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please use System.Drawing namespace in your project.
where you find the Graphics class which will give you all option to Draw anything by using cartesian co-ordinate system.
for example..
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Drawing;
using System.Data;
using System.Linq;
using System.Text;
using System.Windows.Forms;
using System.Drawing.Drawing2D;
using System.Drawing.Imaging;
namespace WaveformDemo
{
public partial class WaveDisplay : UserControl
{
[DefaultValue(10)]
int _XDivision; //Total X Division
[DefaultValue(10)]
int _YDivision;
[DefaultValue(10.0f)]//1 Volt per Division
float _voltsPerDivision;
[DefaultValue(10.0f)]//1 Sec per Division
float _timePerDivision;
[Browsable(true),DefaultValue(10)]
public int XDivisions
{
get
{
return _XDivision;
}
set
{
_XDivision = value;
}
}
[Browsable(true), DefaultValue(10)]
public int YDivisions
{
get
{
return _YDivision;
}
set
{
_YDivision = value;
}
}
[Browsable(true),DefaultValue(10.0f)]
public float VoltagePerDivision
{
get
{
return _voltsPerDivision;
}
set
{
_voltsPerDivision = value;
}
}
[Browsable(true), DefaultValue(10.0f)]
public float TimePerDivision
{
get
{
return _timePerDivision;
}
set
{
_timePerDivision = value;
}
}
public override Image BackgroundImage
{
get
{
return base.BackgroundImage;
}
set
{
base.BackgroundImage = value;
}
}
public override ImageLayout BackgroundImageLayout
{
get
{
return base.BackgroundImageLayout;
}
set
{
base.BackgroundImageLayout = value;
}
}
public WaveDisplay()
{
InitializeComponent();
_voltsPerDivision = 10.0f;
_timePerDivision = 10.0f;
_XDivision = 10;
_YDivision = 10;
_s = new Sample();
}
protected override void OnPaint(PaintEventArgs e)
{
Graphics g = e.Graphics;
if (BackgroundImage != null)
{
g.DrawImage(BackgroundImage, ClientRectangle);
}
else
{
Brush b = null;
b = new SolidBrush(this.BackColor);
g.FillRectangle(b, this.ClientRectangle);
}
Pen pen = new Pen(ForeColor);
Rectangle r = new Rectangle(ClientRectangle.Left, ClientRectangle.Top, ClientRectangle.Width, ClientRectangle.Height);
r.Inflate(new Size((int)(-ClientRectangle.Width * 0.1f),(int) (-ClientRectangle.Height * 0.1f)));
double xPixelPerDiv = (double)r.Width / (double)_XDivision;
double yPixelPerDiv = (double)r.Height /(double)_YDivision;
double TimePerUnit = _timePerDivision/_XDivision;
double VoltsPerUnit = _voltsPerDivision/_YDivision;
string s1 = null;
for (int i = 0; i <= _XDivision; i++)
{
g.DrawLine(pen, new Point((int)(r.Left + xPixelPerDiv * i), r.Top),
new Point((int)(r.Left + xPixelPerDiv * i), r.Bottom));
s1 = (_timePerDivision * i).ToString();
g.DrawString(s1, Font, new SolidBrush(ForeColor), new PointF((int)(r.Left + xPixelPerDiv * i), r.Bottom + 10));
}
for (int i = 0; i <= _YDivision; i++)
{
g.DrawLine(pen, new Point((int)(r.Left), (int)(r.Bottom - i * yPixelPerDiv)),
new Point((int)(r.Right), (int)(r.Bottom - i * yPixelPerDiv)));
s1 = (_voltsPerDivision * i).ToString();
g.DrawString(s1, Font, new SolidBrush(ForeColor), new PointF(r.Left - 15, (int)(r.Bottom - yPixelPerDiv * i)));
}
_s.Render(g,r,XDivisions*TimePerDivision);
//base.OnPaint(e);
}
Sample _s;
}
}
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Thanks, I'm aware that the math can be done manually. I was hoping for a third-party component so I could focus my efforts elsewhere and not have to focus on writing code for the existing drawing components.
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I've been searching for an answer, but I can't seem to find what I'm looking for.
Basically, I have a TTF font with some custom glyphs. I have successfully "painted" them on my OpenGL canvas (C# using Tao). My question is: is it possible to rotate the glyph (from 0-360 degrees)?
I need to be able to rotate the glyph depending on the heading data received - this way, the glyph is facing the correct direction.
If this is not possible, do you have any suggested alternatives? I've considered importing the glyph as an image and converting it to a bitmap - but I'm not sure if this will work either.
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Good day friends. I have window 7 ultimate as my OS, and DX 11 is installed. Now, I want to install DX 8 or 9 but finding it difficult to do it. It refused to install. How can I do it?
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Otekpo Emmanuel wrote: It refused to install.
Meaning what?
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I learnt from an article I read that dx11 can't be used with vb in ease way. So, the available tutorials are limited to dx 5, 6, 7, 8 and 9. And my system has dx11 installed. So, I wanted to un-install dx11 and replace it with dx 8 or 9 but is not successful because dx 1r is higher than 8 and 9. How can I do the replacement?
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You need to uninstall DX11 and make sure that all associated registry keys are removed. You may need to check with Microsoft for more information on this.
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Otekpo Emmanuel wrote: I learnt from an article I read that dx11 can't be used with vb in ease way
Do you have any problems now? If not you should not care about something you have read somewhere.
You can try to install the DX9 runtime from http://www.microsoft.com/en-us/download/details.aspx?id=8109[^] or the SDK from http://www.microsoft.com/en-us/download/details.aspx?id=6812[^]. This should be possible because only missing parts will be installed and DX11 contains DX9. In fact the DX version that will be used depends on the capabilities of your graphics card. If your graphics card does not support DX10/11, DX9 will be used.
The runtime is used by most games and may be already installed if you have installed some games on your system. The SDK is only required if you want to use DX for your own programs (it includes the runtime).
From the above runtime download link:
Quote: The DirectX runtime cannot be uninstalled
So you should try to use your version first. If you really need a development system with an older DX version, you must setup one using an old Windows version.
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I am following a request to write C++ code for a label that contains several text elements in one single line, varying by font, size, color.... Ok, that can be done easily in GDI+ by measuring each element's width and then execute a DrawString for each of the text elements starting at its calculated position.
So far, I failed miserably.  
The horizontal text positions did not appear to be correct. I reverted now to very simple text measuring tests which confused me even more.
Test 1: Use of MeasureString
With the same font, the width of the string "MM" does not match the double with of the string "M". This cannot be explained with eventual rounding problems.
Test2: Use of MeasureCharacterRanges
Used the same font as for the first test. The width of "MM" is now exactly double of the width of "M". But: The width of the "M" ist lightyears away from the measurement result in the first test.
Here's the code I have used for the two tests:
void ApplWindow_TextDrawTest(HDC hDC)
{
Gdiplus::Graphics *G = new Gdiplus::Graphics(hDC);
G->SetTextRenderingHint(TextRenderingHint::TextRenderingHintClearTypeGridFit);
Gdiplus::StringFormat MyFormat;
MyFormat.SetAlignment(Gdiplus::StringAlignment::StringAlignmentNear);
MyFormat.SetFormatFlags(Gdiplus::StringFormatFlags::StringFormatFlagsNoWrap);
Gdiplus::Font TextFont(L"Calibri", 36, Gdiplus::FontStyle::FontStyleBold, Gdiplus::Unit::UnitPoint);
const wchar_t *Text1M = L"M";
Gdiplus::PointF TextOrigin1M(0, 0);
Gdiplus::RectF TextBounds1M;
const wchar_t *Text2M = L"MM";
Gdiplus::PointF TextOrigin2M(0, 50);
Gdiplus::RectF TextBounds2M;
G->MeasureString(Text1M, (INT)wcslen(Text1M), &TextFont, TextOrigin1M, &MyFormat, &TextBounds1M);
G->MeasureString(Text2M, (INT)wcslen(Text2M), &TextFont, TextOrigin2M, &MyFormat, &TextBounds2M);
Gdiplus::Status RCode;
Gdiplus::RectF LayoutRect(0, 0, 1000, 100);
Gdiplus::Region RegionsList[3];
Gdiplus::CharacterRange CRanges[3];
CRanges[0].First = 0; CRanges[0].Length = 1;
CRanges[1].First = 1; CRanges[1].Length = 1;
CRanges[2].First = 0; CRanges[2].Length = 2;
MyFormat.SetMeasurableCharacterRanges(3, CRanges);
G->MeasureCharacterRanges(Text2M, (INT)wcslen(Text2M), &TextFont, LayoutRect, &MyFormat, 3, RegionsList);
RCode = RegionsList[0].GetBounds(&TextBounds1M, G); RCode = RegionsList[1].GetBounds(&TextBounds1M, G); RCode = RegionsList[2].GetBounds(&TextBounds2M, G);
delete G;
}
Drawing of text with GDI+ gives me very nice results, that's why GDI+ is my first choice here. Does anybody have an idea how I can measure my texts correctly?
Thanks in advance.
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Update
I have added one more test which is using standard GDI, and I have changed the GDI+ font to units of pixels. Unfortunately, this third test shows results which do not match the previous results at all.
Does anybody have an idea why I get so different results?
Since I had not only added a third test but also changed the code of the first tests I am appending the full example here; the results I found have been added as comments:
void ApplWindow_TextDrawTest(HDC hDC)
{
Gdiplus::Graphics *G = new Gdiplus::Graphics(hDC);
G->SetTextRenderingHint(TextRenderingHint::TextRenderingHintClearTypeGridFit);
Gdiplus::StringFormat MyFormat;
MyFormat.SetAlignment(Gdiplus::StringAlignment::StringAlignmentNear);
MyFormat.SetFormatFlags(Gdiplus::StringFormatFlags::StringFormatFlagsNoWrap);
Gdiplus::Font TextFont(L"Calibri", 36, Gdiplus::FontStyle::FontStyleBold, Gdiplus::Unit::UnitPixel);
const wchar_t *Text1M = L"M";
Gdiplus::PointF TextOrigin1M(0, 0);
Gdiplus::RectF TextBounds1M;
const wchar_t *Text2M = L"MM";
Gdiplus::PointF TextOrigin2M(0, 50);
Gdiplus::RectF TextBounds2M;
G->MeasureString(Text1M, (INT)wcslen(Text1M), &TextFont, TextOrigin1M, &MyFormat, &TextBounds1M);
G->MeasureString(Text2M, (INT)wcslen(Text2M), &TextFont, TextOrigin2M, &MyFormat, &TextBounds2M);
Gdiplus::Status RCode;
Gdiplus::RectF LayoutRect(0, 0, 1000, 100);
Gdiplus::Region RegionsList[3];
Gdiplus::CharacterRange CRanges[3];
CRanges[0].First = 0; CRanges[0].Length = 1;
CRanges[1].First = 1; CRanges[1].Length = 1;
CRanges[2].First = 0; CRanges[2].Length = 2;
MyFormat.SetMeasurableCharacterRanges(3, CRanges);
G->MeasureCharacterRanges(Text2M, (INT)wcslen(Text2M), &TextFont, LayoutRect, &MyFormat, 3, RegionsList);
RCode = RegionsList[0].GetBounds(&TextBounds1M, G); RCode = RegionsList[1].GetBounds(&TextBounds1M, G); RCode = RegionsList[2].GetBounds(&TextBounds2M, G);
int MapModeResult = SetMapMode(hDC, MM_TEXT); HFONT TextFont3 = CreateFont(36, 0, 0, 0, FW_BOLD, false, false, false, ANSI_CHARSET, OUT_TT_ONLY_PRECIS, CLIP_DEFAULT_PRECIS, CLEARTYPE_QUALITY, VARIABLE_PITCH | FF_DONTCARE, L"Calibri");
HGDIOBJ PrevFont = SelectObject(hDC, TextFont3);
ABCFLOAT ABCCharData;
BOOL RFlg = GetCharABCWidthsFloat(hDC, (UINT)'M', (UINT)'M', &ABCCharData);
delete G;
}
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You should try -36 as font size in your test#3, this matches the font size chosen in the other tests.
Try better
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I think I found the answer to my question:
GDI and GDI+ do both not resolve by fractions of pixels. That is mainly why my measurement result and the rendered output do not match in all situations.
I have now received an advice from a friend to take a closer look into the features of DirectWrite. Indeed, this engine appears to be the solution for my demands.
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Hello ,
I am looking for an image editor control to integrate with my asp.net website project.I have tried Telerik "RadImageEditor" but it does not fulfill my needs like.
1-Control Canvas size.
2-Save image with Provided DPI
3-After Saving can edit the Saved image (like in photoshop where objects are seperate and can be edited any time after) if this is not possible then it should have selection option so that i can select any part of image and can edit it.
can u pls suggest me some controls that can itegrate with asp.net website project.
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I can suggest one thing - STOP POSTING IN MULTIPLE FORUMS !!!
pick the best forum that you think fits, and post there, ONCE
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I once heard that one of the advantages of PNG (over jpg eg.) is that when used on a webpage the image comes through in "blocks" making the site more responsive, while jpg had to be loaded in "one go".
Did I dream this or is this really so?
(I could only find things like transparancy, better for logo's etc... where jpg is better for real photos)
thanks.
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I thought it was the other way round. You can use progressive jpg where the image starts blocky and is rendered in increasing detail as the rest arrives.
PNG does have a rep for being better for 'geometric' stuff as opposed to photos.
hth
Cheers,
Peter
Software rusts. Simon Stephenson, ca 1994. So does this signature. me, 2012
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That's not quite right. You can have an interlaced JPG just as easily as you can have a progressive PNG. Where PNG has the advantage is if you save it as progressive. Progressive PNGs use a two dimensional interlace, which results in it doing 7 passes, instead of 4 passes - which means that you see something within 1/64 of the time you would see the whole item.
It's worth being aware that no matter which option you choose, you would end up increasing the size of the none progressive/interlaced image.
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not quite true.
progressive JPG (an uncommon but perfectly legal variation) allows for JPGs to be transferred in a series of images, each with higher resolution. the final image gets sharper as you go.
interlaced PNG allows you to transfer pixels out of the standard order - they are transferred in a fixed pattern that's basically an ever-finer grid. the receiver would just the duplicate pixels it has received until all have been transferred.
any speedup depends entirely on the reader being smart enough to display the images progressively.
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Hi all,
4 points are defined as follows:
float[,] ctrlpoints = new float [4,3] {{ -4.0f, -4.0f, 0.0f }, { -2.0f, 4.0f, 0.0f }, { 2.0f, -4.0f, 0.0f }, { 4.0f, 4.0f, 0.0f }};
When the 4 points are called in following method:
private void openGLControl_OpenGLDraw(object sender, RenderEventArgs e)
{
OpenGL gl = openGLControl.OpenGL;
gl.Clear(OpenGL.GL_COLOR_BUFFER_BIT | OpenGL.GL_DEPTH_BUFFER_BIT);
int i;
gl.Color(1.0f, 1.0f, 1.0f);
gl.Begin(OpenGL.GL_LINE_STRIP);
for (i = 0; i <= 30; i++)
{
gl.EvalCoord1((float)i / 30.0);
}
gl.End();
gl.PointSize(5.0f);
gl.Color(1.0f, 1.0f, 0.0f);
gl.Begin(OpenGL.GL_POINTS);
for (i = 0; i < 4; i++)
{
gl.Vertex(&ctrlpoints[i][0]);
}
gl.End();
gl.Flush();
}
The &ctrlpoints[i][0] in gl.Vertex(&ctrlpoints[i][0]) was displayed to be an error.
How to fix the problem? Thanks!
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Which language are you using? Most of your syntax looks like C#, but &ctrlpoints[i][0] looks like C++ (or possibly C# in an unsafe context).
If it's C#, what's the signature of the Vertex method in the Object Browser?
"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer
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pvpeng wrote: was displayed to be an error.
What error; please do not expect people to guess what messages you are seeing. I cannot find a description for either a Vertex function, or class constructor; is this something you have created yourself?
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I am working in C++. I am trying to draw a perpendicular hash mark from the start of a sloped line. My code below draws a perpendicular line but when the slope of the original line changes the hash mark appears to change length. When the line is close to horizontal the hash mark looks longest and shortest when the line is close to vertical. I believe the problem is the fixed value for HashLength. Can you show a better way to calculate the end of the perpendicular line(px2,py2) so my hash mark always looks the same size.
Orig_Line_Slope = (y1-y2)/(x1-x2);
Recipical_Slope = ((1.0 / Orig_Line_Slope)*-1);
HashLength = 10.0;
px2 = (x1+HashLength);
py2 = (y1+(Orig_Line_Slope*HashLength));
MoveToEx(hdc, x1, y1, NULL);
LineTo(hdc, px2, py2 );
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//Denote change in x =dx
//Denote change in y =dy
float dx=0.0;
float dy=0.0;
//Then dx^2 + dy^2 = HashLength ^2 ..eq 1
//We can express dy in terms of dy because
// dy/dx= Recipical_Slope
// simplifying..
// dy=Recipical_Slope*dx
//Replacing dy in eq 1, we have
//dx^2 + (Recipical_Slope *dx)^2= HashLength^2
//simplifying..
dx=sqrt(HashLength^2/(1+Recipical_Slope^2));
dy=Recipical_Slope * dx;
px2=x1+dx;
py2=y1+dy;
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To Yang Kok Wah
I tested your solution and it works very well.
Thank You
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