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C# 3.5? list1.Intersect(list2)[^] (it's an extension method in System.Linq)
If not, it's trivial to produce a naive implementation which will be fine for small lists:
IList<T> Intersection<T>(ICollection<T> one, ICollection<T> two){
IList<T> r = new List<T>();
foreach(T t in one)
if(two.Contains(t)) r.Add(t);
return r;
}
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You've been around long enough to know and understand the forum guidelines. DON'T REPOST. You asked this same question four hours ago in the C# forum, it has nothing to do with ASP.NET. If you didn't receive an answer, wait. Don't repost.
I know the language. I've read a book. - _Madmatt
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I think he should delete the other one, not this one, though. C# forum is the correct place for it, the other one is misplaced (and I didn't see it there since I don't read the ASP.NET forum  ).
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Consider using HashSet instead.
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hiiii
iam working on c# windows application
i always use grid just for dir select only
i have issue where i need to add/edit/delete from gridview & dir combobox & Datetimepicker on my cells when i click on it and after leave it dir the selected value in grid cell
i need any help
thanks
md_refay
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hiii
iam working on windows # Application
i need to upload files to server & download it like asp.net
but i don't know how
i need your help
md_refay
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hello Dave help me......
u know about my problem
project not run on vista with amd processor
exception occured on form's InitializeComponent() method.
and run on vista with intel processor....
after installig visual studio it work fine on vista with amd processor.
if u require any other info then let me know.......
thank u
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Please don't post messages addressed to random members like this. Add it to the original thread you started here[^].
The best things in life are not things.
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I would be willing to be that you need to update your .net install.
".45 ACP - because shooting twice is just silly" - JSOP, 2010
-----
You can never have too much ammo - unless you're swimming, or on fire. - JSOP, 2010
-----
"Why don't you tie a kerosene-soaked rag around your ankles so the ants won't climb up and eat your candy ass." - Dale Earnhardt, 1997
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I've looked all over the internet for a formula to calculate the start angle and end angle of an arc. It's very awkward since the angles go in a clockwise motion. The parameters I have are, (X1, Y1), (X2, Y2), ArcCenter, Radius. I'm pretty sure the calculation uses Atan2 as I have tried to figure it out myself.
Thanks
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Start angle = atan2(y1-yc, x1-xc)
End angle = atan2(y2-yc, x2-xc)
... with (xc,yc) being the centre point.
If that isn't right, try switching the parameters or putting minus signs in. That will give you an arc but I'm not sure where it starts from.
Specifying the radius is not necessary if you specify the three points explicitly.
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hello guys... I am trying to get my first crystal report printed but seems to be having a problem I am unable to trace. I added a report to my (Windows Form) project, then added the dataset to it and finally added the following code. This does not show any error but does not show data either. Here is what I tried
private void Form1_Load(object sender, EventArgs e)
{
CrystalReportViewer crv = new CrystalReportViewer();
string ConnString = "Data Source=srv032k3; Initial Catalog= MuzeDB; User ID=muze; Password=saeedasd";
string query = "SELECT * FROM students";
try
{
SqlConnection conn = new SqlConnection(ConnString);
SqlDataAdapter da = new SqlDataAdapter(query, ConnString);
DataSet ds1 = new DataSet();
da.Fill(ds1, "students");
rpt.Load("D:\\Projects\\CrystalReportsApp\\Report\\StudentsReport.rpt");
rpt.SetDataSource(ds1);
crystalReportViewer1.ReportSource = rpt;
}
catch (Exception ex)
{
MessageBox.Show("Something went wrong: " + ex.Message, "Error", MessageBoxButtons.OK, MessageBoxIcon.Warning);
}
}
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I think your problem is here
SqlConnection conn = new SqlConnection(ConnString);
SqlDataAdapter da = new SqlDataAdapter(query, ConnString);
I think it should be
SqlConnection conn = new SqlConnection(ConnString);
conn.open;
SqlDataAdapter da = new SqlDataAdapter(query, conn);
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A mistake that should not have been made. But still the problem is not resolved.
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overloaded Name wrote: but does not show data either.
That is rather indefinite.
I am guessing that you mean that it doesn't show anything at all.
The reason I think that is that I googled for examples.
And one of the shows the use of the 'Visible' property which is a property of the parent of that class. The description of that suggests that it must be true for display to occur.
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Hey everybody.
I have a very small trouble...
List view double click event is getting invoked if I am doing double click on its scroll bar.
How to avoid this...
Thanks in advance..
--
CHEERS
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what are the features of row docking. is it something like data rows on top and stay on their fixed positions. If so how we can use it.
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Is this a feature that the user has asked for? If so, why not ask them what they mean by this? It could mean 2 or 3 things, so it's best to find out out what your users think as it's them you should be satisfying.
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Yes, Hanlon is right, you have to ask them "what they mean by this? It's best to find out out what your users think as it's them you should be satisfying."
In the mean time if you want to know what row docking means. I'll give you an overview about it. Row docking is accessible via Row.Dock property and we can specify multiple docked rows. If our data grid already has docked rows, the next docked row will be placed after the previously docked row and before the first non-docked row. Docked rows can also be filtered or grouped as any other data rows.
To get in depth go here about row docking
Hope it will help you.
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Hello everyone,
I am working on a project where I have to automate the process of entering data through a website. I decided to use the WebBrowser control in .NET for this task.
The problem I am having is that when I try to click on certain buttons, nothing happens. After lookign at the HTML code, I saw a pattern. I can click on buttons where the input type is submit, but I have trouble with the buttons where input type is button and they only have an onclick attribute with javascript code.
I have also tried to use the InvokeScript() method, but that also does not work.
The only think I can think of is that JavaScript is disabled for the WebBrowser control.
Can anyone give me any ideas on how I might be able to resolve this issue?
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The WebBrowser Control uses the same code Internet Explorer does, and also its current settings. So if someone fiddles with IE, your WebBrowser will suddenly behave differently, and you might not like that. I am not aware of an actual solution to this, other than looking for another Control, which probably will cost you.
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I always found that the webbrowser control only allows a subset of javascript. Don't have proof for that though and I always found another way of getting things done. A normal onclick should fire though, are you sure there is no error (mistyped a capital or something?
V.
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