Visual Basic

double degrees = (180 / Math.PI) * radians;

ReadOut.Text = Convert.ToDouble(ReadOut.Text) * (180/Math.PI);

Convert.ToDouble(ReadOut.Text) * (180 / System.Math.PI)

My Readout.Text takes a value, then it finds Math.Sin(Convert.ToDouble(ReadOut.Text)) and gets the radian value, say 0.989 for sin(8) then if degeree is selected then it performs Math.Sin(Convert.ToDouble(ReadOut.Text)) * (180 / Math.PI) which is giving 56.6 for 0.989 * (180 / 3.1415) instead of giving 0.13917


If radians RadioButton is Checked

ReadOut.Text = System.Math.Sin(Convert.ToDouble(ReadOut.Text))

If degrees RadioButton is Checked

ReadOut.Text = System.Math.Sin(Convert.ToDouble(ReadOut.Text)) * (180 / System.Math.PI)

If Gradians RadioButton is Checked

ReadOut.Text = System.Math.Sin(Convert.ToDouble(ReadOut.Text)) * (200 / System.Math.PI )

They are entering simply a number.for eg., 8 is entered and if degree radio button is checked then it does the below code 

ReadOut.Text = System.Math.Sin(Convert.ToDouble(ReadOut.Text)) * (180 / System.Math.PI)


first it finds the Math.Sin(Convert.ToDouble(ReadOut.Text)) and gets the Sin value for 8 in radians and then it multiplies with (180 / Math.PI) to get the degrees and the new value is converted to string and displayed in the same TextBox. The whole process is done in a single statement

bool doesContain = yourString.Contains(searchString);

Private Sub btn_plusminus_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btn_plusminus.Click

        ReadOut.Text = ReadOut.Text * (-1)

    End Sub