is available in the application directory. If you do this, you can then reference it like this:
<Label FontFamily="#Digital-7" Content="Have a nice day!" />
This space for rent
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I like to create a Combobox with multi column header if the Combobox is open but if i close the box only one column should be displayed.
In Forms it's very simple but in WPF i have no solution.
Either i have multi column header or i have one column in the closed Combobox but I can't get both together.
Maybe some one have a solution for me.
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Google has lots of suggestions[^]. For example, WPF Multicolumn Combobox - Stack Overflow[^].
In particular, if you change the ItemContainerStyle, rather than the ItemTemplate, and set the DisplayMemberPath appropriately, then you'll get a single column in the closed box, and multiple columns in the drop-down.
"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer
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Thanks, it's working
I was on the wrong way with ItemTemplate.
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Hi all.
In xaml, which properties i need to override to get MouseEnter, MouseLeave and IsSelected to do nothing visually in a listview. I mean change the default style by one that don't do nothing.
Thanks
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Hi,
i am looking for a simple example or orientations on how to use Grouping in virtualized datagrid in code
i have setup a wpf toolkit virtualized datagrid with entity framework and a DataGridVirtualizingCollectionViewSource by handling the QueryItems and the QueryItemCount events, and it work just fine .
now i want to add groups at runtime by code, but i didn't find any sample on how to do that .
is the QueryGroups event is what i have to implmement ? , if yes how ?
i have asked in the toolkit forum on codeplex for more than a month but got no response, so any help or orientation is welcome .
thanks and good day.
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Stop spamming the forums with your question. You have already been told that you post in one place - and Window Forms has nothing to do with WPF or Silverlight.
This space for rent
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Reposting the same demand for code every few days because nobody has done your work for you yet is considered abuse. Keep it up, and you'll be kicked off this site.
"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer
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This isn't even a question. It's ironic that someone so lazy that cannot even type a question would post the same non-question multiple times. 
There are only 10 types of people in the world, those who understand binary and those who don't.
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